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I have a big PivotTable of sales of specific products against
salespeople. Product Salesperson1 Salesperson2 product1 1 5 product2 0 11 product3 6 2 product4 3 6 Salespeople are paid a bonus if sales are in multiples of 5 - they get no bonus for selling 0-4 units. A 5 euro bonus for selling 5, 6, 7, 8 or 9 units. Then 10 euro for shifting 10, 11, 12, 13, or 14. Then a 15 euro bonus, etc. So in the above examples, Salesperson1 would get 5 euro total. Salesperson2 would get 20. I can copy out the pivot results to another sheet and insert a column for each salesperson that runs a CEILING formula against each adjacent cell. Then sum the ceiling column for each salesperson, getting their total bonus. This works fine. I also ran a VLOOKUP, which worked a-ok too. But there are a lot of columns to insert. What single cell formula would I enter underneath each salesperson's column that could calculate their total bonus? Joe. |
#2
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=5*int(sum(b2:b6)/5)
-- Wag more, bark less "Joe Murphy" wrote: I have a big PivotTable of sales of specific products against salespeople. Product Salesperson1 Salesperson2 product1 1 5 product2 0 11 product3 6 2 product4 3 6 Salespeople are paid a bonus if sales are in multiples of 5 - they get no bonus for selling 0-4 units. A 5 euro bonus for selling 5, 6, 7, 8 or 9 units. Then 10 euro for shifting 10, 11, 12, 13, or 14. Then a 15 euro bonus, etc. So in the above examples, Salesperson1 would get 5 euro total. Salesperson2 would get 20. I can copy out the pivot results to another sheet and insert a column for each salesperson that runs a CEILING formula against each adjacent cell. Then sum the ceiling column for each salesperson, getting their total bonus. This works fine. I also ran a VLOOKUP, which worked a-ok too. But there are a lot of columns to insert. What single cell formula would I enter underneath each salesperson's column that could calculate their total bonus? Joe. |
#3
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On May 9, 2:47*pm, Brad wrote:
=5*int(sum(b2:b6)/5) That's not it, alas. I could have been clearer in my example. It's not the multiples of 5 that create the bonus, it's multiples of 5 _of each product_ that get the bonus. So for Salesperson1, he doesn't get a 10 euro bonus for shifting 10 units total. He gets a 5 euro bonus for shifting 6 units of one product, and the rest are ignored. Salesperson2 gets a 5+10+0+5=20 euro. Joe. |
#4
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=SUMPRODUCT(5*INT(C3:C6/5))
This should do it. -- Wag more, bark less "Joe Murphy" wrote: On May 9, 2:47 pm, Brad wrote: =5*int(sum(b2:b6)/5) That's not it, alas. I could have been clearer in my example. It's not the multiples of 5 that create the bonus, it's multiples of 5 _of each product_ that get the bonus. So for Salesperson1, he doesn't get a 10 euro bonus for shifting 10 units total. He gets a 5 euro bonus for shifting 6 units of one product, and the rest are ignored. Salesperson2 gets a 5+10+0+5=20 euro. Joe. |
#5
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On May 9, 3:21*pm, Brad wrote:
=SUMPRODUCT(5*INT(C3:C6/5)) This should do it. * It totally did. You're a star. (and man, I have to go read about SUMPRODUCT) Joe. |
#6
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You're welcome
Would you please click the button that says that the response answered the question. I would appreciate it. -- Wag more, bark less "Joe Murphy" wrote: On May 9, 3:21 pm, Brad wrote: =SUMPRODUCT(5*INT(C3:C6/5)) This should do it. It totally did. You're a star. (and man, I have to go read about SUMPRODUCT) Joe. |
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