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Find and remove data from a column
I have a column of data that is very long. About ever 10 to 15 rows
the column says Parent Sheet 123456 (a six digit random number) then measurements like 23 X 35. Sometimes the measurements will be 23 1/8 X 36 1/4. Is there a way to go through the coloumn and find Parent Sheet and then remove the Measurements and put them in another column? Column K is where Parent Sheet will be found and the next available column is P. Formula or code will work for me. Thanks in advance, Jay |
Find and remove data from a column
Try this in P1:
=IF(LEFT(K1,12)="Parent Sheet",RIGHT(K1,LEN(K1)-19),"") Copy this down the column. Hope this helps. Pete On May 21, 1:16*am, jlclyde wrote: I have a column of data that is very long. *About ever 10 to 15 rows the column says Parent Sheet 123456 (a six digit random number) then measurements like 23 X 35. *Sometimes the measurements will be 23 1/8 X 36 1/4. *Is there a way to go through the coloumn and find Parent Sheet and then remove the Measurements and put them in another column? *Column K is where Parent Sheet will be found and the next available column is P. *Formula or code will work for me. Thanks in advance, Jay |
Find and remove data from a column
On May 20, 7:48*pm, Pete_UK wrote:
Try this in P1: =IF(LEFT(K1,12)="Parent Sheet",RIGHT(K1,LEN(K1)-19),"") Copy this down the column. Hope this helps. Pete On May 21, 1:16*am, jlclyde wrote: I have a column of data that is very long. *About ever 10 to 15 rows the column says Parent Sheet 123456 (a six digit random number) then measurements like 23 X 35. *Sometimes the measurements will be 23 1/8 X 36 1/4. *Is there a way to go through the coloumn and find Parent Sheet and then remove the Measurements and put them in another column? *Column K is where Parent Sheet will be found and the next available column is P. *Formula or code will work for me. Thanks in advance, Jay- Hide quoted text - - Show quoted text - Pete, I had to subtract more from the Len, but this works great. Thanks, Jay |
Find and remove data from a column
You're welcome, Jay - thanks for feeding back.
Pete On May 21, 1:58*am, jlclyde wrote: Pete, I had to subtract more from the Len, but this works great. Thanks, Jay |
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