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Hi Jerry,
I usually have somewhere around 375 data points, which goes up by 1 each week, as I am tracking a stock closing, but only on a weekly basis. Yes, it is the 6th degree polynomial that I add to the graph. I tried to figure out the individual data points represented by the graph, using the formula provided by the graph, but the "point" was not very accurate and I am given the understanding that this was due to rounding errors and the precion of Excel, prior to Office 2003. Maybe this has all changed? I had also run across a third party add-on that was claiming to have increased the accuracy, but did not purchase it and have not heard anyone else mention it or vouch for it. But if I could find a way to figure out the individual points represented by the graph, I would be interested in doing that. Thanks for your help. -- David "Jerry W. Lewis" wrote: If by "6th degree", you mean a 6th degree polynomial, then you should be conserned about whether you have sampled a wide enough range of data to be able to reliably estimate the parameters. Even with independent parameters and/or adequate data range, validation of the formula could be interesting. Remember the famous quote of von Neumann "With four parameters I can fit an elephant, and with five I can make him wiggle his trunk." Jerry "David" wrote: I just started reading your thread and have become interested. I was at one time trying to create data points from an anaysis of Stock closiings, that are represented by a regression (6th degree) line. I was not able to use the formula supplied in previous versions of Excel, prior to Ver 2003. But I would be interested in trying this again, since i have the new version. I would like to actually create data points as respesented by the regression line, fi that is possible? Thanks, -- David "Mitch" wrote: I need to run regression analyses (linear & nonlinear) on many data sets. I have observed that the resulting equations generated in a chart trend line and that generated by the linest() function are frequently very different. I have read Tushar Mehta's explanation of the problem, but need advice on which is more accurate. |
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