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Simple UDF help
Hi I have the following simple UDF. How can I reference
the column numbers (the column in which they reside on the worksheet) of the arguments "first" and "last" from inside the function? Function CAGR(first As Double, last As Double, n As Integer) CAGR = (last / first) ^ (1 / n) - 1 End Function Thanks. |
Simple UDF help
since you are passing first and last as numbers, you can't. If you intend
to pass them is as range references, then you can redefine them as Ranges Function CAGR(first As Range, last As Range, _ n As Integer) dim firstColumn as Long, lastColumn as Long firstColumn = first.Column lastColumn = Last.Column CAGR = (last.Value / first.Value) ^ (1 / n) - 1 End Function Assumes first and last are single cell references. -- Regards, Tom Ogilvy "Salman" wrote in message ... Hi I have the following simple UDF. How can I reference the column numbers (the column in which they reside on the worksheet) of the arguments "first" and "last" from inside the function? Function CAGR(first As Double, last As Double, n As Integer) CAGR = (last / first) ^ (1 / n) - 1 End Function Thanks. |
Simple UDF help
Salman,
If you want to reference the columns, you need to declare 'first' and 'last' as Ranges. E.g., Function CAGR(first As Range, last As Range, n As Integer) CAGR = (last / first) ^ (1 / n) - 1 Debug.Print first.Column, last.Column End Function -- Cordially, Chip Pearson Microsoft MVP - Excel Pearson Software Consulting, LLC www.cpearson.com "Salman" wrote in message ... Hi I have the following simple UDF. How can I reference the column numbers (the column in which they reside on the worksheet) of the arguments "first" and "last" from inside the function? Function CAGR(first As Double, last As Double, n As Integer) CAGR = (last / first) ^ (1 / n) - 1 End Function Thanks. |
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