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sumif when criteria is a range
I'm still an excel newbie--I searched the archives but couldn't find the
answer... How do I use sumif function when the criteria is a range (eg. =0 to <10 ). Thanks. -- Message posted via http://www.officekb.com |
One way:
=SUMPRODUCT(--(rng=0),--(rng<10), rng) another: =COUNTIF(rng,"=0") - COUNTIF(rng, "=10") a third =COUNTIF(rng, "<10") - COUNTIF(rng, "<0") In article , "jeremy via OfficeKB.com" wrote: I'm still an excel newbie--I searched the archives but couldn't find the answer... How do I use sumif function when the criteria is a range (eg. =0 to <10 ). Thanks. |
The Sumproduct formula that you quoted in your earlier post will do the same
job for this by just adding an additional argument: =SUMPRODUCT(($W$9:$W$272=0)*($W$9:$W$272<10)*$W$9 :$W$272) OR =SUMIF($W$9:$W$272,"0")-SUMIF($W$9:$W$272,"=10") -- HTH, RD ================================================== === Please keep all correspondence within the Group, so all may benefit! ================================================== === "jeremy via OfficeKB.com" wrote in message ... I'm still an excel newbie--I searched the archives but couldn't find the answer... How do I use sumif function when the criteria is a range (eg. =0 to <10 ). Thanks. -- Message posted via http://www.officekb.com |
Sorry, I forgot to specify that I want to sum a second column if the first
meets the criteria range... Eg. =SUMIF($BE$9:$BE$272, 0=<X<10, ($BF$9:$BF$272)) Of course, 0=<X<10 doesn't work..... Thanks.... JE McGimpsey wrote: One way: =SUMPRODUCT(--(rng=0),--(rng<10), rng) another: =COUNTIF(rng,"=0") - COUNTIF(rng, "=10") a third =COUNTIF(rng, "<10") - COUNTIF(rng, "<0") I'm still an excel newbie--I searched the archives but couldn't find the answer... How do I use sumif function when the criteria is a range (eg. =0 to <10 ). Thanks. -- Message posted via http://www.officekb.com |
John,
Countif ? Confusing the OP's 2 posts?<g -- Regards, RD ---------------------------------------------------------------------------- ------------------- Please keep all correspondence within the Group, so all may benefit ! ---------------------------------------------------------------------------- ------------------- "JE McGimpsey" wrote in message ... One way: =SUMPRODUCT(--(rng=0),--(rng<10), rng) another: =COUNTIF(rng,"=0") - COUNTIF(rng, "=10") a third =COUNTIF(rng, "<10") - COUNTIF(rng, "<0") In article , "jeremy via OfficeKB.com" wrote: I'm still an excel newbie--I searched the archives but couldn't find the answer... How do I use sumif function when the criteria is a range (eg. =0 to <10 ). Thanks. |
Again, you can use your original formula and just change the range that you
wish to total: =SUMPRODUCT(($BE$9:$BE$272=0)*($BE$9:$BE$272<10)* $BF$9:$BF$272) -- HTH, RD ================================================== === Please keep all correspondence within the Group, so all may benefit! ================================================== === "jeremy via OfficeKB.com" wrote in message ... Sorry, I forgot to specify that I want to sum a second column if the first meets the criteria range... Eg. =SUMIF($BE$9:$BE$272, 0=<X<10, ($BF$9:$BF$272)) Of course, 0=<X<10 doesn't work..... Thanks.... JE McGimpsey wrote: One way: =SUMPRODUCT(--(rng=0),--(rng<10), rng) another: =COUNTIF(rng,"=0") - COUNTIF(rng, "=10") a third =COUNTIF(rng, "<10") - COUNTIF(rng, "<0") I'm still an excel newbie--I searched the archives but couldn't find the answer... How do I use sumif function when the criteria is a range (eg. =0 to <10 ). Thanks. -- Message posted via http://www.officekb.com |
In article ,
"RagDyeR" wrote: Countif ? Yup - should have been SUMIF() |
thanks--that was brillant...
RagDyeR wrote: The Sumproduct formula that you quoted in your earlier post will do the same job for this by just adding an additional argument: =SUMPRODUCT(($W$9:$W$272=0)*($W$9:$W$272<10)*$W$ 9:$W$272) OR =SUMIF($W$9:$W$272,"0")-SUMIF($W$9:$W$272,"=10") I'm still an excel newbie--I searched the archives but couldn't find the answer... How do I use sumif function when the criteria is a range (eg. =0 to <10 ). Thanks. -- Message posted via http://www.officekb.com |
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