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I have:
A1 = "A" A2 = "A" A3 = "B" A4= "C" A5= "A" and B1= "Apples" B2= "Pears" B3= "Strawberries" B4= "Pears" B5= "Apples" I want to calculate the following: For all the occurences of "A" in Column A, I want to count the uniquely different TYPES of values that are contained in column B. E.g. in the example above, the answer will be "2", because there are 3 x occurences of "A" in column A, and these 3 occurences related to 2 occurences of "Apples" and 1 of "Pears", thus 2 unique strings of data. Please help. |
#2
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Try the following formula, which needs to be confirmed with
CONTROL+SHIFT+ENTER, not just ENTER... =SUM(IF(FREQUENCY(IF(A1:A5="A",IF(B1:B5<"",MATCH( "~"&B1:B5,B1:B5&"",0))) ,ROW(B1:B5)-ROW(B1)+1),1)) Hope this helps! http://www.xl-central.com In article , WildWill wrote: I have: A1 = "A" A2 = "A" A3 = "B" A4= "C" A5= "A" and B1= "Apples" B2= "Pears" B3= "Strawberries" B4= "Pears" B5= "Apples" I want to calculate the following: For all the occurences of "A" in Column A, I want to count the uniquely different TYPES of values that are contained in column B. E.g. in the example above, the answer will be "2", because there are 3 x occurences of "A" in column A, and these 3 occurences related to 2 occurences of "Apples" and 1 of "Pears", thus 2 unique strings of data. Please help. |
#3
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Try this:
=ROUND(SUMPRODUCT(--(A1:A5="A"),1/COUNTIF(B1:B5,B1:B5&"")),0) HTH Elkar "WildWill" wrote: I have: A1 = "A" A2 = "A" A3 = "B" A4= "C" A5= "A" and B1= "Apples" B2= "Pears" B3= "Strawberries" B4= "Pears" B5= "Apples" I want to calculate the following: For all the occurences of "A" in Column A, I want to count the uniquely different TYPES of values that are contained in column B. E.g. in the example above, the answer will be "2", because there are 3 x occurences of "A" in column A, and these 3 occurences related to 2 occurences of "Apples" and 1 of "Pears", thus 2 unique strings of data. Please help. |
#4
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This formula may not return the desired result in some circumstances.
For example, if A1:B5 contains the following data... A Apples A Pears B Pears C Pears A Apples ....the formula will return 1, instead of 2, which is the desired result. Hope this helps! http://www.xl-central.com In article , Elkar wrote: Try this: =ROUND(SUMPRODUCT(--(A1:A5="A"),1/COUNTIF(B1:B5,B1:B5&"")),0) HTH Elkar "WildWill" wrote: I have: A1 = "A" A2 = "A" A3 = "B" A4= "C" A5= "A" and B1= "Apples" B2= "Pears" B3= "Strawberries" B4= "Pears" B5= "Apples" I want to calculate the following: For all the occurences of "A" in Column A, I want to count the uniquely different TYPES of values that are contained in column B. E.g. in the example above, the answer will be "2", because there are 3 x occurences of "A" in column A, and these 3 occurences related to 2 occurences of "Apples" and 1 of "Pears", thus 2 unique strings of data. Please help. |
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