Opening a file using VBA
 

Hi,

Im trying to write a piece of code which will open a txt file. the following code works for the first part of what i am trying to do:

Workbooks.OpenText Filename:= "C:\VisionMate Database\Rack_1_20040715-105339_.txt"

The file location can vary and the actual path to the correct file is stored in cell A1 in sheet1 in the workbook. How do i replace the filename in the code above to read the file path that is stored in cell A1.

Anyhelp will be greatly appreciated!

Thank you

Opening a file using VBA
 

Hi
try
....
dim fname
dim fpath
fname = activesheet.range("A1").value
fpath = "C:\VisionMate Database\"
fnane = fname & ".xls"
workbooks.open fpath & fname

-----Original Message-----
Hi,

Im trying to write a piece of code which will open a txt
file. the following code works for the first part of what
i am trying to do:

Workbooks.OpenText Filename:= "C:\VisionMate
Database\Rack_1_20040715-105339_.txt"

The file location can vary and the actual path to the
correct file is stored in cell A1 in sheet1 in the
workbook. How do i replace the filename in the code above
to read the file path that is stored in cell A1.

Anyhelp will be greatly appreciated!

Thank you
.