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#1
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I am trying to write a formula that will take the total contract value
and times it by the assoicated percentage. $1-$4,999,999 = 5% $5,000,000 - $9,999,999 = 10% $10,000,000+ = 15% If the contract value is $6,000,000, than it would do ($4,999,999*5%)+ ($1,000,001*10%)=$350,000.05 |
#2
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=(A1<"")*MIN(A1,4999999)*5%+MAX(0,A1-4999999)*10%+MAX(0,A1-9999999)*15%
-- ** John C ** Please remember if your question is answered, to mark it answered :). It helps everyone. "KevinM" wrote: I am trying to write a formula that will take the total contract value and times it by the assoicated percentage. $1-$4,999,999 = 5% $5,000,000 - $9,999,999 = 10% $10,000,000+ = 15% If the contract value is $6,000,000, than it would do ($4,999,999*5%)+ ($1,000,001*10%)=$350,000.05 |
#3
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=MIN(A1,4999999)*5%+MAX(0,A1-4999999)*10%+MAX(0,A1-9999999)*15%
And if this is homework, please be sure you can explain how it works <grin best wishes -- Bernard V Liengme Microsoft Excel MVP http://people.stfx.ca/bliengme remove caps from email "KevinM" wrote in message ... I am trying to write a formula that will take the total contract value and times it by the assoicated percentage. $1-$4,999,999 = 5% $5,000,000 - $9,999,999 = 10% $10,000,000+ = 15% If the contract value is $6,000,000, than it would do ($4,999,999*5%)+ ($1,000,001*10%)=$350,000.05 |
#4
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I want to thank you all for the help, but i am not getting the correct
answer back when I try to use you formula. It is double counting somewhere. I tried the following formula and it will only work for two out of the three values i try. Is there a limitation for IF statements? Value = $15,000,000 - Should return back $1,500,000.15 Value = $ 7,000,000 - Should return back $450,000.05 Value = $3,000,000 - Should return back $150,000 =IF(A1<6000000,(A1*$B$34),IF(A16000000&A1<1000000 0,((A1-6000001)*$B $35)+(5999999*$B$34),IF(A110000000,((A1-10000002)*$B$36)+(3999999*$B $35)+(5999999*$B$34),"0"))) |
#5
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=(A1<"")*MIN(A1,4999999)*5%+MAX(0,MIN(A1,9999999)-4999999)*10%+MAX(0,A1-9999999)*15%
You should still tell us how the formula actually works :) -- ** John C ** "KevinM" wrote: I want to thank you all for the help, but i am not getting the correct answer back when I try to use you formula. It is double counting somewhere. I tried the following formula and it will only work for two out of the three values i try. Is there a limitation for IF statements? Value = $15,000,000 - Should return back $1,500,000.15 Value = $ 7,000,000 - Should return back $450,000.05 Value = $3,000,000 - Should return back $150,000 =IF(A1<6000000,(A1*$B$34),IF(A16000000&A1<1000000 0,((A1-6000001)*$B $35)+(5999999*$B$34),IF(A110000000,((A1-10000002)*$B$36)+(3999999*$B $35)+(5999999*$B$34),"0"))) |
#6
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again this works for $3mil and $7mil but not $15Mil. When i try it
for $15mil it gives me $800K for an answer and not the correct $1.5Mil answer |
#7
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Perhaps you would be so kind to copy/paste your formula that is giving you
800000? For me, it gives me the exact answer you were requiring. I modified the formula to add some additional error checking if A1 is blank: =(A1<"")*(MIN(A1,4999999)*5%+MAX(0,MIN(A1,9999999 )-4999999)*10%)+MAX(0,A1-9999999)*15% But otherwise, I type 15,000,000 and I get an 1,500,000.10, so I am really curious what error you made in entering the formula. Did you re-type the original formula? or did you copy/paste? -- ** John C ** "KevinM" wrote: again this works for $3mil and $7mil but not $15Mil. When i try it for $15mil it gives me $800K for an answer and not the correct $1.5Mil answer |
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