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Kaylen

Addition formulas problem
 
For example:
addition formula: A+B+C=D
Condition 1: If A=B=C=N/A, shows N/A since all = N/A
Condition 2: If A=B=C=0, the shows 0 since 0+0+0+0+0=0
Condition 3: If A=0, B=0, C=0, but D= N/A, shows 0 since A+B+C=0
Condition 4: If A=N/A, B=N/A, C=N/A, but C=0, shows 0
Condition 5: If A=4, B=4, C=4, D=N/A, shows 12 since 4+4+4=12
Condition 6: If A= 4, B=4, C= 0, D=N/A, shows 8 since 4+4+0=8
Etc...

Problem:
If example formula is =SUM(E8:E12), then if all(E8 to E12) are N/A then it
shows 0( I want it to show N/A if all is N/A) --- only condition 2 is met

If example formula is =IF(SUM(D8:D12)=0,"N/A",SUM(D8:D12)) then when all is
0, it shows N/A( I want it to shows 0 if all is 0)----only condition 1 is met

I am looking for a formula where both conditions can be true.

Any help is greatly appreciated!!


AKphidelt

Addition formulas problem
 
This is untested but you could try using count and counta to determine if
there is any text in the series. For instance the formula might be

=IF((COUNTA(A1:C1)-COUNT(A1:C1))=0,SUM(A1:C1),"NA")

Basically count, counts all numerical values. Counta counts everything

"Kaylen" wrote:

For example:
addition formula: A+B+C=D
Condition 1: If A=B=C=N/A, shows N/A since all = N/A
Condition 2: If A=B=C=0, the shows 0 since 0+0+0+0+0=0
Condition 3: If A=0, B=0, C=0, but D= N/A, shows 0 since A+B+C=0
Condition 4: If A=N/A, B=N/A, C=N/A, but C=0, shows 0
Condition 5: If A=4, B=4, C=4, D=N/A, shows 12 since 4+4+4=12
Condition 6: If A= 4, B=4, C= 0, D=N/A, shows 8 since 4+4+0=8
Etc...

Problem:
If example formula is =SUM(E8:E12), then if all(E8 to E12) are N/A then it
shows 0( I want it to show N/A if all is N/A) --- only condition 2 is met

If example formula is =IF(SUM(D8:D12)=0,"N/A",SUM(D8:D12)) then when all is
0, it shows N/A( I want it to shows 0 if all is 0)----only condition 1 is met

I am looking for a formula where both conditions can be true.

Any help is greatly appreciated!!


Kaylen

Addition formulas problem
 
Based on your suggestion, this is the formula:
=IF((COUNTA(E8:E12)-COUNT(E8:E12))=0, SUM(E8:E12),"N/A")

Both conditions 1 and 2 are met with this formula, BUT, however, if one of
the values is N/A, for example B=N/A, the result shows N/A instead of summing
the other values. Like for conditions 4, 5, and 6, the results are N/A which
suppose to showing the sum. Is there a forumla where all conditions can be
true?

Thank you so much for you effort.

"akphidelt" wrote:

This is untested but you could try using count and counta to determine if
there is any text in the series. For instance the formula might be

=IF((COUNTA(A1:C1)-COUNT(A1:C1))=0,SUM(A1:C1),"NA")

Basically count, counts all numerical values. Counta counts everything

"Kaylen" wrote:

For example:
addition formula: A+B+C=D
Condition 1: If A=B=C=N/A, shows N/A since all = N/A
Condition 2: If A=B=C=0, the shows 0 since 0+0+0+0+0=0
Condition 3: If A=0, B=0, C=0, but D= N/A, shows 0 since A+B+C=0
Condition 4: If A=N/A, B=N/A, C=N/A, but C=0, shows 0
Condition 5: If A=4, B=4, C=4, D=N/A, shows 12 since 4+4+4=12
Condition 6: If A= 4, B=4, C= 0, D=N/A, shows 8 since 4+4+0=8
Etc...

Problem:
If example formula is =SUM(E8:E12), then if all(E8 to E12) are N/A then it
shows 0( I want it to show N/A if all is N/A) --- only condition 2 is met

If example formula is =IF(SUM(D8:D12)=0,"N/A",SUM(D8:D12)) then when all is
0, it shows N/A( I want it to shows 0 if all is 0)----only condition 1 is met

I am looking for a formula where all conditions can be true.

Any help is greatly appreciated!!


Sandy Mann

Addition formulas problem
 
I understand your conditions to be if all entries, (which may not be all
five cells), are N/A then return N/A otherwise return the SUM() of E8:E12,
if so then try:

=IF(COUNTIF(E8:E12,"n/a")=COUNTA(E8:E12),"N/A",SUM(E8:E12))

--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"Kaylen" wrote in message
...
Based on your suggestion, this is the formula:
=IF((COUNTA(E8:E12)-COUNT(E8:E12))=0, SUM(E8:E12),"N/A")

Both conditions 1 and 2 are met with this formula, BUT, however, if one of
the values is N/A, for example B=N/A, the result shows N/A instead of
summing
the other values. Like for conditions 4, 5, and 6, the results are N/A
which
suppose to showing the sum. Is there a forumla where all conditions can be
true?

Thank you so much for you effort.

"akphidelt" wrote:

This is untested but you could try using count and counta to determine if
there is any text in the series. For instance the formula might be

=IF((COUNTA(A1:C1)-COUNT(A1:C1))=0,SUM(A1:C1),"NA")

Basically count, counts all numerical values. Counta counts everything

"Kaylen" wrote:

For example:
addition formula: A+B+C=D
Condition 1: If A=B=C=N/A, shows N/A since all = N/A
Condition 2: If A=B=C=0, the shows 0 since 0+0+0+0+0=0
Condition 3: If A=0, B=0, C=0, but D= N/A, shows 0 since A+B+C=0
Condition 4: If A=N/A, B=N/A, C=N/A, but C=0, shows 0
Condition 5: If A=4, B=4, C=4, D=N/A, shows 12 since 4+4+4=12
Condition 6: If A= 4, B=4, C= 0, D=N/A, shows 8 since 4+4+0=8
Etc...

Problem:
If example formula is =SUM(E8:E12), then if all(E8 to E12) are N/A then
it
shows 0( I want it to show N/A if all is N/A) --- only condition 2 is
met

If example formula is =IF(SUM(D8:D12)=0,"N/A",SUM(D8:D12)) then when
all is
0, it shows N/A( I want it to shows 0 if all is 0)----only condition 1
is met

I am looking for a formula where all conditions can be true.

Any help is greatly appreciated!!





Kaylen

Addition formulas problem
 
Thank you soo much Sandy! It works!

"Sandy Mann" wrote:

I understand your conditions to be if all entries, (which may not be all
five cells), are N/A then return N/A otherwise return the SUM() of E8:E12,
if so then try:

=IF(COUNTIF(E8:E12,"n/a")=COUNTA(E8:E12),"N/A",SUM(E8:E12))

--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"Kaylen" wrote in message
...
Based on your suggestion, this is the formula:
=IF((COUNTA(E8:E12)-COUNT(E8:E12))=0, SUM(E8:E12),"N/A")

Both conditions 1 and 2 are met with this formula, BUT, however, if one of
the values is N/A, for example B=N/A, the result shows N/A instead of
summing
the other values. Like for conditions 4, 5, and 6, the results are N/A
which
suppose to showing the sum. Is there a forumla where all conditions can be
true?

Thank you so much for you effort.

"akphidelt" wrote:

This is untested but you could try using count and counta to determine if
there is any text in the series. For instance the formula might be

=IF((COUNTA(A1:C1)-COUNT(A1:C1))=0,SUM(A1:C1),"NA")

Basically count, counts all numerical values. Counta counts everything

"Kaylen" wrote:

For example:
addition formula: A+B+C=D
Condition 1: If A=B=C=N/A, shows N/A since all = N/A
Condition 2: If A=B=C=0, the shows 0 since 0+0+0+0+0=0
Condition 3: If A=0, B=0, C=0, but D= N/A, shows 0 since A+B+C=0
Condition 4: If A=N/A, B=N/A, C=N/A, but C=0, shows 0
Condition 5: If A=4, B=4, C=4, D=N/A, shows 12 since 4+4+4=12
Condition 6: If A= 4, B=4, C= 0, D=N/A, shows 8 since 4+4+0=8
Etc...

Problem:
If example formula is =SUM(E8:E12), then if all(E8 to E12) are N/A then
it
shows 0( I want it to show N/A if all is N/A) --- only condition 2 is
met

If example formula is =IF(SUM(D8:D12)=0,"N/A",SUM(D8:D12)) then when
all is
0, it shows N/A( I want it to shows 0 if all is 0)----only condition 1
is met

I am looking for a formula where all conditions can be true.

Any help is greatly appreciated!!






Sandy Mann

Addition formulas problem
 
You are very welcome, thanks for letting us know that it worked.

--
Regards,

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"Kaylen" wrote in message
...
Thank you soo much Sandy! It works!

"Sandy Mann" wrote:

I understand your conditions to be if all entries, (which may not be all
five cells), are N/A then return N/A otherwise return the SUM() of
E8:E12,
if so then try:

=IF(COUNTIF(E8:E12,"n/a")=COUNTA(E8:E12),"N/A",SUM(E8:E12))

--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"Kaylen" wrote in message
...
Based on your suggestion, this is the formula:
=IF((COUNTA(E8:E12)-COUNT(E8:E12))=0, SUM(E8:E12),"N/A")

Both conditions 1 and 2 are met with this formula, BUT, however, if one
of
the values is N/A, for example B=N/A, the result shows N/A instead of
summing
the other values. Like for conditions 4, 5, and 6, the results are N/A
which
suppose to showing the sum. Is there a forumla where all conditions can
be
true?

Thank you so much for you effort.

"akphidelt" wrote:

This is untested but you could try using count and counta to determine
if
there is any text in the series. For instance the formula might be

=IF((COUNTA(A1:C1)-COUNT(A1:C1))=0,SUM(A1:C1),"NA")

Basically count, counts all numerical values. Counta counts everything

"Kaylen" wrote:

For example:
addition formula: A+B+C=D
Condition 1: If A=B=C=N/A, shows N/A since all = N/A
Condition 2: If A=B=C=0, the shows 0 since 0+0+0+0+0=0
Condition 3: If A=0, B=0, C=0, but D= N/A, shows 0 since A+B+C=0
Condition 4: If A=N/A, B=N/A, C=N/A, but C=0, shows 0
Condition 5: If A=4, B=4, C=4, D=N/A, shows 12 since 4+4+4=12
Condition 6: If A= 4, B=4, C= 0, D=N/A, shows 8 since 4+4+0=8
Etc...

Problem:
If example formula is =SUM(E8:E12), then if all(E8 to E12) are N/A
then
it
shows 0( I want it to show N/A if all is N/A) --- only condition 2
is
met

If example formula is =IF(SUM(D8:D12)=0,"N/A",SUM(D8:D12)) then when
all is
0, it shows N/A( I want it to shows 0 if all is 0)----only condition
1
is met

I am looking for a formula where all conditions can be true.

Any help is greatly appreciated!!









Kaylen

Addition formulas problem
 
I tried the formula with a range of cells and it works, but for the ones that
involve a certain cell, I keep getting error message.

This is the formula I entered based on your suggestion:
=IF(COUNTIF(E18:E22,E14,"N/A")=COUNTA(E18:E22,E14),"N/A",SUM(E18:E22,E14))

I get an error message saying that the formula has too many aruguments. Can
this forumla be fixed?

"Sandy Mann" wrote:

I understand your conditions to be if all entries, (which may not be all
five cells), are N/A then return N/A otherwise return the SUM() of E8:E12,
if so then try:

=IF(COUNTIF(E8:E12,"n/a")=COUNTA(E8:E12),"N/A",SUM(E8:E12))

--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"Kaylen" wrote in message
...
Based on your suggestion, this is the formula:
=IF((COUNTA(E8:E12)-COUNT(E8:E12))=0, SUM(E8:E12),"N/A")

Both conditions 1 and 2 are met with this formula, BUT, however, if one of
the values is N/A, for example B=N/A, the result shows N/A instead of
summing
the other values. Like for conditions 4, 5, and 6, the results are N/A
which
suppose to showing the sum. Is there a forumla where all conditions can be
true?

Thank you so much for you effort.

"akphidelt" wrote:

This is untested but you could try using count and counta to determine if
there is any text in the series. For instance the formula might be

=IF((COUNTA(A1:C1)-COUNT(A1:C1))=0,SUM(A1:C1),"NA")

Basically count, counts all numerical values. Counta counts everything

"Kaylen" wrote:

For example:
addition formula: A+B+C=D
Condition 1: If A=B=C=N/A, shows N/A since all = N/A
Condition 2: If A=B=C=0, the shows 0 since 0+0+0+0+0=0
Condition 3: If A=0, B=0, C=0, but D= N/A, shows 0 since A+B+C=0
Condition 4: If A=N/A, B=N/A, C=N/A, but C=0, shows 0
Condition 5: If A=4, B=4, C=4, D=N/A, shows 12 since 4+4+4=12
Condition 6: If A= 4, B=4, C= 0, D=N/A, shows 8 since 4+4+0=8
Etc...

Problem:
If example formula is =SUM(E8:E12), then if all(E8 to E12) are N/A then
it
shows 0( I want it to show N/A if all is N/A) --- only condition 2 is
met

If example formula is =IF(SUM(D8:D12)=0,"N/A",SUM(D8:D12)) then when
all is
0, it shows N/A( I want it to shows 0 if all is 0)----only condition 1
is met

I am looking for a formula where all conditions can be true.

Any help is greatly appreciated!!






Sandy Mann

Addition formulas problem
 
Try:

=IF(COUNTIF(E18:E22,"N/A")+(E14="N/A")=COUNTA(E18:E22,E14),"N/A",SUM(E18:E22,E14))

This returns N/A for all empty cell then try:

=IF((COUNTA(E18:E22)=0)+(E14="")=2,"",IF(COUNTIF(E 18:E22,"N/A")+(E14="N/A")=COUNTA(E18:E22,E14),"N/A",SUM(E18:E22,E14)))

--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"Kaylen" wrote in message
...
I tried the formula with a range of cells and it works, but for the ones
that
involve a certain cell, I keep getting error message.

This is the formula I entered based on your suggestion:
=IF(COUNTIF(E18:E22,E14,"N/A")=COUNTA(E18:E22,E14),"N/A",SUM(E18:E22,E14))

I get an error message saying that the formula has too many aruguments.
Can
this forumla be fixed?

"Sandy Mann" wrote:

I understand your conditions to be if all entries, (which may not be all
five cells), are N/A then return N/A otherwise return the SUM() of
E8:E12,
if so then try:

=IF(COUNTIF(E8:E12,"n/a")=COUNTA(E8:E12),"N/A",SUM(E8:E12))

--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"Kaylen" wrote in message
...
Based on your suggestion, this is the formula:
=IF((COUNTA(E8:E12)-COUNT(E8:E12))=0, SUM(E8:E12),"N/A")

Both conditions 1 and 2 are met with this formula, BUT, however, if one
of
the values is N/A, for example B=N/A, the result shows N/A instead of
summing
the other values. Like for conditions 4, 5, and 6, the results are N/A
which
suppose to showing the sum. Is there a forumla where all conditions can
be
true?

Thank you so much for you effort.

"akphidelt" wrote:

This is untested but you could try using count and counta to determine
if
there is any text in the series. For instance the formula might be

=IF((COUNTA(A1:C1)-COUNT(A1:C1))=0,SUM(A1:C1),"NA")

Basically count, counts all numerical values. Counta counts everything

"Kaylen" wrote:

For example:
addition formula: A+B+C=D
Condition 1: If A=B=C=N/A, shows N/A since all = N/A
Condition 2: If A=B=C=0, the shows 0 since 0+0+0+0+0=0
Condition 3: If A=0, B=0, C=0, but D= N/A, shows 0 since A+B+C=0
Condition 4: If A=N/A, B=N/A, C=N/A, but C=0, shows 0
Condition 5: If A=4, B=4, C=4, D=N/A, shows 12 since 4+4+4=12
Condition 6: If A= 4, B=4, C= 0, D=N/A, shows 8 since 4+4+0=8
Etc...

Problem:
If example formula is =SUM(E8:E12), then if all(E8 to E12) are N/A
then
it
shows 0( I want it to show N/A if all is N/A) --- only condition 2
is
met

If example formula is =IF(SUM(D8:D12)=0,"N/A",SUM(D8:D12)) then when
all is
0, it shows N/A( I want it to shows 0 if all is 0)----only condition
1
is met

I am looking for a formula where all conditions can be true.

Any help is greatly appreciated!!









Kaylen

Addition formulas problem
 
You are a genius! The first formula works beautifully!

"Sandy Mann" wrote:

Try:

=IF(COUNTIF(E18:E22,"N/A")+(E14="N/A")=COUNTA(E18:E22,E14),"N/A",SUM(E18:E22,E14))

This returns N/A for all empty cell then try:

=IF((COUNTA(E18:E22)=0)+(E14="")=2,"",IF(COUNTIF(E 18:E22,"N/A")+(E14="N/A")=COUNTA(E18:E22,E14),"N/A",SUM(E18:E22,E14)))

--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"Kaylen" wrote in message
...
I tried the formula with a range of cells and it works, but for the ones
that
involve a certain cell, I keep getting error message.

This is the formula I entered based on your suggestion:
=IF(COUNTIF(E18:E22,E14,"N/A")=COUNTA(E18:E22,E14),"N/A",SUM(E18:E22,E14))

I get an error message saying that the formula has too many aruguments.
Can
this forumla be fixed?

"Sandy Mann" wrote:

I understand your conditions to be if all entries, (which may not be all
five cells), are N/A then return N/A otherwise return the SUM() of
E8:E12,
if so then try:

=IF(COUNTIF(E8:E12,"n/a")=COUNTA(E8:E12),"N/A",SUM(E8:E12))

--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"Kaylen" wrote in message
...
Based on your suggestion, this is the formula:
=IF((COUNTA(E8:E12)-COUNT(E8:E12))=0, SUM(E8:E12),"N/A")

Both conditions 1 and 2 are met with this formula, BUT, however, if one
of
the values is N/A, for example B=N/A, the result shows N/A instead of
summing
the other values. Like for conditions 4, 5, and 6, the results are N/A
which
suppose to showing the sum. Is there a forumla where all conditions can
be
true?

Thank you so much for you effort.

"akphidelt" wrote:

This is untested but you could try using count and counta to determine
if
there is any text in the series. For instance the formula might be

=IF((COUNTA(A1:C1)-COUNT(A1:C1))=0,SUM(A1:C1),"NA")

Basically count, counts all numerical values. Counta counts everything

"Kaylen" wrote:

For example:
addition formula: A+B+C=D
Condition 1: If A=B=C=N/A, shows N/A since all = N/A
Condition 2: If A=B=C=0, the shows 0 since 0+0+0+0+0=0
Condition 3: If A=0, B=0, C=0, but D= N/A, shows 0 since A+B+C=0
Condition 4: If A=N/A, B=N/A, C=N/A, but C=0, shows 0
Condition 5: If A=4, B=4, C=4, D=N/A, shows 12 since 4+4+4=12
Condition 6: If A= 4, B=4, C= 0, D=N/A, shows 8 since 4+4+0=8
Etc...

Problem:
If example formula is =SUM(E8:E12), then if all(E8 to E12) are N/A
then
it
shows 0( I want it to show N/A if all is N/A) --- only condition 2
is
met

If example formula is =IF(SUM(D8:D12)=0,"N/A",SUM(D8:D12)) then when
all is
0, it shows N/A( I want it to shows 0 if all is 0)----only condition
1
is met

I am looking for a formula where all conditions can be true.

Any help is greatly appreciated!!










Sandy Mann

Addition formulas problem
 
Glad that we got there in the end.

--
Regards,

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"Kaylen" wrote in message
...
You are a genius! The first formula works beautifully!

"Sandy Mann" wrote:

Try:

=IF(COUNTIF(E18:E22,"N/A")+(E14="N/A")=COUNTA(E18:E22,E14),"N/A",SUM(E18:E22,E14))

This returns N/A for all empty cell then try:

=IF((COUNTA(E18:E22)=0)+(E14="")=2,"",IF(COUNTIF(E 18:E22,"N/A")+(E14="N/A")=COUNTA(E18:E22,E14),"N/A",SUM(E18:E22,E14)))

--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"Kaylen" wrote in message
...
I tried the formula with a range of cells and it works, but for the ones
that
involve a certain cell, I keep getting error message.

This is the formula I entered based on your suggestion:
=IF(COUNTIF(E18:E22,E14,"N/A")=COUNTA(E18:E22,E14),"N/A",SUM(E18:E22,E14))

I get an error message saying that the formula has too many aruguments.
Can
this forumla be fixed?

"Sandy Mann" wrote:

I understand your conditions to be if all entries, (which may not be
all
five cells), are N/A then return N/A otherwise return the SUM() of
E8:E12,
if so then try:

=IF(COUNTIF(E8:E12,"n/a")=COUNTA(E8:E12),"N/A",SUM(E8:E12))

--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"Kaylen" wrote in message
...
Based on your suggestion, this is the formula:
=IF((COUNTA(E8:E12)-COUNT(E8:E12))=0, SUM(E8:E12),"N/A")

Both conditions 1 and 2 are met with this formula, BUT, however, if
one
of
the values is N/A, for example B=N/A, the result shows N/A instead
of
summing
the other values. Like for conditions 4, 5, and 6, the results are
N/A
which
suppose to showing the sum. Is there a forumla where all conditions
can
be
true?

Thank you so much for you effort.

"akphidelt" wrote:

This is untested but you could try using count and counta to
determine
if
there is any text in the series. For instance the formula might be

=IF((COUNTA(A1:C1)-COUNT(A1:C1))=0,SUM(A1:C1),"NA")

Basically count, counts all numerical values. Counta counts
everything

"Kaylen" wrote:

For example:
addition formula: A+B+C=D
Condition 1: If A=B=C=N/A, shows N/A since all = N/A
Condition 2: If A=B=C=0, the shows 0 since 0+0+0+0+0=0
Condition 3: If A=0, B=0, C=0, but D= N/A, shows 0 since A+B+C=0
Condition 4: If A=N/A, B=N/A, C=N/A, but C=0, shows 0
Condition 5: If A=4, B=4, C=4, D=N/A, shows 12 since 4+4+4=12
Condition 6: If A= 4, B=4, C= 0, D=N/A, shows 8 since 4+4+0=8
Etc...

Problem:
If example formula is =SUM(E8:E12), then if all(E8 to E12) are
N/A
then
it
shows 0( I want it to show N/A if all is N/A) --- only condition
2
is
met

If example formula is =IF(SUM(D8:D12)=0,"N/A",SUM(D8:D12)) then
when
all is
0, it shows N/A( I want it to shows 0 if all is 0)----only
condition
1
is met

I am looking for a formula where all conditions can be true.

Any help is greatly appreciated!!













Kaylen

Addition formulas problem
 
I'm sorry but there is an error message saying too many arguments again when
I tried this formula:

=IF(COUNTIF(E31="N/A")+(E34="N/A")+(E37="N/A")+(E40="N/A")=COUNTA(E31,E34,E37,E40),"N/A",SUM(E31,E34,E37,E40))

Can it fixed?

"Sandy Mann" wrote:

Try:

=IF(COUNTIF(E18:E22,"N/A")+(E14="N/A")=COUNTA(E18:E22,E14),"N/A",SUM(E18:E22,E14))

This returns N/A for all empty cell then try:

=IF((COUNTA(E18:E22)=0)+(E14="")=2,"",IF(COUNTIF(E 18:E22,"N/A")+(E14="N/A")=COUNTA(E18:E22,E14),"N/A",SUM(E18:E22,E14)))

--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"Kaylen" wrote in message
...
I tried the formula with a range of cells and it works, but for the ones
that
involve a certain cell, I keep getting error message.

This is the formula I entered based on your suggestion:
=IF(COUNTIF(E18:E22,E14,"N/A")=COUNTA(E18:E22,E14),"N/A",SUM(E18:E22,E14))

I get an error message saying that the formula has too many aruguments.
Can
this forumla be fixed?

"Sandy Mann" wrote:

I understand your conditions to be if all entries, (which may not be all
five cells), are N/A then return N/A otherwise return the SUM() of
E8:E12,
if so then try:

=IF(COUNTIF(E8:E12,"n/a")=COUNTA(E8:E12),"N/A",SUM(E8:E12))

--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"Kaylen" wrote in message
...
Based on your suggestion, this is the formula:
=IF((COUNTA(E8:E12)-COUNT(E8:E12))=0, SUM(E8:E12),"N/A")

Both conditions 1 and 2 are met with this formula, BUT, however, if one
of
the values is N/A, for example B=N/A, the result shows N/A instead of
summing
the other values. Like for conditions 4, 5, and 6, the results are N/A
which
suppose to showing the sum. Is there a forumla where all conditions can
be
true?

Thank you so much for you effort.

"akphidelt" wrote:

This is untested but you could try using count and counta to determine
if
there is any text in the series. For instance the formula might be

=IF((COUNTA(A1:C1)-COUNT(A1:C1))=0,SUM(A1:C1),"NA")

Basically count, counts all numerical values. Counta counts everything

"Kaylen" wrote:

For example:
addition formula: A+B+C=D
Condition 1: If A=B=C=N/A, shows N/A since all = N/A
Condition 2: If A=B=C=0, the shows 0 since 0+0+0+0+0=0
Condition 3: If A=0, B=0, C=0, but D= N/A, shows 0 since A+B+C=0
Condition 4: If A=N/A, B=N/A, C=N/A, but C=0, shows 0
Condition 5: If A=4, B=4, C=4, D=N/A, shows 12 since 4+4+4=12
Condition 6: If A= 4, B=4, C= 0, D=N/A, shows 8 since 4+4+0=8
Etc...

Problem:
If example formula is =SUM(E8:E12), then if all(E8 to E12) are N/A
then
it
shows 0( I want it to show N/A if all is N/A) --- only condition 2
is
met

If example formula is =IF(SUM(D8:D12)=0,"N/A",SUM(D8:D12)) then when
all is
0, it shows N/A( I want it to shows 0 if all is 0)----only condition
1
is met

I am looking for a formula where all conditions can be true.

Any help is greatly appreciated!!










Sandy Mann[_2_]

Addition formulas problem
 
My ISP has stopped reading Newsgroups at the moment for some reason so I am
having to post through the Communities site.

COUNTIF() only takes one range in its first argument. Take the COUNTIF()
out and you have:

=IF((E31="N/A")+(E34="N/A")+(E37="N/A")+(E40="N/A")=COUNTA(E31,E34,E37,E40),"N/A",SUM(E31,E34,E37,E40))

The four comparisons, (E31="N/A") etc., return TRUE or FALSE which when
added up with the + sign, XL changes into 1 or 0. This sum is then compared
with the COUNTA() return.

"Kaylen" wrote:

I'm sorry but there is an error message saying too many arguments again when
I tried this formula:

=IF(COUNTIF(E31="N/A")+(E34="N/A")+(E37="N/A")+(E40="N/A")=COUNTA(E31,E34,E37,E40),"N/A",SUM(E31,E34,E37,E40))

Can it fixed?

"Sandy Mann" wrote:

Try:

=IF(COUNTIF(E18:E22,"N/A")+(E14="N/A")=COUNTA(E18:E22,E14),"N/A",SUM(E18:E22,E14))

This returns N/A for all empty cell then try:

=IF((COUNTA(E18:E22)=0)+(E14="")=2,"",IF(COUNTIF(E 18:E22,"N/A")+(E14="N/A")=COUNTA(E18:E22,E14),"N/A",SUM(E18:E22,E14)))

--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"Kaylen" wrote in message
...
I tried the formula with a range of cells and it works, but for the ones
that
involve a certain cell, I keep getting error message.

This is the formula I entered based on your suggestion:
=IF(COUNTIF(E18:E22,E14,"N/A")=COUNTA(E18:E22,E14),"N/A",SUM(E18:E22,E14))

I get an error message saying that the formula has too many aruguments.
Can
this forumla be fixed?

"Sandy Mann" wrote:

I understand your conditions to be if all entries, (which may not be all
five cells), are N/A then return N/A otherwise return the SUM() of
E8:E12,
if so then try:

=IF(COUNTIF(E8:E12,"n/a")=COUNTA(E8:E12),"N/A",SUM(E8:E12))

--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"Kaylen" wrote in message
...
Based on your suggestion, this is the formula:
=IF((COUNTA(E8:E12)-COUNT(E8:E12))=0, SUM(E8:E12),"N/A")

Both conditions 1 and 2 are met with this formula, BUT, however, if one
of
the values is N/A, for example B=N/A, the result shows N/A instead of
summing
the other values. Like for conditions 4, 5, and 6, the results are N/A
which
suppose to showing the sum. Is there a forumla where all conditions can
be
true?

Thank you so much for you effort.

"akphidelt" wrote:

This is untested but you could try using count and counta to determine
if
there is any text in the series. For instance the formula might be

=IF((COUNTA(A1:C1)-COUNT(A1:C1))=0,SUM(A1:C1),"NA")

Basically count, counts all numerical values. Counta counts everything

"Kaylen" wrote:

For example:
addition formula: A+B+C=D
Condition 1: If A=B=C=N/A, shows N/A since all = N/A
Condition 2: If A=B=C=0, the shows 0 since 0+0+0+0+0=0
Condition 3: If A=0, B=0, C=0, but D= N/A, shows 0 since A+B+C=0
Condition 4: If A=N/A, B=N/A, C=N/A, but C=0, shows 0
Condition 5: If A=4, B=4, C=4, D=N/A, shows 12 since 4+4+4=12
Condition 6: If A= 4, B=4, C= 0, D=N/A, shows 8 since 4+4+0=8
Etc...

Problem:
If example formula is =SUM(E8:E12), then if all(E8 to E12) are N/A
then
it
shows 0( I want it to show N/A if all is N/A) --- only condition 2
is
met

If example formula is =IF(SUM(D8:D12)=0,"N/A",SUM(D8:D12)) then when
all is
0, it shows N/A( I want it to shows 0 if all is 0)----only condition
1
is met

I am looking for a formula where all conditions can be true.

Any help is greatly appreciated!!










Kaylen

Addition formulas problem
 
You are brilliant! Thank you so much!

"Sandy Mann" wrote:

My ISP has stopped reading Newsgroups at the moment for some reason so I am
having to post through the Communities site.

COUNTIF() only takes one range in its first argument. Take the COUNTIF()
out and you have:

=IF((E31="N/A")+(E34="N/A")+(E37="N/A")+(E40="N/A")=COUNTA(E31,E34,E37,E40),"N/A",SUM(E31,E34,E37,E40))

The four comparisons, (E31="N/A") etc., return TRUE or FALSE which when
added up with the + sign, XL changes into 1 or 0. This sum is then compared
with the COUNTA() return.

"Kaylen" wrote:

I'm sorry but there is an error message saying too many arguments again when
I tried this formula:

=IF(COUNTIF(E31="N/A")+(E34="N/A")+(E37="N/A")+(E40="N/A")=COUNTA(E31,E34,E37,E40),"N/A",SUM(E31,E34,E37,E40))

Can it fixed?

"Sandy Mann" wrote:

Try:

=IF(COUNTIF(E18:E22,"N/A")+(E14="N/A")=COUNTA(E18:E22,E14),"N/A",SUM(E18:E22,E14))

This returns N/A for all empty cell then try:

=IF((COUNTA(E18:E22)=0)+(E14="")=2,"",IF(COUNTIF(E 18:E22,"N/A")+(E14="N/A")=COUNTA(E18:E22,E14),"N/A",SUM(E18:E22,E14)))

--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"Kaylen" wrote in message
...
I tried the formula with a range of cells and it works, but for the ones
that
involve a certain cell, I keep getting error message.

This is the formula I entered based on your suggestion:
=IF(COUNTIF(E18:E22,E14,"N/A")=COUNTA(E18:E22,E14),"N/A",SUM(E18:E22,E14))

I get an error message saying that the formula has too many aruguments.
Can
this forumla be fixed?

"Sandy Mann" wrote:

I understand your conditions to be if all entries, (which may not be all
five cells), are N/A then return N/A otherwise return the SUM() of
E8:E12,
if so then try:

=IF(COUNTIF(E8:E12,"n/a")=COUNTA(E8:E12),"N/A",SUM(E8:E12))

--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"Kaylen" wrote in message
...
Based on your suggestion, this is the formula:
=IF((COUNTA(E8:E12)-COUNT(E8:E12))=0, SUM(E8:E12),"N/A")

Both conditions 1 and 2 are met with this formula, BUT, however, if one
of
the values is N/A, for example B=N/A, the result shows N/A instead of
summing
the other values. Like for conditions 4, 5, and 6, the results are N/A
which
suppose to showing the sum. Is there a forumla where all conditions can
be
true?

Thank you so much for you effort.

"akphidelt" wrote:

This is untested but you could try using count and counta to determine
if
there is any text in the series. For instance the formula might be

=IF((COUNTA(A1:C1)-COUNT(A1:C1))=0,SUM(A1:C1),"NA")

Basically count, counts all numerical values. Counta counts everything

"Kaylen" wrote:

For example:
addition formula: A+B+C=D
Condition 1: If A=B=C=N/A, shows N/A since all = N/A
Condition 2: If A=B=C=0, the shows 0 since 0+0+0+0+0=0
Condition 3: If A=0, B=0, C=0, but D= N/A, shows 0 since A+B+C=0
Condition 4: If A=N/A, B=N/A, C=N/A, but C=0, shows 0
Condition 5: If A=4, B=4, C=4, D=N/A, shows 12 since 4+4+4=12
Condition 6: If A= 4, B=4, C= 0, D=N/A, shows 8 since 4+4+0=8
Etc...

Problem:
If example formula is =SUM(E8:E12), then if all(E8 to E12) are N/A
then
it
shows 0( I want it to show N/A if all is N/A) --- only condition 2
is
met

If example formula is =IF(SUM(D8:D12)=0,"N/A",SUM(D8:D12)) then when
all is
0, it shows N/A( I want it to shows 0 if all is 0)----only condition
1
is met

I am looking for a formula where all conditions can be true.

Any help is greatly appreciated!!











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