open worksheet
 

Is there a way to open a specific worksheet based on the contents of a cell
in the source worksheet..

Workbooks.Open Filename:="C:\filename.xls#(worksheet name in A1)!A1"

TIA

Ben

open worksheet
 

Here is some code for you to try. You jsut need to get the workbook and sheet
names added in

Sub OpenToSheet()
Dim wbk As Workbook

Workbooks.Open ("C:\ThisBook.xls")
Set wbk = ActiveWorkbook
wbk.Sheets("Sheet1").Select
MsgBox "Here we are"
ThisWorkbook.Activate
MsgBox "And now we are back..."
End Sub
--
HTH...

Jim Thomlinson


"Benjamin" wrote:

Is there a way to open a specific worksheet based on the contents of a cell
in the source worksheet..

Workbooks.Open Filename:="C:\filename.xls#(worksheet name in A1)!A1"

TIA

Ben

open worksheet
 

Thanks. But say I don't want to type in the name of the worksheet, but refer
to it's name which is stored in cell A1.

"Jim Thomlinson" wrote:

Here is some code for you to try. You jsut need to get the workbook and sheet
names added in

Sub OpenToSheet()
Dim wbk As Workbook

Workbooks.Open ("C:\ThisBook.xls")
Set wbk = ActiveWorkbook
wbk.Sheets("Sheet1").Select
MsgBox "Here we are"
ThisWorkbook.Activate
MsgBox "And now we are back..."
End Sub
--
HTH...

Jim Thomlinson


"Benjamin" wrote:

Is there a way to open a specific worksheet based on the contents of a cell
in the source worksheet..

Workbooks.Open Filename:="C:\filename.xls#(worksheet name in A1)!A1"

TIA

Ben

open worksheet
 

option explicit
sub testme01()

dim wkbk as workbook
dim wksName as string

wksname = activesheet.range("a1").value

set wkbk = workbooks.open(filename:=c:\filename.xls")

on error resume next
application.goto wkbk.worksheets(wksname).range("a1"), scroll:=true
if err.number < 0 then
beep
err.clear
end if

end sub



Benjamin wrote:

Is there a way to open a specific worksheet based on the contents of a cell
in the source worksheet..

Workbooks.Open Filename:="C:\filename.xls#(worksheet name in A1)!A1"

TIA

Ben

--

Dave Peterson