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Watch your code step by step...
Let's say a_number (the cell) = 5 - Dim aAd(1 To 12) As Integer This should create an array with 12 elements, although I would choose for Dim aAd As Variant aAd = Array(12) or Dim aAd(12) As Variant - Dim n As Integer Loop counter, seems correct Now here we go and fill the array... For n = 1 To 12 Step 1 aAd(n) = n * a_number Next n - So far so good, the result is: aAd(1) = 5 aAd(2) = 10 ... aAd(12) = 60 Finally you say - DispArray = aAd and there it goes wrong. You have an array with 12 elements, so now you should specify the element to return DispArray = aAd(a_number) Because you can't return an Array with 12 values into one single cell, DispArray = aAd will return 0. "Syed Zeeshan Haider" schreef in bericht ... Hello Everybody, I have Excel 2003 Pro on WinXP Pro. I have been searching on internet but could not find any useful information about creating custom array functions. Can somebody tell me any links to the reference about creating custom array functions? Well, actually I saw a rather complex code on a site. This code returned array but I couldn't spend next 2 to 3 hours in understanding what was it supposed to calculate. No description was provided. I tried to experiment with my own following code: Public Function DispArray(a_number As Integer) As Variant ' yes, varaibles are not logical Dim aAd(1 To 12) As Integer Dim n As Integer For n = 1 To 12 Step 1 aAd(n) = n * a_number Next n DispArray = aAd End Function It is supposed to display multiplication table's result of a given integer (a_number). But it returns same result in all select cells. Thank you, -- Syed Zeeshan Haider ----------------------------------------------------------------------------------------------------------------------------- Download a free game to play with Internet Explorer from http://szh.20m.com/entertainment/olwg.html |
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