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If problem
Can you tell me what's wrong with this formula please
=if(sheet1!A2<"",sheet1!a2,"") that is (being in sheet2) if there's a value in A2 on sheet1 copy it/reference it on sheet2 if not, leave blank. Many thanks, Suzanne |
If problem
Looks fine, what problem are you experiencing?
-- HTH Bob Phillips (replace somewhere in email address with gmail if mailing direct) "sedonovan" wrote in message ... Can you tell me what's wrong with this formula please =if(sheet1!A2<"",sheet1!a2,"") that is (being in sheet2) if there's a value in A2 on sheet1 copy it/reference it on sheet2 if not, leave blank. Many thanks, Suzanne |
If problem
Nel post
*sedonovan* ha scritto: Can you tell me what's wrong with this formula please =if(sheet1!A2<"",sheet1!a2,"") that is (being in sheet2) if there's a value in A2 on sheet1 copy it/reference it on sheet2 if not, leave blank. Many thanks, Suzanne Hi Suzanne, the formula seems to work fine... What is the results you have? -- Ciao Franz Verga from Italy |
If problem
"sedonovan" wrote in message
... Can you tell me what's wrong with this formula please =if(sheet1!A2<"",sheet1!a2,"") that is (being in sheet2) if there's a value in A2 on sheet1 copy it/reference it on sheet2 if not, leave blank. Nothing wrong with the formula, but of course you'd get a very similar result with the simpler formula =sheet1!A2, as you're putting a blank where you're finding a blank. -- David Biddulph |
If problem
Not he won't, it shows as zero
-- HTH Bob Phillips (replace somewhere in email address with gmail if mailing direct) "David Biddulph" wrote in message ... "sedonovan" wrote in message ... Can you tell me what's wrong with this formula please =if(sheet1!A2<"",sheet1!a2,"") that is (being in sheet2) if there's a value in A2 on sheet1 copy it/reference it on sheet2 if not, leave blank. Nothing wrong with the formula, but of course you'd get a very similar result with the simpler formula =sheet1!A2, as you're putting a blank where you're finding a blank. -- David Biddulph |
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