![]() |
Calculating the Length of Service between Hire and Termination dat
Let's say somebody was hired on October 2, 2006 and left on August 14, 2009.
I know that the YEAR function will return a value of 3.0. Is there a way I could calculate the Year and month i.e. in this case the length of service is 2 years and 10 months (ignoring the exact day of hire and termination) Or is there another acceptable way of showig Length of Service? Thanks. |
Calculating the Length of Service between Hire and Termination dat
With hire date in A1 and termination date in B1
=DATEDIF(A1,B1,"Y")&" Y, "&DATEDIF(A1,B1,"ym")&" M, "&DATEDIF(A1,B1,"md")&" D" will give you the answer down to days! You can leave off the days part with: =DATEDIF(A1,B1,"Y")&" Y, "&DATEDIF(A1,B1,"ym")&" M" Courtesy of Chip Pearson: http://www.cpearson.com/excel/datetimews.htm "Shams" wrote: Let's say somebody was hired on October 2, 2006 and left on August 14, 2009. I know that the YEAR function will return a value of 3.0. Is there a way I could calculate the Year and month i.e. in this case the length of service is 2 years and 10 months (ignoring the exact day of hire and termination) Or is there another acceptable way of showig Length of Service? Thanks. |
Calculating the Length of Service between Hire and Termination dat
Chip Pearson has some very nice notes:
http://www.cpearson.com/excel/datedif.aspx Shams wrote: Let's say somebody was hired on October 2, 2006 and left on August 14, 2009. I know that the YEAR function will return a value of 3.0. Is there a way I could calculate the Year and month i.e. in this case the length of service is 2 years and 10 months (ignoring the exact day of hire and termination) Or is there another acceptable way of showig Length of Service? Thanks. -- Dave Peterson |
All times are GMT +1. The time now is 05:24 PM. |
Powered by vBulletin® Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
ExcelBanter.com