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Help with code or formula
I have the following problem and don't mind which solution is forthcoming:
Sheet1 contains data about claims made to our department (approx 700 rows). Column A contains the claim reference number (5 digits) - there can be up to 50 rows with the same reference number. Column D is either 'Adult' or 'Veal'. Column F is either 'Yes' or 'No' to say if the animal is satisfactory. What I need is the number of 'Adult' and 'Veal' claims that are satisfactory. A satisfactory claim is defined as one where all animals in a claim are 'Yes' in column F. Thanks in advance. Gareth |
Help with code or formula
try
=sumproduct((rngA=12345)*(rngD={"Adult","Veal"})*( rngF="Yes")) "Gareth" wrote in message ... I have the following problem and don't mind which solution is forthcoming: Sheet1 contains data about claims made to our department (approx 700 rows). Column A contains the claim reference number (5 digits) - there can be up to 50 rows with the same reference number. Column D is either 'Adult' or 'Veal'. Column F is either 'Yes' or 'No' to say if the animal is satisfactory. What I need is the number of 'Adult' and 'Veal' claims that are satisfactory. A satisfactory claim is defined as one where all animals in a claim are 'Yes' in column F. Thanks in advance. Gareth |
Help with code or formula
the problem with this is that I don't know the the claim numbers'
Example: 25 animals with the same ref number, they are all Adult and all are Yes - this would be 1 satisfactory claim. 41 animals with another refernce number (but the same), all Adult but with 2 No's - this shouldn't be counted as a satifacctory claim. I think what I want to do is count the number of animals in a claim, if all are yes then count it as 1. Gareth "Don Guillett" wrote in message ... try =sumproduct((rngA=12345)*(rngD={"Adult","Veal"})*( rngF="Yes")) "Gareth" wrote in message ... I have the following problem and don't mind which solution is forthcoming: Sheet1 contains data about claims made to our department (approx 700 rows). Column A contains the claim reference number (5 digits) - there can be up to 50 rows with the same reference number. Column D is either 'Adult' or 'Veal'. Column F is either 'Yes' or 'No' to say if the animal is satisfactory. What I need is the number of 'Adult' and 'Veal' claims that are satisfactory. A satisfactory claim is defined as one where all animals in a claim are 'Yes' in column F. Thanks in advance. Gareth |
Help with code or formula
You need to use IF, AND Function, send me a sample of the
spreadsheet and I'll enter the formula for you. Jez -----Original Message----- the problem with this is that I don't know the the claim numbers' Example: 25 animals with the same ref number, they are all Adult and all are Yes - this would be 1 satisfactory claim. 41 animals with another refernce number (but the same), all Adult but with 2 No's - this shouldn't be counted as a satifacctory claim. I think what I want to do is count the number of animals in a claim, if all are yes then count it as 1. Gareth "Don Guillett" wrote in message ... try =sumproduct((rngA=12345)*(rngD={"Adult","Veal"})* (rngF="Yes")) "Gareth" wrote in message ... I have the following problem and don't mind which solution is forthcoming: Sheet1 contains data about claims made to our department (approx 700 rows). Column A contains the claim reference number (5 digits) - there can be up to 50 rows with the same reference number. Column D is either 'Adult' or 'Veal'. Column F is either 'Yes' or 'No' to say if the animal is satisfactory. What I need is the number of 'Adult' and 'Veal' claims that are satisfactory. A satisfactory claim is defined as one where all animals in a claim are 'Yes' in column F. Thanks in advance. Gareth . |
Help with code or formula
Yeah just send me an example
-----Original Message----- example data... Gareth "Jez" wrote in message ... You need to use IF, AND Function, send me a sample of the spreadsheet and I'll enter the formula for you. Jez -----Original Message----- the problem with this is that I don't know the the claim numbers' Example: 25 animals with the same ref number, they are all Adult and all are Yes - this would be 1 satisfactory claim. 41 animals with another refernce number (but the same), all Adult but with 2 No's - this shouldn't be counted as a satifacctory claim. I think what I want to do is count the number of animals in a claim, if all are yes then count it as 1. Gareth "Don Guillett" wrote in message ... try =sumproduct((rngA=12345)*(rngD={"Adult","Veal"})* (rngF="Yes")) "Gareth" wrote in message ... I have the following problem and don't mind which solution is forthcoming: Sheet1 contains data about claims made to our department (approx 700 rows). Column A contains the claim reference number (5 digits) - there can be up to 50 rows with the same reference number. Column D is either 'Adult' or 'Veal'. Column F is either 'Yes' or 'No' to say if the animal is satisfactory. What I need is the number of 'Adult' and 'Veal' claims that are satisfactory. A satisfactory claim is defined as one where all animals in a claim are 'Yes' in column F. Thanks in advance. Gareth . |
Help with code or formula
Gareth,
We try to discourage sending files to the ng. So, when someone says "send me an example", pls send to their email. "Gareth" wrote in message ... example data... Gareth "Jez" wrote in message ... You need to use IF, AND Function, send me a sample of the spreadsheet and I'll enter the formula for you. Jez -----Original Message----- the problem with this is that I don't know the the claim numbers' Example: 25 animals with the same ref number, they are all Adult and all are Yes - this would be 1 satisfactory claim. 41 animals with another refernce number (but the same), all Adult but with 2 No's - this shouldn't be counted as a satifacctory claim. I think what I want to do is count the number of animals in a claim, if all are yes then count it as 1. Gareth "Don Guillett" wrote in message ... try =sumproduct((rngA=12345)*(rngD={"Adult","Veal"})* (rngF="Yes")) "Gareth" wrote in message ... I have the following problem and don't mind which solution is forthcoming: Sheet1 contains data about claims made to our department (approx 700 rows). Column A contains the claim reference number (5 digits) - there can be up to 50 rows with the same reference number. Column D is either 'Adult' or 'Veal'. Column F is either 'Yes' or 'No' to say if the animal is satisfactory. What I need is the number of 'Adult' and 'Veal' claims that are satisfactory. A satisfactory claim is defined as one where all animals in a claim are 'Yes' in column F. Thanks in advance. Gareth . |
Help with code or formula
It dawned on me last night all you really need to use is a pivot table, it will amalgamate the data for you. -----Original Message----- Gareth, We try to discourage sending files to the ng. So, when someone says "send me an example", pls send to their email. "Gareth" wrote in message ... example data... Gareth "Jez" wrote in message ... You need to use IF, AND Function, send me a sample of the spreadsheet and I'll enter the formula for you. Jez -----Original Message----- the problem with this is that I don't know the the claim numbers' Example: 25 animals with the same ref number, they are all Adult and all are Yes - this would be 1 satisfactory claim. 41 animals with another refernce number (but the same), all Adult but with 2 No's - this shouldn't be counted as a satifacctory claim. I think what I want to do is count the number of animals in a claim, if all are yes then count it as 1. Gareth "Don Guillett" wrote in message ... try =sumproduct((rngA=12345)*(rngD={"Adult","Veal"})* (rngF="Yes")) "Gareth" wrote in message ... I have the following problem and don't mind which solution is forthcoming: Sheet1 contains data about claims made to our department (approx 700 rows). Column A contains the claim reference number (5 digits) - there can be up to 50 rows with the same reference number. Column D is either 'Adult' or 'Veal'. Column F is either 'Yes' or 'No' to say if the animal is satisfactory. What I need is the number of 'Adult' and 'Veal' claims that are satisfactory. A satisfactory claim is defined as one where all animals in a claim are 'Yes' in column F. Thanks in advance. Gareth . . |
Help with code or formula
never used pivot tables, can you help?
"Jez" wrote in message ... It dawned on me last night all you really need to use is a pivot table, it will amalgamate the data for you. -----Original Message----- Gareth, We try to discourage sending files to the ng. So, when someone says "send me an example", pls send to their email. "Gareth" wrote in message ... example data... Gareth "Jez" wrote in message ... You need to use IF, AND Function, send me a sample of the spreadsheet and I'll enter the formula for you. Jez -----Original Message----- the problem with this is that I don't know the the claim numbers' Example: 25 animals with the same ref number, they are all Adult and all are Yes - this would be 1 satisfactory claim. 41 animals with another refernce number (but the same), all Adult but with 2 No's - this shouldn't be counted as a satifacctory claim. I think what I want to do is count the number of animals in a claim, if all are yes then count it as 1. Gareth "Don Guillett" wrote in message ... try =sumproduct((rngA=12345)*(rngD={"Adult","Veal"})* (rngF="Yes")) "Gareth" wrote in message ... I have the following problem and don't mind which solution is forthcoming: Sheet1 contains data about claims made to our department (approx 700 rows). Column A contains the claim reference number (5 digits) - there can be up to 50 rows with the same reference number. Column D is either 'Adult' or 'Veal'. Column F is either 'Yes' or 'No' to say if the animal is satisfactory. What I need is the number of 'Adult' and 'Veal' claims that are satisfactory. A satisfactory claim is defined as one where all animals in a claim are 'Yes' in column F. Thanks in advance. Gareth . . |
Help with code or formula
Here are some links for pivottable info:
Debra Dalgleish's pictures at Jon Peltier's site: http://www.geocities.com/jonpeltier/...ivottables.htm And Debra's own site: http://www.contextures.com/xlPivot01.html John Walkenbach also has some at: http://j-walk.com/ss/excel/files/general.htm (look for Tony Gwynn's Hit Database) Chip Pearson keeps Harald Staff's notes at: http://www.cpearson.com/excel/pivots.htm MS has some at (xl2000 and xl2002): http://office.microsoft.com/downloads/2000/XCrtPiv.aspx http://office.microsoft.com/assistan...lconPT101.aspx Gareth wrote: never used pivot tables, can you help? "Jez" wrote in message ... It dawned on me last night all you really need to use is a pivot table, it will amalgamate the data for you. -----Original Message----- Gareth, We try to discourage sending files to the ng. So, when someone says "send me an example", pls send to their email. "Gareth" wrote in message ... example data... Gareth "Jez" wrote in message ... You need to use IF, AND Function, send me a sample of the spreadsheet and I'll enter the formula for you. Jez -----Original Message----- the problem with this is that I don't know the the claim numbers' Example: 25 animals with the same ref number, they are all Adult and all are Yes - this would be 1 satisfactory claim. 41 animals with another refernce number (but the same), all Adult but with 2 No's - this shouldn't be counted as a satifacctory claim. I think what I want to do is count the number of animals in a claim, if all are yes then count it as 1. Gareth "Don Guillett" wrote in message ... try =sumproduct((rngA=12345)*(rngD={"Adult","Veal"})* (rngF="Yes")) "Gareth" wrote in message ... I have the following problem and don't mind which solution is forthcoming: Sheet1 contains data about claims made to our department (approx 700 rows). Column A contains the claim reference number (5 digits) - there can be up to 50 rows with the same reference number. Column D is either 'Adult' or 'Veal'. Column F is either 'Yes' or 'No' to say if the animal is satisfactory. What I need is the number of 'Adult' and 'Veal' claims that are satisfactory. A satisfactory claim is defined as one where all animals in a claim are 'Yes' in column F. Thanks in advance. Gareth . . -- Dave Peterson |
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