#1   Report Post  
Posted to microsoft.public.excel.misc
fivermsg
 
Posts: n/a
Default need help


at 90% of company goal i get paid 1.84$, for every 1% increase up to 99%
i get 9 cents more ... any formula out there that could solve this for
me?

ex- (90%- 1.84) , (91%- 1.93) , (92%- 2.02) and so on up to 99%..


--
fivermsg
------------------------------------------------------------------------
fivermsg's Profile: http://www.excelforum.com/member.php...o&userid=32348
View this thread: http://www.excelforum.com/showthread...hreadid=521849

  #2   Report Post  
Posted to microsoft.public.excel.misc
Gary''s Student
 
Posts: n/a
Default need help

=IF(A1<0.9,0,1.84+(A1-0.9)*9)

if you put the %-tage in A1
--
Gary's Student


"fivermsg" wrote:


at 90% of company goal i get paid 1.84$, for every 1% increase up to 99%
i get 9 cents more ... any formula out there that could solve this for
me?

ex- (90%- 1.84) , (91%- 1.93) , (92%- 2.02) and so on up to 99%..


--
fivermsg
------------------------------------------------------------------------
fivermsg's Profile: http://www.excelforum.com/member.php...o&userid=32348
View this thread: http://www.excelforum.com/showthread...hreadid=521849


  #3   Report Post  
Posted to microsoft.public.excel.misc
Dominic
 
Posts: n/a
Default need help

Fiver,

I'd use a lookup table. Check out Debra's site at www.contextures.com

Basically, create a table with the percentage and amount as listed in your
post. Then use something like =a1*vlookup(b1,lookuptable,2,false)

a1 would be your unit count (assuming that this is how you will use your
percentage), b1 is your percentage for this value, lookuptable is the name
used for your lookup table, and false means find an exact match.

HTH

"fivermsg" wrote:


at 90% of company goal i get paid 1.84$, for every 1% increase up to 99%
i get 9 cents more ... any formula out there that could solve this for
me?

ex- (90%- 1.84) , (91%- 1.93) , (92%- 2.02) and so on up to 99%..


--
fivermsg
------------------------------------------------------------------------
fivermsg's Profile: http://www.excelforum.com/member.php...o&userid=32348
View this thread: http://www.excelforum.com/showthread...hreadid=521849


  #4   Report Post  
Posted to microsoft.public.excel.misc
fivermsg
 
Posts: n/a
Default need help


ok, this formula is working but it is continually counting even on mid
percent.. i only wont it to cont on everytime 1 single percent is
surpassed =IF(A1<0.9,0,1.84+(A1-0.9)*9)

any help?


--
fivermsg
------------------------------------------------------------------------
fivermsg's Profile: http://www.excelforum.com/member.php...o&userid=32348
View this thread: http://www.excelforum.com/showthread...hreadid=521849

  #5   Report Post  
Posted to microsoft.public.excel.misc
Dominic
 
Posts: n/a
Default need help

Fiver,

I like Gary's solution. How about:

=IF(A1<0.9,0,1.84+ROUNDDOWN((A1-0.9),2)*9)

HTH

"fivermsg" wrote:


ok, this formula is working but it is continually counting even on mid
percent.. i only wont it to cont on everytime 1 single percent is
surpassed =IF(A1<0.9,0,1.84+(A1-0.9)*9)

any help?


--
fivermsg
------------------------------------------------------------------------
fivermsg's Profile: http://www.excelforum.com/member.php...o&userid=32348
View this thread: http://www.excelforum.com/showthread...hreadid=521849




  #6   Report Post  
Posted to microsoft.public.excel.misc
fivermsg
 
Posts: n/a
Default need help


that doesn't work at all.. anyone one with another idea?


--
fivermsg
------------------------------------------------------------------------
fivermsg's Profile: http://www.excelforum.com/member.php...o&userid=32348
View this thread: http://www.excelforum.com/showthread...hreadid=521849

Reply
Thread Tools Search this Thread
Search this Thread:

Advanced Search
Display Modes

Posting Rules

Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On



All times are GMT +1. The time now is 07:05 AM.

Powered by vBulletin® Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
Copyright ©2004-2025 ExcelBanter.
The comments are property of their posters.
 

About Us

"It's about Microsoft Excel"