can somebody help me out? i can't remember the columns command i used or where
i used it, to return the column letter of a column.

it's not a function, it doesn't return the address, or use the left property or
anything like that, i think it was just using the columns property.

hopefully i explained it well enough. it was simple when it came to me, but i
can't remember it for the life of me.

--


Gary

Is this what you saw

On Error Resume Next
sColumn = Split(Columns(Col).Address(, False), ":")(1)
On Error GoTo 0


--
HTH

Bob Phillips

(remove nothere from email address if mailing direct)

"Gary Keramidas" <GKeramidasATmsn.com wrote in message
...
can somebody help me out? i can't remember the columns command i used or
where
i used it, to return the column letter of a column.

it's not a function, it doesn't return the address, or use the left
property or
anything like that, i think it was just using the columns property.

hopefully i explained it well enough. it was simple when it came to me,
but i
can't remember it for the life of me.

--


Gary

nobody has any idea how i did this? i can't blame you, neither do i at the
moment. hopefully it will come back to me.

--


Gary


"Gary Keramidas" <GKeramidasATmsn.com wrote in message
...
can somebody help me out? i can't remember the columns command i used or
where i used it, to return the column letter of a column.

it's not a function, it doesn't return the address, or use the left property
or anything like that, i think it was just using the columns property.

hopefully i explained it well enough. it was simple when it came to me, but i
can't remember it for the life of me.

--


Gary

Gary,
Did you ever remember how to do find the column letter? I'm
trying to do the same thing and can't figure it out either.

I'd like to return the column letter from a cell reference

i.e. for cell(5,y)

It would return L if y = 13
or D if y = 4

etc.

Does anyone know how to do this?

Thanks


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i have not.

--


Gary


"bhofsetz" wrote in
message ...

Gary,
Did you ever remember how to do find the column letter? I'm
trying to do the same thing and can't figure it out either.

I'd like to return the column letter from a cell reference

i.e. for cell(5,y)

It would return L if y = 13
or D if y = 4

etc.

Does anyone know how to do this?

Thanks


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bhofsetz
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bhofsetz's Profile:
http://www.excelforum.com/member.php...o&userid=18807
View this thread: http://www.excelforum.com/showthread...hreadid=530389

If you use

cells(5,y).Address

it will return to you

$L$5 when y = 12

I know this isn't exactly what you are after but by using a mid comman
you can get just the letter out.

mid(cells(5,y),2,1).Address

will return

L when y = 12

this would have to be modified if you know that you will be dealin
with more than 26 columns.

Not the method you were looking for but a possible work around

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