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I assume the statements you included below would go into the cells on the spreadsheet? I am actually looking to write code in a module to figure out the column letter. My example is over simplified. I have a large amount of data that will be copied to numerous worksheets every day. However the date (7/6/04) will be in the same column on every worksheet I will be copying to for that day, and it will increment to the next column for the following day.
So if 7/6/04 is in the "D" column, 7/7/04 will be in the "E" column, but the dates will only be for Monday thru Friday. I hope this clarifies my dilemma. "Jeff Standen" wrote: Something like this: range("1:1").Find(#7/6/04#).offset(1,0).Value=6500 range("1:1").Find(#7/6/04#).offset(2,0).Value=format(1000.12, "$###,###.00") You would probably use variables where I have used values. Note the date format - I have assumed you are using the US system. Jeff "Jon Workman" <Jon wrote in message ... I am trying to write a function that will copy data from an import sheet to a particular column on another sheet. The column is determined by a date that is shown on a particular row. For example, I have this data on the import sheet: 7/6/2004, 6500, $1000.12 A B C D E 1 7/1/04 7/2/04 7/5/04 7/6/04 7/7/04 2 ______ 3 ______ Is it possible to go this sheet I set up, determine that 7/6/04 is in column D, and return "D" as the value? I can then copy the 6500 into D2, and $1000.12 in D3. Thank you for any help. This is way outside of my expertise in programming in excel. |
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