Home |
Search |
Today's Posts |
#4
![]()
Posted to microsoft.public.excel.misc
|
|||
|
|||
![]()
unless i miss something important Column F is always 36 x column E
so in your example: put "=36*E3" in F3 and copy down If you got the example wrong (the text says 'true value between 1-5') then the formula might be "=36/E3" hth RegMigrant "Alicia-Paris" wrote: It didnt work. Basically: 1=36, 2=72, 3=108, 4=132, 5=165. COLUMN E comes from a different worksheet via macros, so i want COLUMN F to then show the true value between 1-5 to the numbers shown above. i.e. e3= 4............... therefore i want f3= 132 "Mike H" wrote: Hi, This isn't; to me, very clear but maybe this =CHOOSE(E1,12,57,67,77,87) Now if e1 is 1 the formula returns 12, If e1=2 it returns 57 etc -- Mike When competing hypotheses are otherwise equal, adopt the hypothesis that introduces the fewest assumptions while still sufficiently answering the question. "Alicia-Paris" wrote: COLUMN E has a range from 1-5, COLUMN F I want to show a number depending on COLUMN E. E.g. if e1=1 then f1=12, if e2=4 then f1=57. I want the F COLUMN to depend on the E COLUMN. But I am not sure how to do this. The IF function doesnt work because I want there to be 5 conditions. Basically.... 1= one number 2= a different number 3= a diff number and so on; and with this, depending on which number gets put in cell E (1-5), i want F to reflect the true number. Please help guys as this is driving me bonkers! |