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Brad Zenner

macro that loops to multiple columns
 
it's a simple macro that i've created, because I'm still a newbie at all of
this.

basically, the macro goes down each cell in a column, and if the cell's
value is greater than 300, then it puts in a background color into the cell.
the macro stops when the cell has nothing in it (the end of the column). I'd
like it to jump to the next column and repeat the macro, but not sure how to
do it. Here's what I've got so far:

Sub testcolors()
ActiveCell.Select
Do Until ActiveCell = ""
If ActiveCell = "" Then End
ActiveCell.Select
If ActiveCell 300 Then
With Selection.Interior
.ColorIndex = 6
.Pattern = xlSolid
.PatternColorIndex = xlAutomatic
End With
End If
ActiveCell.Offset(1,0).Activate
Loop
End Sub

Not even sure if this is the right way to write the macro.....
Any help is greatly appreciated. Thanks.
Brad




acw

macro that loops to multiple columns
 
Brad

If you can select the entire range, then the following
should give you what you are chasing.

Tony

Sub aaa()
Range("a1:c10").Select
ActiveCell.CurrentRegion.Select
For Each ce In Selection
If ce.Value 300 Then
With ce.Interior
.ColorIndex = 6
.Pattern = xlSolid
.PatternColorIndex = xlAutomatic
End With
End If
Next ce

End Sub
-----Original Message-----
it's a simple macro that i've created, because I'm still

a newbie at all of
this.

basically, the macro goes down each cell in a column, and

if the cell's
value is greater than 300, then it puts in a background

color into the cell.
the macro stops when the cell has nothing in it (the end

of the column). I'd
like it to jump to the next column and repeat the macro,

but not sure how to
do it. Here's what I've got so far:

Sub testcolors()
ActiveCell.Select
Do Until ActiveCell = ""
If ActiveCell = "" Then End
ActiveCell.Select
If ActiveCell 300 Then
With Selection.Interior
.ColorIndex = 6
.Pattern = xlSolid
.PatternColorIndex = xlAutomatic
End With
End If
ActiveCell.Offset(1,0).Activate
Loop
End Sub

Not even sure if this is the right way to write the

macro.....
Any help is greatly appreciated. Thanks.
Brad



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