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Jay Jay is offline
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Default difference in time


I have 2 times : 16:20 and 01:02
Trying to find the difference in hours between these times.

Used this formula : =(((HOUR(H135-I135)-24)*60)+MINUTE(H135-I135))/60

However the difference comes up as a negetive numbe. I understand the 24
hour clock peice and why this is happening.

Is there a way to return the correct number as a positive value of hours
between these 2 times?

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Default difference in time

In article , ?B?SmF5?= wrote:

I have 2 times : 16:20 and 01:02
Trying to find the difference in hours between these times.

Used this formula : =(((HOUR(H135-I135)-24)*60)+MINUTE(H135-I135))/60

However the difference comes up as a negetive numbe. I understand the 24
hour clock peice and why this is happening.

Is there a way to return the correct number as a positive value of hours
between these 2 times?


Suggest using dates/times. I suspect the negative number you are getting is
right (as you are subtracting 16:20 from 02:02 ?) ... but what you are
trying to do is get the hours from 16:20 to 01:02 *the next day* ??
Remember that standard dates and times are just numbers in XL ... it's all
in the formatting as to what you see. :)

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Default difference in time

If you want to find the time difference between 16:20 one day and 01:02 the
next day, you might try =MOD(I135-H135,1) and format as [hh]:mm, or if you
want a number of hours in decimal use =MOD(I135-H135,1)*24 and format as
number or general, not time.
--
David Biddulph

"Jay" wrote in message
...

I have 2 times : 16:20 and 01:02
Trying to find the difference in hours between these times.

Used this formula : =(((HOUR(H135-I135)-24)*60)+MINUTE(H135-I135))/60

However the difference comes up as a negetive numbe. I understand the 24
hour clock peice and why this is happening.

Is there a way to return the correct number as a positive value of hours
between these 2 times?



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