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How to copy rows using fontcolor as bookmark?
Hi
I've got a workbook with 12 sheets, containing both old an new data. The old data is in red font, the new in blue. A sheet could contain maybe 200 - 300 rows with red font, and 0 - maybe 20 in blue. Is it possible to make a macro, that would copy/collect all the blue rows in all 12 sheets into an emty sheet, leaveing the copied rows red, in the original sheets? Best regards Henrik Bonde Btw. Don't hit the emailreplybutton. My header replyaddress don't work Reply to group :-) |
How to copy rows using fontcolor as bookmark?
Henrik,
These assumption must be true about the data: 1. Sheet1 has no data and is the sheet that will collect the blue data rows. 2. The entire row of blue data in each sheet is colored blue and the row starts in column A of each sheet. 3. there are no blanks in your blue data rows. Code could use some polishing, but it works: Sub test() Dim rng As Range For Each sht In Sheets Set rng = Nothing If sht.Name < "Sheet1" Then sht.Select ActiveSheet.UsedRange.Select For Each cell In Selection If (cell.Font.ColorIndex = 5) Then If rng Is Nothing Then Set rng = cell Else Set rng = Union(rng, cell) End If End If Next cell If Not rng Is Nothing Then rng.Select End If rng.EntireRow.Copy Worksheets("Sheet1").Select Range("A1").Select If ActiveCell.End(xlDown).Row = Rows.Count Then ActiveCell.Select: GoTo 10 ActiveCell.End(xlDown).Offset(1, 0).Select 10 ActiveSheet.Paste Else End If Next sht End Sub If you want a sample of the code in a file, e-mail me. Don Pistulka "Henrik Bonde (3400)" wrote in message ... Hi I've got a workbook with 12 sheets, containing both old an new data. The old data is in red font, the new in blue. A sheet could contain maybe 200 - 300 rows with red font, and 0 - maybe 20 in blue. Is it possible to make a macro, that would copy/collect all the blue rows in all 12 sheets into an emty sheet, leaveing the copied rows red, in the original sheets? Best regards Henrik Bonde Btw. Don't hit the emailreplybutton. My header replyaddress don't work Reply to group :-) |
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