Advanced Formula...
 

Is there anyone out there who could assist with a probability formula?

Here is a quick sample...

I have numbers ranging from 1 to 100.
I have documented history of 800 "pick a number" from the above range.

For example, history looks like this:

1 picked 9 times, 2 picked 23 times, 3 picked 14 times, 4 picked 42 times...

How could I create a formula to determine the probability of numbers chosen
to be chosen again? Is it even possible?

Thanx.

Advanced Formula...
 

If the number picked is fair (equal chance), then each should have a 1/100
chance of being picked.

If the numbers aren't fairly picked, then you could use the number of times
picked / 800 as an estimate:

probability of
1 = 9/800
2 = 23/800
3 = 14/800
4 = 42/800
....

If this is like a lotto pick, then the numbers drawn last week won't have any
affect on the number drawn this week--pingpong balls don't have a memory (in
fair and honest games!).



Steven Sinclair wrote:

Is there anyone out there who could assist with a probability formula?

Here is a quick sample...

I have numbers ranging from 1 to 100.
I have documented history of 800 "pick a number" from the above range.

For example, history looks like this:

1 picked 9 times, 2 picked 23 times, 3 picked 14 times, 4 picked 42 times...

How could I create a formula to determine the probability of numbers chosen
to be chosen again? Is it even possible?

Thanx.

--

Dave Peterson

Advanced Formula...
 

If the numbers are picked at random from 1 to 100 then the probability of a
particular number being picked is 0.01. No formula is needed as previous
results will not affect the next result. It is an independant event.

"Steven Sinclair" wrote in
message ...
Is there anyone out there who could assist with a probability formula?

Here is a quick sample...

I have numbers ranging from 1 to 100.
I have documented history of 800 "pick a number" from the above range.

For example, history looks like this:

1 picked 9 times, 2 picked 23 times, 3 picked 14 times, 4 picked 42
times...

How could I create a formula to determine the probability of numbers
chosen
to be chosen again? Is it even possible?

Thanx.