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Offset from a variable column to a fixed column
I'm trying to put together a macro that will take a value from one cell in a
row, and then move it to another cell in the same row. The originating cell is going to vary, but the receiving cell is going to be in a constant column in the same row. I know about using offset to move over a specified number of cells, but I'm not certain as to how many cells I'm going to want to move over to get to the same column in each row that I work with. Is there a way to use offset to move into a constant column? |
Offset from a variable column to a fixed column
set rCell=Cells(Activecell.row,"B")
will set rCell to same row as active cell, column B HTH -- AP "Kurt Barr" a écrit dans le message de news: ... I'm trying to put together a macro that will take a value from one cell in a row, and then move it to another cell in the same row. The originating cell is going to vary, but the receiving cell is going to be in a constant column in the same row. I know about using offset to move over a specified number of cells, but I'm not certain as to how many cells I'm going to want to move over to get to the same column in each row that I work with. Is there a way to use offset to move into a constant column? |
Offset from a variable column to a fixed column
Perfect!! That was just what I needed. Thanks!!
"Ardus Petus" wrote: set rCell=Cells(Activecell.row,"B") will set rCell to same row as active cell, column B HTH -- AP "Kurt Barr" a écrit dans le message de news: ... I'm trying to put together a macro that will take a value from one cell in a row, and then move it to another cell in the same row. The originating cell is going to vary, but the receiving cell is going to be in a constant column in the same row. I know about using offset to move over a specified number of cells, but I'm not certain as to how many cells I'm going to want to move over to get to the same column in each row that I work with. Is there a way to use offset to move into a constant column? |
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