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Average of Unknown Range
I am trying to take an average of a changing range of numbers.
The range always starts at A2 but ends at different rows of column A. If I'm using the formula =AVERAGE(SMALL(A2:A??,{1,2,3,4,5})), how do I determine A?? (the last row containing data). Note: I have a field that contains the next available row number, so I could use it minus 1 except I don't know how to get the formula to use this value. Thanks for any help. Mike |
Average of Unknown Range
the trick is to try to match a number larger than any possible in the column
=AVERAGE(SMALL(INDIRECT("f2:f"&MATCH(999999999,F:F )),{1,2,3,4,5})) -- Don Guillett SalesAid Software "Mike" wrote in message ... I am trying to take an average of a changing range of numbers. The range always starts at A2 but ends at different rows of column A. If I'm using the formula =AVERAGE(SMALL(A2:A??,{1,2,3,4,5})), how do I determine A?? (the last row containing data). Note: I have a field that contains the next available row number, so I could use it minus 1 except I don't know how to get the formula to use this value. Thanks for any help. Mike |
Average of Unknown Range
Try something like this:
for a list if values (or blanks) beginning in A2 and ending with the location of the last numeric value in Col_A: This formula returns the average of the smallest 5 numeric cells: B1: =AVERAGE(SMALL(A2:INDEX(A:A,MATCH(10^99,A:A)),{1,2 ,3,4,5})) Does that help? *********** Regards, Ron XL2002, WinXP-Pro "Mike" wrote: I am trying to take an average of a changing range of numbers. The range always starts at A2 but ends at different rows of column A. If I'm using the formula =AVERAGE(SMALL(A2:A??,{1,2,3,4,5})), how do I determine A?? (the last row containing data). Note: I have a field that contains the next available row number, so I could use it minus 1 except I don't know how to get the formula to use this value. Thanks for any help. Mike |
Average of Unknown Range
That works.
Could I do the same type of thing for a straight average? B1: =AVERAGE(A2:INDEX(A:A,MATCH(10^99,A:A))) Mike "Ron Coderre" wrote: Try something like this: for a list if values (or blanks) beginning in A2 and ending with the location of the last numeric value in Col_A: This formula returns the average of the smallest 5 numeric cells: B1: =AVERAGE(SMALL(A2:INDEX(A:A,MATCH(10^99,A:A)),{1,2 ,3,4,5})) Does that help? *********** Regards, Ron XL2002, WinXP-Pro "Mike" wrote: I am trying to take an average of a changing range of numbers. The range always starts at A2 but ends at different rows of column A. If I'm using the formula =AVERAGE(SMALL(A2:A??,{1,2,3,4,5})), how do I determine A?? (the last row containing data). Note: I have a field that contains the next available row number, so I could use it minus 1 except I don't know how to get the formula to use this value. Thanks for any help. Mike |
Average of Unknown Range
I take it from the two responses I've received that it is not possible to
take the value in a cell and use it as a pointer to a cell? i.e. B1=400 So, C1=AVERAGE(A2:A,(B1-1) would come out to be C1=AVERAGE(A2:A399) Mike "Ron Coderre" wrote: Try something like this: for a list if values (or blanks) beginning in A2 and ending with the location of the last numeric value in Col_A: This formula returns the average of the smallest 5 numeric cells: B1: =AVERAGE(SMALL(A2:INDEX(A:A,MATCH(10^99,A:A)),{1,2 ,3,4,5})) Does that help? *********** Regards, Ron XL2002, WinXP-Pro "Mike" wrote: I am trying to take an average of a changing range of numbers. The range always starts at A2 but ends at different rows of column A. If I'm using the formula =AVERAGE(SMALL(A2:A??,{1,2,3,4,5})), how do I determine A?? (the last row containing data). Note: I have a field that contains the next available row number, so I could use it minus 1 except I don't know how to get the formula to use this value. Thanks for any help. Mike |
Average of Unknown Range
Try this:
B1l: (a numeric value) C1: =AVERAGE(A2:INDEX(A:A,(B1-1))) Is that what you're looking for? *********** Regards, Ron XL2002, WinXP-Pro "Mike" wrote: I take it from the two responses I've received that it is not possible to take the value in a cell and use it as a pointer to a cell? i.e. B1=400 So, C1=AVERAGE(A2:A,(B1-1) would come out to be C1=AVERAGE(A2:A399) Mike "Ron Coderre" wrote: Try something like this: for a list if values (or blanks) beginning in A2 and ending with the location of the last numeric value in Col_A: This formula returns the average of the smallest 5 numeric cells: B1: =AVERAGE(SMALL(A2:INDEX(A:A,MATCH(10^99,A:A)),{1,2 ,3,4,5})) Does that help? *********** Regards, Ron XL2002, WinXP-Pro "Mike" wrote: I am trying to take an average of a changing range of numbers. The range always starts at A2 but ends at different rows of column A. If I'm using the formula =AVERAGE(SMALL(A2:A??,{1,2,3,4,5})), how do I determine A?? (the last row containing data). Note: I have a field that contains the next available row number, so I could use it minus 1 except I don't know how to get the formula to use this value. Thanks for any help. Mike |
Average of Unknown Range
I pasted that in and it worked.
Now, any chance you could explain it a little? I don't see the purpose of the "A:A" preceding the "(B1-1)" Mike "Ron Coderre" wrote: Try this: B1l: (a numeric value) C1: =AVERAGE(A2:INDEX(A:A,(B1-1))) Is that what you're looking for? *********** Regards, Ron XL2002, WinXP-Pro "Mike" wrote: I take it from the two responses I've received that it is not possible to take the value in a cell and use it as a pointer to a cell? i.e. B1=400 So, C1=AVERAGE(A2:A,(B1-1) would come out to be C1=AVERAGE(A2:A399) Mike "Ron Coderre" wrote: Try something like this: for a list if values (or blanks) beginning in A2 and ending with the location of the last numeric value in Col_A: This formula returns the average of the smallest 5 numeric cells: B1: =AVERAGE(SMALL(A2:INDEX(A:A,MATCH(10^99,A:A)),{1,2 ,3,4,5})) Does that help? *********** Regards, Ron XL2002, WinXP-Pro "Mike" wrote: I am trying to take an average of a changing range of numbers. The range always starts at A2 but ends at different rows of column A. If I'm using the formula =AVERAGE(SMALL(A2:A??,{1,2,3,4,5})), how do I determine A?? (the last row containing data). Note: I have a field that contains the next available row number, so I could use it minus 1 except I don't know how to get the formula to use this value. Thanks for any help. Mike |
Average of Unknown Range
Sorry Ron,
I shouldn't have posted so quickly. After further analysis I see the structure of the formula. Thanks again, Mike "Ron Coderre" wrote: Try this: B1l: (a numeric value) C1: =AVERAGE(A2:INDEX(A:A,(B1-1))) Is that what you're looking for? *********** Regards, Ron XL2002, WinXP-Pro "Mike" wrote: I take it from the two responses I've received that it is not possible to take the value in a cell and use it as a pointer to a cell? i.e. B1=400 So, C1=AVERAGE(A2:A,(B1-1) would come out to be C1=AVERAGE(A2:A399) Mike "Ron Coderre" wrote: Try something like this: for a list if values (or blanks) beginning in A2 and ending with the location of the last numeric value in Col_A: This formula returns the average of the smallest 5 numeric cells: B1: =AVERAGE(SMALL(A2:INDEX(A:A,MATCH(10^99,A:A)),{1,2 ,3,4,5})) Does that help? *********** Regards, Ron XL2002, WinXP-Pro "Mike" wrote: I am trying to take an average of a changing range of numbers. The range always starts at A2 but ends at different rows of column A. If I'm using the formula =AVERAGE(SMALL(A2:A??,{1,2,3,4,5})), how do I determine A?? (the last row containing data). Note: I have a field that contains the next available row number, so I could use it minus 1 except I don't know how to get the formula to use this value. Thanks for any help. Mike |
Average of Unknown Range
OK...Here's the explanation:
Regarding: INDEX(A:A,(B1-1)) The INDEX function starts with a range and returns a reference to a cell in that range as indicated by the RowRef and ColRef arugments. Example: In =INDEX(A5:C10,2,3) we start with the range A5:C10 and isolate the cell that is in the second row and third column of that grid....C6. In our case, the range A:A refers to a single column so no ColRef is required. Since you could choose ANY row in Col_A to be the last cell referenced by the formula we have to assume that it could be anywhere in Col_A. Hence, the A:A reference. Does that help? *********** Regards, Ron XL2002, WinXP-Pro "Mike" wrote: I pasted that in and it worked. Now, any chance you could explain it a little? I don't see the purpose of the "A:A" preceding the "(B1-1)" Mike "Ron Coderre" wrote: Try this: B1l: (a numeric value) C1: =AVERAGE(A2:INDEX(A:A,(B1-1))) Is that what you're looking for? *********** Regards, Ron XL2002, WinXP-Pro "Mike" wrote: I take it from the two responses I've received that it is not possible to take the value in a cell and use it as a pointer to a cell? i.e. B1=400 So, C1=AVERAGE(A2:A,(B1-1) would come out to be C1=AVERAGE(A2:A399) Mike "Ron Coderre" wrote: Try something like this: for a list if values (or blanks) beginning in A2 and ending with the location of the last numeric value in Col_A: This formula returns the average of the smallest 5 numeric cells: B1: =AVERAGE(SMALL(A2:INDEX(A:A,MATCH(10^99,A:A)),{1,2 ,3,4,5})) Does that help? *********** Regards, Ron XL2002, WinXP-Pro "Mike" wrote: I am trying to take an average of a changing range of numbers. The range always starts at A2 but ends at different rows of column A. If I'm using the formula =AVERAGE(SMALL(A2:A??,{1,2,3,4,5})), how do I determine A?? (the last row containing data). Note: I have a field that contains the next available row number, so I could use it minus 1 except I don't know how to get the formula to use this value. Thanks for any help. Mike |
Average of Unknown Range
Great explanation.
Thanks! "Ron Coderre" wrote: OK...Here's the explanation: Regarding: INDEX(A:A,(B1-1)) The INDEX function starts with a range and returns a reference to a cell in that range as indicated by the RowRef and ColRef arugments. Example: In =INDEX(A5:C10,2,3) we start with the range A5:C10 and isolate the cell that is in the second row and third column of that grid....C6. In our case, the range A:A refers to a single column so no ColRef is required. Since you could choose ANY row in Col_A to be the last cell referenced by the formula we have to assume that it could be anywhere in Col_A. Hence, the A:A reference. Does that help? *********** Regards, Ron XL2002, WinXP-Pro "Mike" wrote: I pasted that in and it worked. Now, any chance you could explain it a little? I don't see the purpose of the "A:A" preceding the "(B1-1)" Mike "Ron Coderre" wrote: Try this: B1l: (a numeric value) C1: =AVERAGE(A2:INDEX(A:A,(B1-1))) Is that what you're looking for? *********** Regards, Ron XL2002, WinXP-Pro "Mike" wrote: I take it from the two responses I've received that it is not possible to take the value in a cell and use it as a pointer to a cell? i.e. B1=400 So, C1=AVERAGE(A2:A,(B1-1) would come out to be C1=AVERAGE(A2:A399) Mike "Ron Coderre" wrote: Try something like this: for a list if values (or blanks) beginning in A2 and ending with the location of the last numeric value in Col_A: This formula returns the average of the smallest 5 numeric cells: B1: =AVERAGE(SMALL(A2:INDEX(A:A,MATCH(10^99,A:A)),{1,2 ,3,4,5})) Does that help? *********** Regards, Ron XL2002, WinXP-Pro "Mike" wrote: I am trying to take an average of a changing range of numbers. The range always starts at A2 but ends at different rows of column A. If I'm using the formula =AVERAGE(SMALL(A2:A??,{1,2,3,4,5})), how do I determine A?? (the last row containing data). Note: I have a field that contains the next available row number, so I could use it minus 1 except I don't know how to get the formula to use this value. Thanks for any help. Mike |
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