| Home |
| Search |
| Today's Posts |
|
#1
Posted to microsoft.public.excel.misc
|
|||
|
|||
Excel 2003 version of Countifs
I have tried the suggested Excel 2003 solution to the Countifs function but
am getting stuck. I want to count the number of tems in a spreadsheet where two predefined conditions are met so where the month = x and where the status is "1" My original formula is: =_xlfn.COUNTIFS('HB Appeals'!$E$2:$E$65536,"=5",'HB Appeals'!$L$2:$L$65536,"=1") as I had it sorted on Excel 2007. I have tried: =SUMPRODUCT("--('HB Appeals'!e2:E200,4)","--('HB Appeals'!L2:L200,1)") as suggested but I am getting nowhere. Please adise |
| Thread Tools | Search this Thread |
| Display Modes | |
|
|
Similar Threads
|
||||
| Thread | Forum | |||
| countifs on earlier version of excel | Excel Worksheet Functions | |||
| Countifs to Sumproduct for 2003 - was Simple Countifs.. from Fr | Excel Worksheet Functions | |||
| Alternative for =countifs (in 2007) for Excel 2003 | Excel Discussion (Misc queries) | |||
| translating countifs function to Excel 2003 | Excel Worksheet Functions | |||
| download trial version excel 2003? can only find trial version 200 | Excel Discussion (Misc queries) | |||
Threaded Mode
