Error Msg: 'No Cells were found'
 

I'm trying to build an array where the start of each
element will be defined by a particular value in
Col 6.

In the following code I receive the above error message
on the line marked ***

For Each ws In Workbooks(SourceWorkbook).Worksheets()
With ws
Shtname = ws.Name
Dim i As Long
Dim varr()
Dim rng As Range, Cell As Range, rng1 As Range
ReDim varr(1 To 1)

If Not (UCase(.Name) = "MASTER" Or UCase(.Name) _
= "COVER" Or UCase(.Name) = "CONTENTS" Or _
UCase(.Name) = "SUMMARY") Then
*** Set rng = Columns(6).SpecialCells(xlConstants, xlTextValues)
For Each Cell In rng
If Cell.Value = "£" Then
If IsEmpty(varr(1)) Then
Set varr(1) = Cell
Else
ReDim Preserve varr(1 To UBound(varr) + 1)
Set varr(UBound(varr)) = Cell
End If
End If
Next
etc

As far as I can see with the test workbook, there are instances of
'£' in Col 6 in every worksheet. Why does the code appear to fail to
find '£', please?

Regards.


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Error Msg: 'No Cells were found'
 

Yes, qualifying worked.
Thanks also for the test advice.

Regards.

"J.E. McGimpsey" wrote in message
...
For one thing, you're not qualifying Columns(6) with the worksheet.
That shouldn't cause the error if your activesheet column 6 has text
- does it?

Try:

Set rng = .Columns(6).SpecialCells(xlConstants, XLTextValues)



Also, I've found it's nearly always worth testing the results of
SpecialCells"


Set rng = .Columns(6).SpecialCells(xlConstants, XLTextValues)
If rng is Nothing Then
<handle no text found
Else
<your existing code
End If



In article ,
"Stuart" wrote:

I'm trying to build an array where the start of each
element will be defined by a particular value in
Col 6.

In the following code I receive the above error message
on the line marked ***

For Each ws In Workbooks(SourceWorkbook).Worksheets()
With ws
Shtname = ws.Name
Dim i As Long
Dim varr()
Dim rng As Range, Cell As Range, rng1 As Range
ReDim varr(1 To 1)

If Not (UCase(.Name) = "MASTER" Or UCase(.Name) _
= "COVER" Or UCase(.Name) = "CONTENTS" Or _
UCase(.Name) = "SUMMARY") Then
*** Set rng = Columns(6).SpecialCells(xlConstants, xlTextValues)
For Each Cell In rng
If Cell.Value = "£" Then
If IsEmpty(varr(1)) Then
Set varr(1) = Cell
Else
ReDim Preserve varr(1 To UBound(varr) + 1)
Set varr(UBound(varr)) = Cell
End If
End If
Next
etc

As far as I can see with the test workbook, there are instances of
'£' in Col 6 in every worksheet. Why does the code appear to fail to
find '£', please?

Regards.


---
Outgoing mail is certified Virus Free.
Checked by AVG anti-virus system (http://www.grisoft.com).
Version: 6.0.500 / Virus Database: 298 - Release Date: 10/07/2003




---
Outgoing mail is certified Virus Free.
Checked by AVG anti-virus system (http://www.grisoft.com).
Version: 6.0.500 / Virus Database: 298 - Release Date: 10/07/2003

Error Msg: 'No Cells were found'
 

Stuart

why do you believe the routine is not finding "£" signs ? What do you next
that doesn't work as you expect it to ?

The following extract from your code finds "£" signs in column 6 ... but
each entry in the array just contains a "£" sign. Is that what you expect ?

Dim i As Long
Dim varr()
Dim rng As Range, Cell As Range, rng1 As Range
ReDim varr(1 To 1)
Set rng = Columns(6).SpecialCells(xlConstants, xlTextValues)
For Each Cell In rng
If Cell.Value = "£" Then
If IsEmpty(varr(1)) Then
Set varr(1) = Cell
Else
ReDim Preserve varr(1 To UBound(varr) + 1)
Set varr(UBound(varr)) = Cell
End If
End If
Next

In my test I have four cells with values, only three of them "£" signs. I
ended up with an array of three elements, each containing a "£" sign.
Doesn't seem that useful an exercise but maybe I've just taken it out of
context ? If the cell contains anything besides the "£" sign it will be
ignored, for example, "£x"

Maybe you need: If Cell.Value Like "£*" Then

Another thought: if the contents of the cell is interpreted as a monetary
value then I don't think SpecialCells(xlConstants, xlTextValues) picks it
up.

As you are running this across all the worksheets, how do you plan to use
the information gathered ?

I think you need to step through your code to see what cells are included in
rng and how they are handled.

Regards

Trevor


"Stuart" wrote in message
...
I'm trying to build an array where the start of each
element will be defined by a particular value in
Col 6.

In the following code I receive the above error message
on the line marked ***

For Each ws In Workbooks(SourceWorkbook).Worksheets()
With ws
Shtname = ws.Name
Dim i As Long
Dim varr()
Dim rng As Range, Cell As Range, rng1 As Range
ReDim varr(1 To 1)

If Not (UCase(.Name) = "MASTER" Or UCase(.Name) _
= "COVER" Or UCase(.Name) = "CONTENTS" Or _
UCase(.Name) = "SUMMARY") Then
*** Set rng = Columns(6).SpecialCells(xlConstants, xlTextValues)
For Each Cell In rng
If Cell.Value = "£" Then
If IsEmpty(varr(1)) Then
Set varr(1) = Cell
Else
ReDim Preserve varr(1 To UBound(varr) + 1)
Set varr(UBound(varr)) = Cell
End If
End If
Next
etc

As far as I can see with the test workbook, there are instances of
'£' in Col 6 in every worksheet. Why does the code appear to fail to
find '£', please?

Regards.


---
Outgoing mail is certified Virus Free.
Checked by AVG anti-virus system (http://www.grisoft.com).
Version: 6.0.500 / Virus Database: 298 - Release Date: 10/07/2003

Error Msg: 'No Cells were found'
 

Just to add to J.E.'s advice,
Testing won't help if you never get past the set statement. When cells
matching the criteria are not found, that raises a trappable error so it
would be

On Error Resume Next
set rng = .Columns(6).SpecialCells(xlConstants, xlTextValues)
On Error goto 0
if not rng is nothing then
'cells were found
else
' cells were not found
End if

Don't get carried away with the On Error Resume next - nest it around the
command as shown - that is where it is needed. You have been down that road
before.

--
Regards,
Tom Ogilvy


Stuart wrote in message
...
Yes, qualifying worked.
Thanks also for the test advice.

Regards.

"J.E. McGimpsey" wrote in message
...
For one thing, you're not qualifying Columns(6) with the worksheet.
That shouldn't cause the error if your activesheet column 6 has text
- does it?

Try:

Set rng = .Columns(6).SpecialCells(xlConstants, XLTextValues)



Also, I've found it's nearly always worth testing the results of
SpecialCells"


Set rng = .Columns(6).SpecialCells(xlConstants, XLTextValues)
If rng is Nothing Then
<handle no text found
Else
<your existing code
End If



In article ,
"Stuart" wrote:

I'm trying to build an array where the start of each
element will be defined by a particular value in
Col 6.

In the following code I receive the above error message
on the line marked ***

For Each ws In Workbooks(SourceWorkbook).Worksheets()
With ws
Shtname = ws.Name
Dim i As Long
Dim varr()
Dim rng As Range, Cell As Range, rng1 As Range
ReDim varr(1 To 1)

If Not (UCase(.Name) = "MASTER" Or UCase(.Name) _
= "COVER" Or UCase(.Name) = "CONTENTS" Or _
UCase(.Name) = "SUMMARY") Then
*** Set rng = Columns(6).SpecialCells(xlConstants, xlTextValues)
For Each Cell In rng
If Cell.Value = "£" Then
If IsEmpty(varr(1)) Then
Set varr(1) = Cell
Else
ReDim Preserve varr(1 To UBound(varr) + 1)
Set varr(UBound(varr)) = Cell
End If
End If
Next
etc

As far as I can see with the test workbook, there are instances of
'£' in Col 6 in every worksheet. Why does the code appear to fail to
find '£', please?

Regards.


---
Outgoing mail is certified Virus Free.
Checked by AVG anti-virus system (http://www.grisoft.com).
Version: 6.0.500 / Virus Database: 298 - Release Date: 10/07/2003




---
Outgoing mail is certified Virus Free.
Checked by AVG anti-virus system (http://www.grisoft.com).
Version: 6.0.500 / Virus Database: 298 - Release Date: 10/07/2003

Error Msg: 'No Cells were found'
 

One thing I didn't include is that you need to have an On Error
Resume Next...On Error Goto (or a pointer to your error handling
routine) bracketing the call to SpecialCells, othewise Specialcells
can still throw a run-time error.


In article ,
"Stuart" wrote:

Yes, qualifying worked.
Thanks also for the test advice.

Error Msg: 'No Cells were found'
 

Yes, I remember that one!

Regards.

"Tom Ogilvy" wrote in message
...
Just to add to J.E.'s advice,
Testing won't help if you never get past the set statement. When cells
matching the criteria are not found, that raises a trappable error so it
would be

On Error Resume Next
set rng = .Columns(6).SpecialCells(xlConstants, xlTextValues)
On Error goto 0
if not rng is nothing then
'cells were found
else
' cells were not found
End if

Don't get carried away with the On Error Resume next - nest it around the
command as shown - that is where it is needed. You have been down that
road
before.

--
Regards,
Tom Ogilvy


Stuart wrote in message
...
Yes, qualifying worked.
Thanks also for the test advice.

Regards.

"J.E. McGimpsey" wrote in message
...
For one thing, you're not qualifying Columns(6) with the worksheet.
That shouldn't cause the error if your activesheet column 6 has text
- does it?

Try:

Set rng = .Columns(6).SpecialCells(xlConstants, XLTextValues)



Also, I've found it's nearly always worth testing the results of
SpecialCells"


Set rng = .Columns(6).SpecialCells(xlConstants, XLTextValues)
If rng is Nothing Then
<handle no text found
Else
<your existing code
End If



In article ,
"Stuart" wrote:

I'm trying to build an array where the start of each
element will be defined by a particular value in
Col 6.

In the following code I receive the above error message
on the line marked ***

For Each ws In Workbooks(SourceWorkbook).Worksheets()
With ws
Shtname = ws.Name
Dim i As Long
Dim varr()
Dim rng As Range, Cell As Range, rng1 As Range
ReDim varr(1 To 1)

If Not (UCase(.Name) = "MASTER" Or UCase(.Name) _
= "COVER" Or UCase(.Name) = "CONTENTS" Or _
UCase(.Name) = "SUMMARY") Then
*** Set rng = Columns(6).SpecialCells(xlConstants, xlTextValues)
For Each Cell In rng
If Cell.Value = "£" Then
If IsEmpty(varr(1)) Then
Set varr(1) = Cell
Else
ReDim Preserve varr(1 To UBound(varr) + 1)
Set varr(UBound(varr)) = Cell
End If
End If
Next
etc

As far as I can see with the test workbook, there are instances of
'£' in Col 6 in every worksheet. Why does the code appear to fail to
find '£', please?

Regards.


---
Outgoing mail is certified Virus Free.
Checked by AVG anti-virus system (http://www.grisoft.com).
Version: 6.0.500 / Virus Database: 298 - Release Date: 10/07/2003




---
Outgoing mail is certified Virus Free.
Checked by AVG anti-virus system (http://www.grisoft.com).
Version: 6.0.500 / Virus Database: 298 - Release Date: 10/07/2003






---
Outgoing mail is certified Virus Free.
Checked by AVG anti-virus system (http://www.grisoft.com).
Version: 6.0.500 / Virus Database: 298 - Release Date: 10/07/2003

Error Msg: 'No Cells were found'
 

Thanks for the reply.

I've taken the problem a little further, at least as far as
my limited knowledge allows.

My latest post explains what I've been using the array
for.......ie to collect the 'page' start instances in col(6).

Regards and thanks.

"Trevor Shuttleworth" wrote in message
...
Stuart

why do you believe the routine is not finding "£" signs ? What do you
next
that doesn't work as you expect it to ?

The following extract from your code finds "£" signs in column 6 ... but
each entry in the array just contains a "£" sign. Is that what you expect
?

Dim i As Long
Dim varr()
Dim rng As Range, Cell As Range, rng1 As Range
ReDim varr(1 To 1)
Set rng = Columns(6).SpecialCells(xlConstants, xlTextValues)
For Each Cell In rng
If Cell.Value = "£" Then
If IsEmpty(varr(1)) Then
Set varr(1) = Cell
Else
ReDim Preserve varr(1 To UBound(varr) + 1)
Set varr(UBound(varr)) = Cell
End If
End If
Next

In my test I have four cells with values, only three of them "£" signs. I
ended up with an array of three elements, each containing a "£" sign.
Doesn't seem that useful an exercise but maybe I've just taken it out of
context ? If the cell contains anything besides the "£" sign it will be
ignored, for example, "£x"

Maybe you need: If Cell.Value Like "£*" Then

Another thought: if the contents of the cell is interpreted as a monetary
value then I don't think SpecialCells(xlConstants, xlTextValues) picks it
up.

As you are running this across all the worksheets, how do you plan to use
the information gathered ?

I think you need to step through your code to see what cells are included
in
rng and how they are handled.

Regards

Trevor


"Stuart" wrote in message
...
I'm trying to build an array where the start of each
element will be defined by a particular value in
Col 6.

In the following code I receive the above error message
on the line marked ***

For Each ws In Workbooks(SourceWorkbook).Worksheets()
With ws
Shtname = ws.Name
Dim i As Long
Dim varr()
Dim rng As Range, Cell As Range, rng1 As Range
ReDim varr(1 To 1)

If Not (UCase(.Name) = "MASTER" Or UCase(.Name) _
= "COVER" Or UCase(.Name) = "CONTENTS" Or _
UCase(.Name) = "SUMMARY") Then
*** Set rng = Columns(6).SpecialCells(xlConstants, xlTextValues)
For Each Cell In rng
If Cell.Value = "£" Then
If IsEmpty(varr(1)) Then
Set varr(1) = Cell
Else
ReDim Preserve varr(1 To UBound(varr) + 1)
Set varr(UBound(varr)) = Cell
End If
End If
Next
etc

As far as I can see with the test workbook, there are instances of
'£' in Col 6 in every worksheet. Why does the code appear to fail to
find '£', please?

Regards.


---
Outgoing mail is certified Virus Free.
Checked by AVG anti-virus system (http://www.grisoft.com).
Version: 6.0.500 / Virus Database: 298 - Release Date: 10/07/2003






---
Outgoing mail is certified Virus Free.
Checked by AVG anti-virus system (http://www.grisoft.com).
Version: 6.0.500 / Virus Database: 298 - Release Date: 10/07/2003