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Trying to use INDEX function in VBA Code, compile error
The following formula works like a charm as a formula in sheet1.
stringvar = = Application.WorksheetFunction.Index(sheet1!C1:HE58 6,MATCH('sheet2'!A1,sheet1!C1:C1000,0),MATCH('shee t2'!K9,sheet1!C1:FC1,0)) Try to use it in my macro and compile error states: "Expected: line separator or )" and highlights the first colon at ":HE586," Are Index and Match valid forumulas to use in VBA? I know the syntax is straight from excel built-in functions. Isn't that what Application.WorksheetFunction demands? Thanks |
Trying to use INDEX function in VBA Code, compile error
Finny wrote: The following formula works like a charm as a formula in sheet1. stringvar = = Application.WorksheetFunction.Index(sheet1!C1:HE58 6,MATCH('sheet2'!A1,sheet1!C1:C1000,0),MATCH('shee t2'!K9,sheet1!C1:FC1,0)) Try to use it in my macro and compile error states: "Expected: line separator or )" and highlights the first colon at ":HE586," Are Index and Match valid forumulas to use in VBA? I know the syntax is straight from excel built-in functions. Isn't that what Application.WorksheetFunction demands? Thanks Not sure that i fully understand your question but i can tell you that Application.WorksheetFunction doesn't include all of the functions available to formulas (because there is a VBA function that will already do it) have you looked into .address? Hope this helps AR |
Trying to use INDEX function in VBA Code, compile error
I would expect this to work:
Sub hhh() Dim res As Variant Dim stringVar As String res = Application.Index(Range("sheet1!C1:HE586"), _ Application.Match(Range("sheet2!A1"), _ Range("sheet1!C1:C1000"), 0), Application.Match( _ Range("sheet2!K9"), Range("sheet1!C1:FC1"), 0)) If Not IsError(res) Then stringVar = res MsgBox stringVar Else MsgBox "Not found" End If End Sub Using application.match allows you to test the result with IsError - otherwise, using worksheetfunction causes a trappable error and this must be handled. Also not that the arguments must be passed as valid VBA ranges where you are using ranges. -- Regards, Tom Ogilvy "Finny" wrote: The following formula works like a charm as a formula in sheet1. stringvar = = Application.WorksheetFunction.Index(sheet1!C1:HE58 6,MATCH('sheet2'!A1,sheet1!C1:C1000,0),MATCH('shee t2'!K9,sheet1!C1:FC1,0)) Try to use it in my macro and compile error states: "Expected: line separator or )" and highlights the first colon at ":HE586," Are Index and Match valid forumulas to use in VBA? I know the syntax is straight from excel built-in functions. Isn't that what Application.WorksheetFunction demands? Thanks |
Trying to use INDEX function in VBA Code, compile error
That worked like a charm Tom.
My trouble is now that I've got working code and wan to implement, I substituted the names of the actual sheets where the code will be run. It gives me a runtime 1004. Application.Match(Range("Item Detail!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("Item Detail!K9"), Range("forecast!C1:FC1"), 0)) Is it b/c I have a space in the name of sheet1: "Item Detail"? I can't change it there are too many dependents on the name. Thanks Tom Ogilvy wrote: I would expect this to work: Sub hhh() Dim res As Variant Dim stringVar As String res = Application.Index(Range("sheet1!C1:HE586"), _ Application.Match(Range("sheet2!A1"), _ Range("sheet1!C1:C1000"), 0), Application.Match( _ Range("sheet2!K9"), Range("sheet1!C1:FC1"), 0)) If Not IsError(res) Then stringVar = res MsgBox stringVar Else MsgBox "Not found" End If End Sub Using application.match allows you to test the result with IsError - otherwise, using worksheetfunction causes a trappable error and this must be handled. Also not that the arguments must be passed as valid VBA ranges where you are using ranges. -- Regards, Tom Ogilvy "Finny" wrote: The following formula works like a charm as a formula in sheet1. stringvar = = Application.WorksheetFunction.Index(sheet1!C1:HE58 6,MATCH('sheet2'!A1,sheet1!C1:C1000,0),MATCH('shee t2'!K9,sheet1!C1:FC1,0)) Try to use it in my macro and compile error states: "Expected: line separator or )" and highlights the first colon at ":HE586," Are Index and Match valid forumulas to use in VBA? I know the syntax is straight from excel built-in functions. Isn't that what Application.WorksheetFunction demands? Thanks |
Trying to use INDEX function in VBA Code, compile error
^ :)
Finny wrote: That worked like a charm Tom. My trouble is now that I've got working code and wan to implement, I substituted the names of the actual sheets where the code will be run. It gives me a runtime 1004. Application.Match(Range("Item Detail!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("Item Detail!K9"), Range("forecast!C1:FC1"), 0)) Is it b/c I have a space in the name of sheet1: "Item Detail"? I can't change it there are too many dependents on the name. Thanks Tom Ogilvy wrote: I would expect this to work: Sub hhh() Dim res As Variant Dim stringVar As String res = Application.Index(Range("sheet1!C1:HE586"), _ Application.Match(Range("sheet2!A1"), _ Range("sheet1!C1:C1000"), 0), Application.Match( _ Range("sheet2!K9"), Range("sheet1!C1:FC1"), 0)) If Not IsError(res) Then stringVar = res MsgBox stringVar Else MsgBox "Not found" End If End Sub Using application.match allows you to test the result with IsError - otherwise, using worksheetfunction causes a trappable error and this must be handled. Also not that the arguments must be passed as valid VBA ranges where you are using ranges. -- Regards, Tom Ogilvy "Finny" wrote: The following formula works like a charm as a formula in sheet1. stringvar = = Application.WorksheetFunction.Index(sheet1!C1:HE58 6,MATCH('sheet2'!A1,sheet1!C1:C1000,0),MATCH('shee t2'!K9,sheet1!C1:FC1,0)) Try to use it in my macro and compile error states: "Expected: line separator or )" and highlights the first colon at ":HE586," Are Index and Match valid forumulas to use in VBA? I know the syntax is straight from excel built-in functions. Isn't that what Application.WorksheetFunction demands? Thanks |
Trying to use INDEX function in VBA Code, compile error
put single quotes around the names with a space like this:
Application.Match(Range("'Item Detail'!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("'Item Detail'!K9"), Range("forecast!C1:FC1"), 0)) -- Regards, Tom Ogilvy "Finny" wrote: That worked like a charm Tom. My trouble is now that I've got working code and wan to implement, I substituted the names of the actual sheets where the code will be run. It gives me a runtime 1004. Application.Match(Range("Item Detail!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("Item Detail!K9"), Range("forecast!C1:FC1"), 0)) Is it b/c I have a space in the name of sheet1: "Item Detail"? I can't change it there are too many dependents on the name. Thanks Tom Ogilvy wrote: I would expect this to work: Sub hhh() Dim res As Variant Dim stringVar As String res = Application.Index(Range("sheet1!C1:HE586"), _ Application.Match(Range("sheet2!A1"), _ Range("sheet1!C1:C1000"), 0), Application.Match( _ Range("sheet2!K9"), Range("sheet1!C1:FC1"), 0)) If Not IsError(res) Then stringVar = res MsgBox stringVar Else MsgBox "Not found" End If End Sub Using application.match allows you to test the result with IsError - otherwise, using worksheetfunction causes a trappable error and this must be handled. Also not that the arguments must be passed as valid VBA ranges where you are using ranges. -- Regards, Tom Ogilvy "Finny" wrote: The following formula works like a charm as a formula in sheet1. stringvar = = Application.WorksheetFunction.Index(sheet1!C1:HE58 6,MATCH('sheet2'!A1,sheet1!C1:C1000,0),MATCH('shee t2'!K9,sheet1!C1:FC1,0)) Try to use it in my macro and compile error states: "Expected: line separator or )" and highlights the first colon at ":HE586," Are Index and Match valid forumulas to use in VBA? I know the syntax is straight from excel built-in functions. Isn't that what Application.WorksheetFunction demands? Thanks |
Trying to use INDEX function in VBA Code, compile error
I had tried that and still get the 1004
res = Application.Index(Range("forecast!C1:HE586"), _ Application.Match(Range("'Item detail'!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("'Item detail'!K9"), Range("forecast!C1:FC1"), 0)) I also tried using the first code you gave me, created string vars as sheet1 and sheet2 and loaded the strings with the sheet names. No go. Could this have something to do with the workbook? Thanks for your help Tom Ogilvy wrote: put single quotes around the names with a space like this: Application.Match(Range("'Item Detail'!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("'Item Detail'!K9"), Range("forecast!C1:FC1"), 0)) -- Regards, Tom Ogilvy "Finny" wrote: That worked like a charm Tom. My trouble is now that I've got working code and wan to implement, I substituted the names of the actual sheets where the code will be run. It gives me a runtime 1004. Application.Match(Range("Item Detail!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("Item Detail!K9"), Range("forecast!C1:FC1"), 0)) Is it b/c I have a space in the name of sheet1: "Item Detail"? I can't change it there are too many dependents on the name. Thanks Tom Ogilvy wrote: I would expect this to work: Sub hhh() Dim res As Variant Dim stringVar As String res = Application.Index(Range("sheet1!C1:HE586"), _ Application.Match(Range("sheet2!A1"), _ Range("sheet1!C1:C1000"), 0), Application.Match( _ Range("sheet2!K9"), Range("sheet1!C1:FC1"), 0)) If Not IsError(res) Then stringVar = res MsgBox stringVar Else MsgBox "Not found" End If End Sub Using application.match allows you to test the result with IsError - otherwise, using worksheetfunction causes a trappable error and this must be handled. Also not that the arguments must be passed as valid VBA ranges where you are using ranges. -- Regards, Tom Ogilvy "Finny" wrote: The following formula works like a charm as a formula in sheet1. stringvar = = Application.WorksheetFunction.Index(sheet1!C1:HE58 6,MATCH('sheet2'!A1,sheet1!C1:C1000,0),MATCH('shee t2'!K9,sheet1!C1:FC1,0)) Try to use it in my macro and compile error states: "Expected: line separator or )" and highlights the first colon at ":HE586," Are Index and Match valid forumulas to use in VBA? I know the syntax is straight from excel built-in functions. Isn't that what Application.WorksheetFunction demands? Thanks |
Trying to use INDEX function in VBA Code, compile error
I'd use...
dim myRng as range dim ResRow as variant dim ResCol as variant dim res as variant set myRng = worksheets("forecast").range("C1:HE586") resrow = application.match(worksheets("item detail").range("a1").value, _ myrng.columns(1),0) rescol = application.match(worksheets("item detail").range("k9").value, _ myrng.rows(1),0) if isnumeric(resrow) _ and isnumeric(rescol) then res = myrng(resrow,rescol) else msgbox "missing at least one match! res = "whateveryouwanthere" end if (untested, uncompiled--watch for typos) Finny wrote: I had tried that and still get the 1004 res = Application.Index(Range("forecast!C1:HE586"), _ Application.Match(Range("'Item detail'!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("'Item detail'!K9"), Range("forecast!C1:FC1"), 0)) I also tried using the first code you gave me, created string vars as sheet1 and sheet2 and loaded the strings with the sheet names. No go. Could this have something to do with the workbook? Thanks for your help Tom Ogilvy wrote: put single quotes around the names with a space like this: Application.Match(Range("'Item Detail'!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("'Item Detail'!K9"), Range("forecast!C1:FC1"), 0)) -- Regards, Tom Ogilvy "Finny" wrote: That worked like a charm Tom. My trouble is now that I've got working code and wan to implement, I substituted the names of the actual sheets where the code will be run. It gives me a runtime 1004. Application.Match(Range("Item Detail!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("Item Detail!K9"), Range("forecast!C1:FC1"), 0)) Is it b/c I have a space in the name of sheet1: "Item Detail"? I can't change it there are too many dependents on the name. Thanks Tom Ogilvy wrote: I would expect this to work: Sub hhh() Dim res As Variant Dim stringVar As String res = Application.Index(Range("sheet1!C1:HE586"), _ Application.Match(Range("sheet2!A1"), _ Range("sheet1!C1:C1000"), 0), Application.Match( _ Range("sheet2!K9"), Range("sheet1!C1:FC1"), 0)) If Not IsError(res) Then stringVar = res MsgBox stringVar Else MsgBox "Not found" End If End Sub Using application.match allows you to test the result with IsError - otherwise, using worksheetfunction causes a trappable error and this must be handled. Also not that the arguments must be passed as valid VBA ranges where you are using ranges. -- Regards, Tom Ogilvy "Finny" wrote: The following formula works like a charm as a formula in sheet1. stringvar = = Application.WorksheetFunction.Index(sheet1!C1:HE58 6,MATCH('sheet2'!A1,sheet1!C1:C1000,0),MATCH('shee t2'!K9,sheet1!C1:FC1,0)) Try to use it in my macro and compile error states: "Expected: line separator or )" and highlights the first colon at ":HE586," Are Index and Match valid forumulas to use in VBA? I know the syntax is straight from excel built-in functions. Isn't that what Application.WorksheetFunction demands? Thanks -- Dave Peterson |
Trying to use INDEX function in VBA Code, compile error
Well, I wouldn't have suggested it if I hadn't tested it.
break it into parts and see where the problem is use something like this: sub Testit() Dim rng1 as Range, rng2 as Range, rng3 as Range Dim rng4 as Range, rng5 as Range, res1, res2, res set rng1 = Range("forecast!C1:HE586") set rng2 = Range("'Item detail'!A1") set rng3 = Range("forecast!C1:C1000") set rng4 = Range("'Item detail'!K9") set rng5 = Range("forecast!C1:FC1") res1 = Application.Match(rng2,rng3, 0) res2 = Application.Match(rng4, rng5, 0) if iserror(res1) then msgbox "Problems with finding " & rng2.value elseif iserror(res2) then msgbox "Problems with finding " & rng4.Value else res = Application.Index(rng1,res1,res2) end if if iserror(res) then msgbox res1 & " or " & res2 & " is out of bounds" else msgbox "Results are " & res End if end sub -- Regards, Tom Ogilvy "Finny" wrote: I had tried that and still get the 1004 res = Application.Index(Range("forecast!C1:HE586"), _ Application.Match(Range("'Item detail'!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("'Item detail'!K9"), Range("forecast!C1:FC1"), 0)) I also tried using the first code you gave me, created string vars as sheet1 and sheet2 and loaded the strings with the sheet names. No go. Could this have something to do with the workbook? Thanks for your help Tom Ogilvy wrote: put single quotes around the names with a space like this: Application.Match(Range("'Item Detail'!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("'Item Detail'!K9"), Range("forecast!C1:FC1"), 0)) -- Regards, Tom Ogilvy "Finny" wrote: That worked like a charm Tom. My trouble is now that I've got working code and wan to implement, I substituted the names of the actual sheets where the code will be run. It gives me a runtime 1004. Application.Match(Range("Item Detail!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("Item Detail!K9"), Range("forecast!C1:FC1"), 0)) Is it b/c I have a space in the name of sheet1: "Item Detail"? I can't change it there are too many dependents on the name. Thanks Tom Ogilvy wrote: I would expect this to work: Sub hhh() Dim res As Variant Dim stringVar As String res = Application.Index(Range("sheet1!C1:HE586"), _ Application.Match(Range("sheet2!A1"), _ Range("sheet1!C1:C1000"), 0), Application.Match( _ Range("sheet2!K9"), Range("sheet1!C1:FC1"), 0)) If Not IsError(res) Then stringVar = res MsgBox stringVar Else MsgBox "Not found" End If End Sub Using application.match allows you to test the result with IsError - otherwise, using worksheetfunction causes a trappable error and this must be handled. Also not that the arguments must be passed as valid VBA ranges where you are using ranges. -- Regards, Tom Ogilvy "Finny" wrote: The following formula works like a charm as a formula in sheet1. stringvar = = Application.WorksheetFunction.Index(sheet1!C1:HE58 6,MATCH('sheet2'!A1,sheet1!C1:C1000,0),MATCH('shee t2'!K9,sheet1!C1:FC1,0)) Try to use it in my macro and compile error states: "Expected: line separator or )" and highlights the first colon at ":HE586," Are Index and Match valid forumulas to use in VBA? I know the syntax is straight from excel built-in functions. Isn't that what Application.WorksheetFunction demands? Thanks |
Trying to use INDEX function in VBA Code, compile error
It dies on first Set statement - 1004.
Wierd Tom Ogilvy wrote: Well, I wouldn't have suggested it if I hadn't tested it. break it into parts and see where the problem is use something like this: sub Testit() Dim rng1 as Range, rng2 as Range, rng3 as Range Dim rng4 as Range, rng5 as Range, res1, res2, res set rng1 = Range("forecast!C1:HE586") set rng2 = Range("'Item detail'!A1") set rng3 = Range("forecast!C1:C1000") set rng4 = Range("'Item detail'!K9") set rng5 = Range("forecast!C1:FC1") res1 = Application.Match(rng2,rng3, 0) res2 = Application.Match(rng4, rng5, 0) if iserror(res1) then msgbox "Problems with finding " & rng2.value elseif iserror(res2) then msgbox "Problems with finding " & rng4.Value else res = Application.Index(rng1,res1,res2) end if if iserror(res) then msgbox res1 & " or " & res2 & " is out of bounds" else msgbox "Results are " & res End if end sub -- Regards, Tom Ogilvy "Finny" wrote: I had tried that and still get the 1004 res = Application.Index(Range("forecast!C1:HE586"), _ Application.Match(Range("'Item detail'!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("'Item detail'!K9"), Range("forecast!C1:FC1"), 0)) I also tried using the first code you gave me, created string vars as sheet1 and sheet2 and loaded the strings with the sheet names. No go. Could this have something to do with the workbook? Thanks for your help Tom Ogilvy wrote: put single quotes around the names with a space like this: Application.Match(Range("'Item Detail'!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("'Item Detail'!K9"), Range("forecast!C1:FC1"), 0)) -- Regards, Tom Ogilvy "Finny" wrote: That worked like a charm Tom. My trouble is now that I've got working code and wan to implement, I substituted the names of the actual sheets where the code will be run. It gives me a runtime 1004. Application.Match(Range("Item Detail!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("Item Detail!K9"), Range("forecast!C1:FC1"), 0)) Is it b/c I have a space in the name of sheet1: "Item Detail"? I can't change it there are too many dependents on the name. Thanks Tom Ogilvy wrote: I would expect this to work: Sub hhh() Dim res As Variant Dim stringVar As String res = Application.Index(Range("sheet1!C1:HE586"), _ Application.Match(Range("sheet2!A1"), _ Range("sheet1!C1:C1000"), 0), Application.Match( _ Range("sheet2!K9"), Range("sheet1!C1:FC1"), 0)) If Not IsError(res) Then stringVar = res MsgBox stringVar Else MsgBox "Not found" End If End Sub Using application.match allows you to test the result with IsError - otherwise, using worksheetfunction causes a trappable error and this must be handled. Also not that the arguments must be passed as valid VBA ranges where you are using ranges. -- Regards, Tom Ogilvy "Finny" wrote: The following formula works like a charm as a formula in sheet1. stringvar = = Application.WorksheetFunction.Index(sheet1!C1:HE58 6,MATCH('sheet2'!A1,sheet1!C1:C1000,0),MATCH('shee t2'!K9,sheet1!C1:FC1,0)) Try to use it in my macro and compile error states: "Expected: line separator or )" and highlights the first colon at ":HE586," Are Index and Match valid forumulas to use in VBA? I know the syntax is straight from excel built-in functions. Isn't that what Application.WorksheetFunction demands? Thanks |
Trying to use INDEX function in VBA Code, compile error
Also thanks Dave. I can't figure out what was wrong with the previous
code but yours worked! Thank you. It recieves the value of that cell. But what I'm trying to do in all this is take to two strings from "Item detail", look on of the them up on the y and one on the x axis in a table in "forecast" and activate (go to) that intersecting cell. I can't get the cell location form the returned value b/c it's not unique. I tried declaring res as a range and that didn't work phew I'm new to using excel functions in VBA. Thanks for all the help thus far. Finny wrote: It dies on first Set statement - 1004. Wierd Tom Ogilvy wrote: Well, I wouldn't have suggested it if I hadn't tested it. break it into parts and see where the problem is use something like this: sub Testit() Dim rng1 as Range, rng2 as Range, rng3 as Range Dim rng4 as Range, rng5 as Range, res1, res2, res set rng1 = Range("forecast!C1:HE586") set rng2 = Range("'Item detail'!A1") set rng3 = Range("forecast!C1:C1000") set rng4 = Range("'Item detail'!K9") set rng5 = Range("forecast!C1:FC1") res1 = Application.Match(rng2,rng3, 0) res2 = Application.Match(rng4, rng5, 0) if iserror(res1) then msgbox "Problems with finding " & rng2.value elseif iserror(res2) then msgbox "Problems with finding " & rng4.Value else res = Application.Index(rng1,res1,res2) end if if iserror(res) then msgbox res1 & " or " & res2 & " is out of bounds" else msgbox "Results are " & res End if end sub -- Regards, Tom Ogilvy "Finny" wrote: I had tried that and still get the 1004 res = Application.Index(Range("forecast!C1:HE586"), _ Application.Match(Range("'Item detail'!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("'Item detail'!K9"), Range("forecast!C1:FC1"), 0)) I also tried using the first code you gave me, created string vars as sheet1 and sheet2 and loaded the strings with the sheet names. No go. Could this have something to do with the workbook? Thanks for your help Tom Ogilvy wrote: put single quotes around the names with a space like this: Application.Match(Range("'Item Detail'!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("'Item Detail'!K9"), Range("forecast!C1:FC1"), 0)) -- Regards, Tom Ogilvy "Finny" wrote: That worked like a charm Tom. My trouble is now that I've got working code and wan to implement, I substituted the names of the actual sheets where the code will be run. It gives me a runtime 1004. Application.Match(Range("Item Detail!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("Item Detail!K9"), Range("forecast!C1:FC1"), 0)) Is it b/c I have a space in the name of sheet1: "Item Detail"? I can't change it there are too many dependents on the name. Thanks Tom Ogilvy wrote: I would expect this to work: Sub hhh() Dim res As Variant Dim stringVar As String res = Application.Index(Range("sheet1!C1:HE586"), _ Application.Match(Range("sheet2!A1"), _ Range("sheet1!C1:C1000"), 0), Application.Match( _ Range("sheet2!K9"), Range("sheet1!C1:FC1"), 0)) If Not IsError(res) Then stringVar = res MsgBox stringVar Else MsgBox "Not found" End If End Sub Using application.match allows you to test the result with IsError - otherwise, using worksheetfunction causes a trappable error and this must be handled. Also not that the arguments must be passed as valid VBA ranges where you are using ranges. -- Regards, Tom Ogilvy "Finny" wrote: The following formula works like a charm as a formula in sheet1. stringvar = = Application.WorksheetFunction.Index(sheet1!C1:HE58 6,MATCH('sheet2'!A1,sheet1!C1:C1000,0),MATCH('shee t2'!K9,sheet1!C1:FC1,0)) Try to use it in my macro and compile error states: "Expected: line separator or )" and highlights the first colon at ":HE586," Are Index and Match valid forumulas to use in VBA? I know the syntax is straight from excel built-in functions. Isn't that what Application.WorksheetFunction demands? Thanks |
Trying to use INDEX function in VBA Code, compile error
I should have been more explicit (this is just for completeness):
Dim Res as variant if isnumeric(resrow) _ and isnumeric(rescol) then res = myrng(resrow,rescol).value else msgbox "missing at least one match! res = "whateveryouwanthere" end if But you'd want: Dim res as Range if isnumeric(resrow) _ and isnumeric(rescol) then set res = myrng(resrow,rescol) application.goto res 'or just application.goto myrng(resrow,rescol) else msgbox "missing at least one match! res = "whateveryouwanthere" end if Finny wrote: Also thanks Dave. I can't figure out what was wrong with the previous code but yours worked! Thank you. It recieves the value of that cell. But what I'm trying to do in all this is take to two strings from "Item detail", look on of the them up on the y and one on the x axis in a table in "forecast" and activate (go to) that intersecting cell. I can't get the cell location form the returned value b/c it's not unique. I tried declaring res as a range and that didn't work phew I'm new to using excel functions in VBA. Thanks for all the help thus far. Finny wrote: It dies on first Set statement - 1004. Wierd Tom Ogilvy wrote: Well, I wouldn't have suggested it if I hadn't tested it. break it into parts and see where the problem is use something like this: sub Testit() Dim rng1 as Range, rng2 as Range, rng3 as Range Dim rng4 as Range, rng5 as Range, res1, res2, res set rng1 = Range("forecast!C1:HE586") set rng2 = Range("'Item detail'!A1") set rng3 = Range("forecast!C1:C1000") set rng4 = Range("'Item detail'!K9") set rng5 = Range("forecast!C1:FC1") res1 = Application.Match(rng2,rng3, 0) res2 = Application.Match(rng4, rng5, 0) if iserror(res1) then msgbox "Problems with finding " & rng2.value elseif iserror(res2) then msgbox "Problems with finding " & rng4.Value else res = Application.Index(rng1,res1,res2) end if if iserror(res) then msgbox res1 & " or " & res2 & " is out of bounds" else msgbox "Results are " & res End if end sub -- Regards, Tom Ogilvy "Finny" wrote: I had tried that and still get the 1004 res = Application.Index(Range("forecast!C1:HE586"), _ Application.Match(Range("'Item detail'!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("'Item detail'!K9"), Range("forecast!C1:FC1"), 0)) I also tried using the first code you gave me, created string vars as sheet1 and sheet2 and loaded the strings with the sheet names. No go. Could this have something to do with the workbook? Thanks for your help Tom Ogilvy wrote: put single quotes around the names with a space like this: Application.Match(Range("'Item Detail'!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("'Item Detail'!K9"), Range("forecast!C1:FC1"), 0)) -- Regards, Tom Ogilvy "Finny" wrote: That worked like a charm Tom. My trouble is now that I've got working code and wan to implement, I substituted the names of the actual sheets where the code will be run. It gives me a runtime 1004. Application.Match(Range("Item Detail!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("Item Detail!K9"), Range("forecast!C1:FC1"), 0)) Is it b/c I have a space in the name of sheet1: "Item Detail"? I can't change it there are too many dependents on the name. Thanks Tom Ogilvy wrote: I would expect this to work: Sub hhh() Dim res As Variant Dim stringVar As String res = Application.Index(Range("sheet1!C1:HE586"), _ Application.Match(Range("sheet2!A1"), _ Range("sheet1!C1:C1000"), 0), Application.Match( _ Range("sheet2!K9"), Range("sheet1!C1:FC1"), 0)) If Not IsError(res) Then stringVar = res MsgBox stringVar Else MsgBox "Not found" End If End Sub Using application.match allows you to test the result with IsError - otherwise, using worksheetfunction causes a trappable error and this must be handled. Also not that the arguments must be passed as valid VBA ranges where you are using ranges. -- Regards, Tom Ogilvy "Finny" wrote: The following formula works like a charm as a formula in sheet1. stringvar = = Application.WorksheetFunction.Index(sheet1!C1:HE58 6,MATCH('sheet2'!A1,sheet1!C1:C1000,0),MATCH('shee t2'!K9,sheet1!C1:FC1,0)) Try to use it in my macro and compile error states: "Expected: line separator or )" and highlights the first colon at ":HE586," Are Index and Match valid forumulas to use in VBA? I know the syntax is straight from excel built-in functions. Isn't that what Application.WorksheetFunction demands? Thanks -- Dave Peterson |
Trying to use INDEX function in VBA Code, compile error
Is your code in a general module or behind a worksheet?
If your code is behind a worksheet, then that unqualified range will refer to the sheet that owns the code--and if Forecast isn't that sheet, you'll see that error. You can either change it to look more "normal" (ahem): set rng1 = worksheets("forecast").range("C1:He586") or you can qualify that range: Set rng1 = Application.Range("forecast!C1:HE586") ========== It's usually nicer to post more of the function--sometimes it helps clarify the question. Finny wrote: It dies on first Set statement - 1004. Wierd Tom Ogilvy wrote: Well, I wouldn't have suggested it if I hadn't tested it. break it into parts and see where the problem is use something like this: sub Testit() Dim rng1 as Range, rng2 as Range, rng3 as Range Dim rng4 as Range, rng5 as Range, res1, res2, res set rng1 = Range("forecast!C1:HE586") set rng2 = Range("'Item detail'!A1") set rng3 = Range("forecast!C1:C1000") set rng4 = Range("'Item detail'!K9") set rng5 = Range("forecast!C1:FC1") res1 = Application.Match(rng2,rng3, 0) res2 = Application.Match(rng4, rng5, 0) if iserror(res1) then msgbox "Problems with finding " & rng2.value elseif iserror(res2) then msgbox "Problems with finding " & rng4.Value else res = Application.Index(rng1,res1,res2) end if if iserror(res) then msgbox res1 & " or " & res2 & " is out of bounds" else msgbox "Results are " & res End if end sub -- Regards, Tom Ogilvy "Finny" wrote: I had tried that and still get the 1004 res = Application.Index(Range("forecast!C1:HE586"), _ Application.Match(Range("'Item detail'!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("'Item detail'!K9"), Range("forecast!C1:FC1"), 0)) I also tried using the first code you gave me, created string vars as sheet1 and sheet2 and loaded the strings with the sheet names. No go. Could this have something to do with the workbook? Thanks for your help Tom Ogilvy wrote: put single quotes around the names with a space like this: Application.Match(Range("'Item Detail'!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("'Item Detail'!K9"), Range("forecast!C1:FC1"), 0)) -- Regards, Tom Ogilvy "Finny" wrote: That worked like a charm Tom. My trouble is now that I've got working code and wan to implement, I substituted the names of the actual sheets where the code will be run. It gives me a runtime 1004. Application.Match(Range("Item Detail!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("Item Detail!K9"), Range("forecast!C1:FC1"), 0)) Is it b/c I have a space in the name of sheet1: "Item Detail"? I can't change it there are too many dependents on the name. Thanks Tom Ogilvy wrote: I would expect this to work: Sub hhh() Dim res As Variant Dim stringVar As String res = Application.Index(Range("sheet1!C1:HE586"), _ Application.Match(Range("sheet2!A1"), _ Range("sheet1!C1:C1000"), 0), Application.Match( _ Range("sheet2!K9"), Range("sheet1!C1:FC1"), 0)) If Not IsError(res) Then stringVar = res MsgBox stringVar Else MsgBox "Not found" End If End Sub Using application.match allows you to test the result with IsError - otherwise, using worksheetfunction causes a trappable error and this must be handled. Also not that the arguments must be passed as valid VBA ranges where you are using ranges. -- Regards, Tom Ogilvy "Finny" wrote: The following formula works like a charm as a formula in sheet1. stringvar = = Application.WorksheetFunction.Index(sheet1!C1:HE58 6,MATCH('sheet2'!A1,sheet1!C1:C1000,0),MATCH('shee t2'!K9,sheet1!C1:FC1,0)) Try to use it in my macro and compile error states: "Expected: line separator or )" and highlights the first colon at ":HE586," Are Index and Match valid forumulas to use in VBA? I know the syntax is straight from excel built-in functions. Isn't that what Application.WorksheetFunction demands? Thanks -- Dave Peterson |
Trying to use INDEX function in VBA Code, compile error
You shouldn't have the code in a sheet module.
It should be in a general module. -- Regards, Tom Ogilvy "Finny" wrote in message oups.com... It dies on first Set statement - 1004. Wierd Tom Ogilvy wrote: Well, I wouldn't have suggested it if I hadn't tested it. break it into parts and see where the problem is use something like this: sub Testit() Dim rng1 as Range, rng2 as Range, rng3 as Range Dim rng4 as Range, rng5 as Range, res1, res2, res set rng1 = Range("forecast!C1:HE586") set rng2 = Range("'Item detail'!A1") set rng3 = Range("forecast!C1:C1000") set rng4 = Range("'Item detail'!K9") set rng5 = Range("forecast!C1:FC1") res1 = Application.Match(rng2,rng3, 0) res2 = Application.Match(rng4, rng5, 0) if iserror(res1) then msgbox "Problems with finding " & rng2.value elseif iserror(res2) then msgbox "Problems with finding " & rng4.Value else res = Application.Index(rng1,res1,res2) end if if iserror(res) then msgbox res1 & " or " & res2 & " is out of bounds" else msgbox "Results are " & res End if end sub -- Regards, Tom Ogilvy "Finny" wrote: I had tried that and still get the 1004 res = Application.Index(Range("forecast!C1:HE586"), _ Application.Match(Range("'Item detail'!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("'Item detail'!K9"), Range("forecast!C1:FC1"), 0)) I also tried using the first code you gave me, created string vars as sheet1 and sheet2 and loaded the strings with the sheet names. No go. Could this have something to do with the workbook? Thanks for your help Tom Ogilvy wrote: put single quotes around the names with a space like this: Application.Match(Range("'Item Detail'!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("'Item Detail'!K9"), Range("forecast!C1:FC1"), 0)) -- Regards, Tom Ogilvy "Finny" wrote: That worked like a charm Tom. My trouble is now that I've got working code and wan to implement, I substituted the names of the actual sheets where the code will be run. It gives me a runtime 1004. Application.Match(Range("Item Detail!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("Item Detail!K9"), Range("forecast!C1:FC1"), 0)) Is it b/c I have a space in the name of sheet1: "Item Detail"? I can't change it there are too many dependents on the name. Thanks Tom Ogilvy wrote: I would expect this to work: Sub hhh() Dim res As Variant Dim stringVar As String res = Application.Index(Range("sheet1!C1:HE586"), _ Application.Match(Range("sheet2!A1"), _ Range("sheet1!C1:C1000"), 0), Application.Match( _ Range("sheet2!K9"), Range("sheet1!C1:FC1"), 0)) If Not IsError(res) Then stringVar = res MsgBox stringVar Else MsgBox "Not found" End If End Sub Using application.match allows you to test the result with IsError - otherwise, using worksheetfunction causes a trappable error and this must be handled. Also not that the arguments must be passed as valid VBA ranges where you are using ranges. -- Regards, Tom Ogilvy "Finny" wrote: The following formula works like a charm as a formula in sheet1. stringvar = = Application.WorksheetFunction.Index(sheet1!C1:HE58 6,MATCH('sheet2'!A1,sheet1!C1:C1000,0),MATCH('shee t2'!K9,sheet1!C1:FC1,0)) Try to use it in my macro and compile error states: "Expected: line separator or )" and highlights the first colon at ":HE586," Are Index and Match valid forumulas to use in VBA? I know the syntax is straight from excel built-in functions. Isn't that what Application.WorksheetFunction demands? Thanks |
Trying to use INDEX function in VBA Code, compile error
Hello all,
How would I be able to modify the Match() portion of the code so that it looks for multiple criteria in different ranges. For example, in excel, I am able to use "=Index(RangeOfValues,Match(Criteria1&Criteria2&Cr iteria3,Range1&Range2&Range3,0))." How would this translate into VBA? I understand the idea of using the index function in vba but only the match function with 1 set of criteria and no more. If you could help, I would highly appreciate it. -- Isaac Tom Ogilvy wrote: You shouldn't have the code in a sheet module. It should be in a general module. -- Regards, Tom Ogilvy "Finny" wrote in message oups.com... It dies on first Set statement - 1004. Wierd Tom Ogilvy wrote: Well, I wouldn't have suggested it if I hadn't tested it. break it into parts and see where the problem is use something like this: sub Testit() Dim rng1 as Range, rng2 as Range, rng3 as Range Dim rng4 as Range, rng5 as Range, res1, res2, res set rng1 = Range("forecast!C1:HE586") set rng2 = Range("'Item detail'!A1") set rng3 = Range("forecast!C1:C1000") set rng4 = Range("'Item detail'!K9") set rng5 = Range("forecast!C1:FC1") res1 = Application.Match(rng2,rng3, 0) res2 = Application.Match(rng4, rng5, 0) if iserror(res1) then msgbox "Problems with finding " & rng2.value elseif iserror(res2) then msgbox "Problems with finding " & rng4.Value else res = Application.Index(rng1,res1,res2) end if if iserror(res) then msgbox res1 & " or " & res2 & " is out of bounds" else msgbox "Results are " & res End if end sub -- Regards, Tom Ogilvy "Finny" wrote: I had tried that and still get the 1004 res = Application.Index(Range("forecast!C1:HE586"), _ Application.Match(Range("'Item detail'!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("'Item detail'!K9"), Range("forecast!C1:FC1"), 0)) I also tried using the first code you gave me, created string vars as sheet1 and sheet2 and loaded the strings with the sheet names. No go. Could this have something to do with the workbook? Thanks for your help Tom Ogilvy wrote: put single quotes around the names with a space like this: Application.Match(Range("'Item Detail'!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("'Item Detail'!K9"), Range("forecast!C1:FC1"), 0)) -- Regards, Tom Ogilvy "Finny" wrote: That worked like a charm Tom. My trouble is now that I've got working code and wan to implement, I substituted the names of the actual sheets where the code will be run. It gives me a runtime 1004. Application.Match(Range("Item Detail!A1"), _ Range("forecast!C1:C1000"), 0), Application.Match( _ Range("Item Detail!K9"), Range("forecast!C1:FC1"), 0)) Is it b/c I have a space in the name of sheet1: "Item Detail"? I can't change it there are too many dependents on the name. Thanks Tom Ogilvy wrote: I would expect this to work: Sub hhh() Dim res As Variant Dim stringVar As String res = Application.Index(Range("sheet1!C1:HE586"), _ Application.Match(Range("sheet2!A1"), _ Range("sheet1!C1:C1000"), 0), Application.Match( _ Range("sheet2!K9"), Range("sheet1!C1:FC1"), 0)) If Not IsError(res) Then stringVar = res MsgBox stringVar Else MsgBox "Not found" End If End Sub Using application.match allows you to test the result with IsError - otherwise, using worksheetfunction causes a trappable error and this must be handled. Also not that the arguments must be passed as valid VBA ranges where you are using ranges. -- Regards, Tom Ogilvy "Finny" wrote: The following formula works like a charm as a formula in sheet1. stringvar = = Application.WorksheetFunction.Index(sheet1!C1:HE58 6,MATCH('sheet2'!A1,sheet1!C1:C1000,0),MATCH('shee t2'!K9,sheet1!C1:FC1,0)) Try to use it in my macro and compile error states: "Expected: line separator or )" and highlights the first colon at ":HE586," Are Index and Match valid forumulas to use in VBA? I know the syntax is straight from excel built-in functions. Isn't that what Application.WorksheetFunction demands? Thanks |
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