simple macro
 

Hi Folks

I have the following macro that, for the life of me, I can't seem to change so that it cuts the last 5 characters of a cell instead of the first 5 characters. Any help much appreicated.

Sub MoveAround()

Dim CellVal As String

CellVal = ActiveCell.Text
Range(ActiveCell.Address) = Right(CellVal, Len(CellVal) - 6)
ActiveCell.Offset(0, 1).Select
Range(ActiveCell.Address) = Left(CellVal, 6)
ActiveCell.Offset(1, -1).Select

End Sub

simple macro
 

try this
Sub cut5()
On Error Resume Next
ActiveCell = Left(ActiveCell, (Len(ActiveCell) - 5))
End Sub
--
Don Guillett
SalesAid Software

"Joe" wrote in message
...
Hi Folks

I have the following macro that, for the life of me, I can't seem to
change so that it cuts the last 5 characters of a cell instead of the first
5 characters. Any help much appreicated.

Sub MoveAround()

Dim CellVal As String

CellVal = ActiveCell.Text
Range(ActiveCell.Address) = Right(CellVal, Len(CellVal) - 6)
ActiveCell.Offset(0, 1).Select
Range(ActiveCell.Address) = Left(CellVal, 6)
ActiveCell.Offset(1, -1).Select

End Sub

simple macro
 

Joe

This worked for me

Sub test()

Dim CellText As String

CellText = ActiveCell.Text
ActiveCell.Value = Right(CellText, Len(CellText) - 6)
ActiveCell.Offset(0, 1).Value = Left(CellText, 6)

End Sub

There must be something wrong with the CellVal variable. Put this after the
CellVal assignment

MsgBox CellVal

and see if it's what you expect it to be.

--
Dick Kusleika
MVP - Excel
Excel Blog - Daily Dose of Excel
www.dicks-blog.com

"Joe" wrote in message
...
Hi Folks

I have the following macro that, for the life of me, I can't seem to
change so that it cuts the last 5 characters of a cell instead of the first
5 characters. Any help much appreicated.

Sub MoveAround()

Dim CellVal As String

CellVal = ActiveCell.Text
Range(ActiveCell.Address) = Right(CellVal, Len(CellVal) - 6)
ActiveCell.Offset(0, 1).Select
Range(ActiveCell.Address) = Left(CellVal, 6)
ActiveCell.Offset(1, -1).Select

End Sub