Position of Chr(10)
I have a string with *Chr(10)* in it. I want to know the position of this Chr(10) so I can cut off the string starting from this Chr(10). What function gives this position? Thx -- Zurn ------------------------------------------------------------------------ Zurn's Profile: http://www.excelforum.com/member.php...o&userid=14645 View this thread: http://www.excelforum.com/showthread...hreadid=387930 |
Position of Chr(10)
Function SnipString(rng) x = Mid(rng, Application.Find(Chr(10), rng) + 1, Len(rng)) Loc = x End Function -- davidm ------------------------------------------------------------------------ davidm's Profile: http://www.excelforum.com/member.php...o&userid=20645 View this thread: http://www.excelforum.com/showthread...hreadid=387930 |
Position of Chr(10)
in a worksheetfunction you'd use the search or find function =SEARCH(CHAR(10),a1) in VBA: use the InStr function. dim iPos% ipos = instr("where's the linefeed", vblf) xl2000 and newer also have an InstrRev() function which search from the end of the string to give you the LAST occurance of the substring. note: vblf is a constant used in VB(a) for chr(10) vbcr = chr(13) see VBA help for the full monty. -- keepITcool | www.XLsupport.com | keepITcool chello nl | amsterdam Zurn wrote : I have a string with *Chr(10)* in it. I want to know the position of this Chr(10) so I can cut off the string starting from this Chr(10). What function gives this position? Thx |
Position of Chr(10)
David, i would NOT use the FIND worksheetfunction for this. it's many times slower than instr. WHY then len(s)?? - it's optional for vba's mid function. - it should be len(s) - iPos Sub USEinstrNOTfind() Dim s$, r$, n&, m&, t(1) m = 100000 s = "Find the line" & vbLf & "feed" t(0) = Timer For n = 1 To m r = Mid$(s, Application.Find(vbLf, s) + 1) Next t(0) = Format(Timer - t(0), "0.00") t(1) = Timer For n = 1 To m r = Mid$(s, InStr(1, s, vbLf) + 1) Next t(1) = Format(Timer - t(1), "0.00") MsgBox Join(t, vbLf) End Sub -- keepITcool | www.XLsupport.com | keepITcool chello nl | amsterdam davidm wrote : Function SnipString(rng) x = Mid(rng, Application.Find(Chr(10), rng) + 1, Len(rng)) Loc = x End Function |
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