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This is a follow up to a previous question:
I have a web query which gives me the result "385/1700" and all I want is the first part "385" to allow me to do calculations with, but because it's a web query, it wont let me just format it as a fraction and times it by 1700.. it comes up with the #VALUE! error. So I dont know what else to try, Can anyone help? Thanks, Aden --------------------------------------------------- Answer: =--(LEFT(A1,FIND("/",A1)-1)) -- HTH Bob My question is basically the same as the first, except I need the numbers on the right side of the "/" (the 1700). Thanks, Anthony |
#2
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Given the example, surely you can figure this out yourself.
-- Don Guillett Microsoft MVP Excel SalesAid Software "AJSloss" wrote in message ... This is a follow up to a previous question: I have a web query which gives me the result "385/1700" and all I want is the first part "385" to allow me to do calculations with, but because it's a web query, it wont let me just format it as a fraction and times it by 1700.. it comes up with the #VALUE! error. So I dont know what else to try, Can anyone help? Thanks, Aden --------------------------------------------------- Answer: =--(LEFT(A1,FIND("/",A1)-1)) -- HTH Bob My question is basically the same as the first, except I need the numbers on the right side of the "/" (the 1700). Thanks, Anthony |
#4
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![]() Also have a look at LEN and MID -- Don Guillett Microsoft MVP Excel SalesAid Software "AJSloss" wrote in message ... well, dick i haven't been able to figure it out, otherwise i wouldn't have posted the question. i tried substituting "right" for "left" and in some cases it works and sometimes it doesn't based on how many digits are in the whole cell "Don Guillett" wrote: Given the example, surely you can figure this out yourself. -- Don Guillett Microsoft MVP Excel SalesAid Software "AJSloss" wrote in message ... This is a follow up to a previous question: I have a web query which gives me the result "385/1700" and all I want is the first part "385" to allow me to do calculations with, but because it's a web query, it wont let me just format it as a fraction and times it by 1700.. it comes up with the #VALUE! error. So I dont know what else to try, Can anyone help? Thanks, Aden --------------------------------------------------- Answer: =--(LEFT(A1,FIND("/",A1)-1)) -- HTH Bob My question is basically the same as the first, except I need the numbers on the right side of the "/" (the 1700). Thanks, Anthony |
#5
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Try this...
=MID(A1,FIND("/",A1)+1,99) -- Rick (MVP - Excel) "AJSloss" wrote in message ... This is a follow up to a previous question: I have a web query which gives me the result "385/1700" and all I want is the first part "385" to allow me to do calculations with, but because it's a web query, it wont let me just format it as a fraction and times it by 1700.. it comes up with the #VALUE! error. So I dont know what else to try, Can anyone help? Thanks, Aden --------------------------------------------------- Answer: =--(LEFT(A1,FIND("/",A1)-1)) -- HTH Bob My question is basically the same as the first, except I need the numbers on the right side of the "/" (the 1700). Thanks, Anthony |
#6
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That's exactly what I needed. Thanks Rick
"Rick Rothstein" wrote: Try this... =MID(A1,FIND("/",A1)+1,99) -- Rick (MVP - Excel) "AJSloss" wrote in message ... This is a follow up to a previous question: I have a web query which gives me the result "385/1700" and all I want is the first part "385" to allow me to do calculations with, but because it's a web query, it wont let me just format it as a fraction and times it by 1700.. it comes up with the #VALUE! error. So I dont know what else to try, Can anyone help? Thanks, Aden --------------------------------------------------- Answer: =--(LEFT(A1,FIND("/",A1)-1)) -- HTH Bob My question is basically the same as the first, except I need the numbers on the right side of the "/" (the 1700). Thanks, Anthony |
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