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Excel 2003 won't run simple code that Excel XP and Excel 2000 will run
Hi All,
I was wondering if anyone had come across this problem. I have two separate applications in which Excel 2003 will not run my code. On one application, it won't recognize a userform when I am in a sub, but if I call the userform in the parent sub that calls the problem sub, it will recognize it. Strange! In the other one, the code is simple: thisworkbook.activate sheets("data entry").activate It chokes on the 2nd line. I even tried: thisworkbook.activate x = activesheet.name and it choked on that too. The error is: Run-time error '32809' Application-defined or object-defined error. Any ideas? |
Excel 2003 won't run simple code that Excel XP and Excel 2000 will run
Hi Moses, I am taking a bit of a stab in the dark, but I have seen some
similar problems if the windows in taskbar option is not turned off. I use the following code upon opening a workbook: If Application.Version = "11.0" Then Application.ShowWindowsInTaskbar = False End If HTH--Lonnie M. |
Excel 2003 won't run simple code that Excel XP and Excel 2000 will run
As for the second issue try something like this:
Dim DataEntry As Worksheet Set DataEntry = Workbook("workbookNameHere.xls").Worksheet("Data Entry") 'OR if data entry is active: 'Set DataEntry = ActiveWorkbook.ActiveSheet DataEntry.Activate HTH--Lonnie M. |
Excel 2003 won't run simple code that Excel XP and Excel 2000 will run
I don't get it. (Oh, I am Moses, by the way). As Lonnie suggested, I
added something like Dim DE as worksheet set DE = sheets("Data Entry") DE.activate and now it works. So, why did it work before in Excel 2000 and Excel 97 but didn't work in Excel 2003? Is there something to learn here? *** Sent via Developersdex http://www.developersdex.com *** Don't just participate in USENET...get rewarded for it! |
Excel 2003 won't run simple code that Excel XP and Excel 2000 will run
I don't get it. Lonnie's solution worked.
Instead of this: sheets("Data Entry").activate I used the following code: dim DE as worksheet set DE = sheets("Data Entry") DE.activate and it worked! Now why is that? Why did the simpler code work in Excel 97 or Excel 2000 but not in Excel 2003? Does anyone know? Is there something to learn here? |
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