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Column count if's
I have a column with employee code numbers. ie. A23,A34,A54,B43,B63,C23. They
are always a capital letter ans a 2 digit number. I need to build a formula for a range that tells me how many employees there are that start with and "A", a "B", a "C" and so on. Can someone help me with this? Thanks -- rustyrunrite |
Column count if's
Rusty,
This is what I came up with: Add a helper column to left of list of employee numbers. To total emploee numbers with "A" "=COUNTIF($B$1:$B$3,"A1") in cell to left of this formula I put "A". My list of employee numbers is in cell B1 thru B6, I used the numbers you provided A23, A34, A54, B34, B63, C23 To total emploee numbers with "B" "=COUNTIF($B$4:$B$5,"B1") in cell to left of this formula I put "B". To total emploee numbers with "C" "=COUNTIF($B$6:$B$6,"C1") in cell to left of this formula I put "C". It should look like this: A23 A34 A54 B43 B63 C23 "A" 6 "B" 2 "C" 1 hth "Rusty" wrote: I have a column with employee code numbers. ie. A23,A34,A54,B43,B63,C23. They are always a capital letter ans a 2 digit number. I need to build a formula for a range that tells me how many employees there are that start with and "A", a "B", a "C" and so on. Can someone help me with this? Thanks -- rustyrunrite |
Column count if's
Hi Rusty
You can use countif with a wildcard e.g:=COUNTIF(A1:A500,"A*") Adjust range and letter to your needs. HTH John "Rusty" wrote in message ... I have a column with employee code numbers. ie. A23,A34,A54,B43,B63,C23. They are always a capital letter ans a 2 digit number. I need to build a formula for a range that tells me how many employees there are that start with and "A", a "B", a "C" and so on. Can someone help me with this? Thanks -- rustyrunrite |
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