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Don't understand - Arrays 101 (Help)
The below macro is bombing 5 rows from (the present) bottom.
I'm sure it is elementary, but obviously not for me. Can someone point out my problem? Thanks in Advance.. Jim Sub Foo() Dim searchc As String Dim DestWb As Workbook Dim MyList As Range Dim Arr() As Long Dim i As Integer Range("B2").Select searchc = ActiveCell.Offset(0, -1).Value Set DestWb = Workbooks("Ex1.xls") Workbooks("Ex2.xls").Activate Lrow = Cells(Rows.Count, "b").End(xlUp).Row Set MyList = Range("B2:B" & Lrow) Range("B2").Select i = 0 For Each c In MyList If c.Offset(0, -1) = searchc Then i = i + 1 Arr(i) = c.Value '' R/T Error 9, Subscript Out of range c.Offset(1, 0).Select End If Next c End Sub |
Don't understand - Arrays 101 (Help)
For Each c In MyList
If c.Offset(0, -1) = searchc Then i = i + 1 redim preserve arr(1 to i) Arr(i) = c.Value '' R/T Error 9, Subscript Out of range 'not sure why you're selecting this c.Offset(1, 0).Select End If Next c JimMay wrote: The below macro is bombing 5 rows from (the present) bottom. I'm sure it is elementary, but obviously not for me. Can someone point out my problem? Thanks in Advance.. Jim Sub Foo() Dim searchc As String Dim DestWb As Workbook Dim MyList As Range Dim Arr() As Long Dim i As Integer Range("B2").Select searchc = ActiveCell.Offset(0, -1).Value Set DestWb = Workbooks("Ex1.xls") Workbooks("Ex2.xls").Activate Lrow = Cells(Rows.Count, "b").End(xlUp).Row Set MyList = Range("B2:B" & Lrow) Range("B2").Select i = 0 For Each c In MyList If c.Offset(0, -1) = searchc Then i = i + 1 Arr(i) = c.Value '' R/T Error 9, Subscript Out of range c.Offset(1, 0).Select End If Next c End Sub -- Dave Peterson |
Don't understand - Arrays 101 (Help)
Thanks Dave,
Added the line redim preserve arr(1 to i) and removed the line c.Offset(1, 0).Select Now it works great after I add: Workbooks("EX1.xls").Activate Range("B2").Select Cells(2, 2).Value = Arr(1) Cells(3, 2).Value = Arr(2) Cells(4, 2).Value = Arr(3) Thanks so much, Jim May "Dave Peterson" wrote in message : For Each c In MyList If c.Offset(0, -1) = searchc Then i = i + 1 redim preserve arr(1 to i) Arr(i) = c.Value '' R/T Error 9, Subscript Out of range 'not sure why you're selecting this c.Offset(1, 0).Select End If Next c JimMay wrote: The below macro is bombing 5 rows from (the present) bottom. I'm sure it is elementary, but obviously not for me. Can someone point out my problem? Thanks in Advance.. Jim Sub Foo() Dim searchc As String Dim DestWb As Workbook Dim MyList As Range Dim Arr() As Long Dim i As Integer Range("B2").Select searchc = ActiveCell.Offset(0, -1).Value Set DestWb = Workbooks("Ex1.xls") Workbooks("Ex2.xls").Activate Lrow = Cells(Rows.Count, "b").End(xlUp).Row Set MyList = Range("B2:B" & Lrow) Range("B2").Select i = 0 For Each c In MyList If c.Offset(0, -1) = searchc Then i = i + 1 Arr(i) = c.Value '' R/T Error 9, Subscript Out of range c.Offset(1, 0).Select End If Next c End Sub -- Dave Peterson |
Don't understand - Arrays 101 (Help)
You don't need that Range("B2").select line either.
And unless you know when to stop (which is the last row to be populated), you might get that same kind of error (subscript out of range). Heck, you may even miss some of the values in the array. You could loop through the array: 'since we know that the lbound of arr() is 1 [arr(1 to ###)] for i = lbound(arr) to ubound(arr) cells(1+i,2).value = arr(i) next i Or you could plop the whole array into that range: Range("b2").Resize(UBound(arr) - LBound(arr) + 1, 1).Value _ = Application.Transpose(arr) (Application.transpose() is limited to about 5000 (5417???) elements in xl2k and before, IIRC). JimMay wrote: Thanks Dave, Added the line redim preserve arr(1 to i) and removed the line c.Offset(1, 0).Select Now it works great after I add: Workbooks("EX1.xls").Activate Range("B2").Select Cells(2, 2).Value = Arr(1) Cells(3, 2).Value = Arr(2) Cells(4, 2).Value = Arr(3) Thanks so much, Jim May "Dave Peterson" wrote in message : For Each c In MyList If c.Offset(0, -1) = searchc Then i = i + 1 redim preserve arr(1 to i) Arr(i) = c.Value '' R/T Error 9, Subscript Out of range 'not sure why you're selecting this c.Offset(1, 0).Select End If Next c JimMay wrote: The below macro is bombing 5 rows from (the present) bottom. I'm sure it is elementary, but obviously not for me. Can someone point out my problem? Thanks in Advance.. Jim Sub Foo() Dim searchc As String Dim DestWb As Workbook Dim MyList As Range Dim Arr() As Long Dim i As Integer Range("B2").Select searchc = ActiveCell.Offset(0, -1).Value Set DestWb = Workbooks("Ex1.xls") Workbooks("Ex2.xls").Activate Lrow = Cells(Rows.Count, "b").End(xlUp).Row Set MyList = Range("B2:B" & Lrow) Range("B2").Select i = 0 For Each c In MyList If c.Offset(0, -1) = searchc Then i = i + 1 Arr(i) = c.Value '' R/T Error 9, Subscript Out of range c.Offset(1, 0).Select End If Next c End Sub -- Dave Peterson -- Dave Peterson |
Don't understand - Arrays 101 (Help)
Dave;
Thanks for the additional advice; I will incorporate this: for i = lbound(arr) to ubound(arr) cells(1+i,2).value = arr(i) next i into my code - when I get home from work to my Home PC where I have the WB. Graciously appreciate your help, Jim May "Dave Peterson" wrote: You don't need that Range("B2").select line either. And unless you know when to stop (which is the last row to be populated), you might get that same kind of error (subscript out of range). Heck, you may even miss some of the values in the array. You could loop through the array: 'since we know that the lbound of arr() is 1 [arr(1 to ###)] for i = lbound(arr) to ubound(arr) cells(1+i,2).value = arr(i) next i Or you could plop the whole array into that range: Range("b2").Resize(UBound(arr) - LBound(arr) + 1, 1).Value _ = Application.Transpose(arr) (Application.transpose() is limited to about 5000 (5417???) elements in xl2k and before, IIRC). JimMay wrote: Thanks Dave, Added the line redim preserve arr(1 to i) and removed the line c.Offset(1, 0).Select Now it works great after I add: Workbooks("EX1.xls").Activate Range("B2").Select Cells(2, 2).Value = Arr(1) Cells(3, 2).Value = Arr(2) Cells(4, 2).Value = Arr(3) Thanks so much, Jim May "Dave Peterson" wrote in message : For Each c In MyList If c.Offset(0, -1) = searchc Then i = i + 1 redim preserve arr(1 to i) Arr(i) = c.Value '' R/T Error 9, Subscript Out of range 'not sure why you're selecting this c.Offset(1, 0).Select End If Next c JimMay wrote: The below macro is bombing 5 rows from (the present) bottom. I'm sure it is elementary, but obviously not for me. Can someone point out my problem? Thanks in Advance.. Jim Sub Foo() Dim searchc As String Dim DestWb As Workbook Dim MyList As Range Dim Arr() As Long Dim i As Integer Range("B2").Select searchc = ActiveCell.Offset(0, -1).Value Set DestWb = Workbooks("Ex1.xls") Workbooks("Ex2.xls").Activate Lrow = Cells(Rows.Count, "b").End(xlUp).Row Set MyList = Range("B2:B" & Lrow) Range("B2").Select i = 0 For Each c In MyList If c.Offset(0, -1) = searchc Then i = i + 1 Arr(i) = c.Value '' R/T Error 9, Subscript Out of range c.Offset(1, 0).Select End If Next c End Sub -- Dave Peterson -- Dave Peterson |
Don't understand - Arrays 101 (Help)
I like the other one that plops everything at once.
Jim May wrote: Dave; Thanks for the additional advice; I will incorporate this: for i = lbound(arr) to ubound(arr) cells(1+i,2).value = arr(i) next i into my code - when I get home from work to my Home PC where I have the WB. Graciously appreciate your help, Jim May "Dave Peterson" wrote: You don't need that Range("B2").select line either. And unless you know when to stop (which is the last row to be populated), you might get that same kind of error (subscript out of range). Heck, you may even miss some of the values in the array. You could loop through the array: 'since we know that the lbound of arr() is 1 [arr(1 to ###)] for i = lbound(arr) to ubound(arr) cells(1+i,2).value = arr(i) next i Or you could plop the whole array into that range: Range("b2").Resize(UBound(arr) - LBound(arr) + 1, 1).Value _ = Application.Transpose(arr) (Application.transpose() is limited to about 5000 (5417???) elements in xl2k and before, IIRC). JimMay wrote: Thanks Dave, Added the line redim preserve arr(1 to i) and removed the line c.Offset(1, 0).Select Now it works great after I add: Workbooks("EX1.xls").Activate Range("B2").Select Cells(2, 2).Value = Arr(1) Cells(3, 2).Value = Arr(2) Cells(4, 2).Value = Arr(3) Thanks so much, Jim May "Dave Peterson" wrote in message : For Each c In MyList If c.Offset(0, -1) = searchc Then i = i + 1 redim preserve arr(1 to i) Arr(i) = c.Value '' R/T Error 9, Subscript Out of range 'not sure why you're selecting this c.Offset(1, 0).Select End If Next c JimMay wrote: The below macro is bombing 5 rows from (the present) bottom. I'm sure it is elementary, but obviously not for me. Can someone point out my problem? Thanks in Advance.. Jim Sub Foo() Dim searchc As String Dim DestWb As Workbook Dim MyList As Range Dim Arr() As Long Dim i As Integer Range("B2").Select searchc = ActiveCell.Offset(0, -1).Value Set DestWb = Workbooks("Ex1.xls") Workbooks("Ex2.xls").Activate Lrow = Cells(Rows.Count, "b").End(xlUp).Row Set MyList = Range("B2:B" & Lrow) Range("B2").Select i = 0 For Each c In MyList If c.Offset(0, -1) = searchc Then i = i + 1 Arr(i) = c.Value '' R/T Error 9, Subscript Out of range c.Offset(1, 0).Select End If Next c End Sub -- Dave Peterson -- Dave Peterson -- Dave Peterson |
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