scheduling dates
 

dear all
I have a worksheet with a comlum of dates
is there a way to increment the dates using code
for example

existing results
column column (e.g. after adding 6 months)

10/15/05 04/15/06
10/15/05 04/15/06
10/16/05 04/16/06

I know I can acheive this with the formula
=DATE(YEAR(A1),MONTH(A1)+6,DAY(A1))
but is there a simple way to do this with code

--
thanks as always for the help
jer

scheduling dates
 

On Wed, 19 Oct 2005 15:52:08 -0700, jer wrote:

dear all
I have a worksheet with a comlum of dates
is there a way to increment the dates using code
for example

existing results
column column (e.g. after adding 6 months)

10/15/05 04/15/06
10/15/05 04/15/06
10/16/05 04/16/06

I know I can acheive this with the formula
=DATE(YEAR(A1),MONTH(A1)+6,DAY(A1))
but is there a simple way to do this with code

There is a very similar VBA function:

DateSerial(Year(dt1), Month(dt1) + 6, Day(dt1))

Of course, that has the same limitations as does the worksheet function when it
comes to dealing with end of the month issues.

It may be simpler to use the DateAdd function which takes end of the month
issues into account:

DateAdd("m", 6, dt1)




--ron

scheduling dates
 

Thanks Ron
--
thanks as always for the help
jer

"Ron Rosenfeld" wrote:

On Wed, 19 Oct 2005 15:52:08 -0700, jer wrote:

dear all
I have a worksheet with a comlum of dates
is there a way to increment the dates using code
for example

existing results
column column (e.g. after adding 6 months)

10/15/05 04/15/06
10/15/05 04/15/06
10/16/05 04/16/06

I know I can acheive this with the formula
=DATE(YEAR(A1),MONTH(A1)+6,DAY(A1))
but is there a simple way to do this with code

There is a very similar VBA function:

DateSerial(Year(dt1), Month(dt1) + 6, Day(dt1))

Of course, that has the same limitations as does the worksheet function when it
comes to dealing with end of the month issues.

It may be simpler to use the DateAdd function which takes end of the month
issues into account:

DateAdd("m", 6, dt1)




--ron

scheduling dates
 

On Thu, 20 Oct 2005 08:39:04 -0700, jer wrote:

Thanks Ron
--
thanks as always for the help
jer

You're welcome. Glad to help.
--ron