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Advance if statements?
The message below refers: I am trying to create some kind of artificial
intelligence where I compare data sets, e.g. R13:W13 is a part of a structure, Z13:AE13 is another part. What I need the inferencing machine to do is to say if R13:W13 have values between 1 and 4 and Z13:AE13 have values between 1 and 3, structure is Ok =IF(COUNTIF(R13:W13,"<4",Countif(Z13:AE13,"<3","OK ","Replace"))) I actually want to produce one ling if statement where each scenario has a set output. Please help |
Advance if statements?
Hi Ralph
the structure of an IF(AND()) function is =IF(AND(condition1,condition2,....,condition29),tr ue,false) i think you should be able to achieve what you want using this structure Hope this helps Cheers JulieD "Ralph" wrote in message ... The message below refers: I am trying to create some kind of artificial intelligence where I compare data sets, e.g. R13:W13 is a part of a structure, Z13:AE13 is another part. What I need the inferencing machine to do is to say if R13:W13 have values between 1 and 4 and Z13:AE13 have values between 1 and 3, structure is Ok =IF(COUNTIF(R13:W13,"<4",Countif(Z13:AE13,"<3","OK ","Replace"))) I actually want to produce one ling if statement where each scenario has a set output. Please help |
Advance if statements?
=If(And((countif(R13:W13,"=1")-countif(R13:W13,"4"))=6,(countif(Z13:AE13,"
=1")-countif(Z13:AE13,"3"))=6),"OK","REPLACE") -- Regards, Tom Ogilvy "Ralph" wrote in message ... The message below refers: I am trying to create some kind of artificial intelligence where I compare data sets, e.g. R13:W13 is a part of a structure, Z13:AE13 is another part. What I need the inferencing machine to do is to say if R13:W13 have values between 1 and 4 and Z13:AE13 have values between 1 and 3, structure is Ok =IF(COUNTIF(R13:W13,"<4",Countif(Z13:AE13,"<3","OK ","Replace"))) I actually want to produce one ling if statement where each scenario has a set output. Please help |
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