hi

can anybody tell why this doesn't work, or better yet show me how t
make it work

Function Dandy(P As Double, rng)
Dim M As Double
M = Application.Average(rng)
Dim S As Double
S = Application.StDev(rng)

Dandy = Application.Norminv(P, M, S)
End Function

What im tryin to do is write a UDF tha replaces this
=Norminv(P, average(range), Stdev(range)

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Message posted from http://www.ExcelForum.com

It seems to work for me in Excel XP. Give an example of what you are
passing and what unacceptable results you are getting.

Jerry

ksnapp < wrote:

hi

can anybody tell why this doesn't work, or better yet show me how to
make it work

Function Dandy(P As Double, rng)
Dim M As Double
M = Application.Average(rng)
Dim S As Double
S = Application.StDev(rng)

Dandy = Application.Norminv(P, M, S)
End Function

What im tryin to do is write a UDF tha replaces this
=Norminv(P, average(range), Stdev(range))

I'm not a stats person, but would taking the StDev of the population
(StDevP) work? I am not sure what you mean by "doesn't work."

Function Dandy(P As Double, rng As Range)
Dim M As Double
Dim S As Double

With WorksheetFunction
M = .Average(rng)
S = .StDevP(rng)
Dandy = .NormInv(P, M, S)
End With
End Function


--
Dana DeLouis
Using Windows XP & Office XP
= = = = = = = = = = = = = = = = =


"ksnapp " wrote in message
...
hi

can anybody tell why this doesn't work, or better yet show me how to
make it work

Function Dandy(P As Double, rng)
Dim M As Double
M = Application.Average(rng)
Dim S As Double
S = Application.StDev(rng)

Dandy = Application.Norminv(P, M, S)
End Function

What im tryin to do is write a UDF tha replaces this
=Norminv(P, average(range), Stdev(range))


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Message posted from http://www.ExcelForum.com/