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=IF(A1=B1,TRUE,FALSE), easy enough, but how about A1 being within .5 of B1?
In other words if B1=5, the statement would be true if A1=anywhere from 4.5 - 5.5. is there a way to write this formula? Thanks! M.A.Tyler |
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Try this:
=ABS(+B1-A1)<=0.5 Does that help? Post back if you have more questions. -------------------------- Regards, Ron Microsoft MVP (Excel) (XL2003, Win XP) "M.A.Tyler" <Great Lakes State wrote in message ... =IF(A1=B1,TRUE,FALSE), easy enough, but how about A1 being within .5 of B1? In other words if B1=5, the statement would be true if A1=anywhere from 4.5 - 5.5. is there a way to write this formula? Thanks! M.A.Tyler |
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One way:
=AND(A1=B1-.5,A1<=B1+.5) Tyro "M.A.Tyler" <Great Lakes State wrote in message ... =IF(A1=B1,TRUE,FALSE), easy enough, but how about A1 being within .5 of B1? In other words if B1=5, the statement would be true if A1=anywhere from 4.5 - 5.5. is there a way to write this formula? Thanks! M.A.Tyler |
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Try this:
=IF(ABS(B1)-ABS(A1)<=0.5,TRUE,FALSE) or even: =(ABS(B1)-ABS(A1))<=0.5 Hope this helps. Pete On Feb 6, 1:36*am, M.A.Tyler <Great Lakes State wrote: =IF(A1=B1,TRUE,FALSE), easy enough, but how about A1 being within .5 of B1? In other words if B1=5, the statement would be true if A1=anywhere from 4.5 - 5.5. is there a way to write this formula? Thanks! M.A.Tyler |
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All good, thanks as always!
"Pete_UK" wrote: Try this: =IF(ABS(B1)-ABS(A1)<=0.5,TRUE,FALSE) or even: =(ABS(B1)-ABS(A1))<=0.5 Hope this helps. Pete On Feb 6, 1:36 am, M.A.Tyler <Great Lakes State wrote: =IF(A1=B1,TRUE,FALSE), easy enough, but how about A1 being within .5 of B1? In other words if B1=5, the statement would be true if A1=anywhere from 4.5 - 5.5. is there a way to write this formula? Thanks! M.A.Tyler |
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No, Pete, because that would return true for any value of A1 <=-4.5 or
=+4.5 rather than for values between +4.5 and +5.5 You ned to change (ABS(B1)-ABS(A1)) to (ABS(B1-A1)) -- David Biddulph "Pete_UK" wrote in message ... Try this: =IF(ABS(B1)-ABS(A1)<=0.5,TRUE,FALSE) or even: =(ABS(B1)-ABS(A1))<=0.5 Hope this helps. Pete On Feb 6, 1:36 am, M.A.Tyler <Great Lakes State wrote: =IF(A1=B1,TRUE,FALSE), easy enough, but how about A1 being within .5 of B1? In other words if B1=5, the statement would be true if A1=anywhere from 4.5 - 5.5. is there a way to write this formula? Thanks! M.A.Tyler |
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Right, David, thanks.
I thought I was checking for the difference of the magnitures, but have now re-read the OP's request - that always helps !! <bg Pete On Feb 6, 8:16*am, "David Biddulph" <groups [at] biddulph.org.uk wrote: No, Pete, because that would return true for any value of A1 <=-4.5 or *=+4.5 rather than for values between +4.5 and +5.5 You ned to change (ABS(B1)-ABS(A1)) to (ABS(B1-A1)) -- David Biddulph "Pete_UK" wrote in message ... Try this: =IF(ABS(B1)-ABS(A1)<=0.5,TRUE,FALSE) or even: =(ABS(B1)-ABS(A1))<=0.5 Hope this helps. Pete On Feb 6, 1:36 am, M.A.Tyler <Great Lakes State wrote: =IF(A1=B1,TRUE,FALSE), easy enough, but how about A1 being within .5 of B1? In other words if B1=5, the statement would be true if A1=anywhere from 4.5 - 5.5. is there a way to write this formula? Thanks! M.A.Tyler- Hide quoted text - - Show quoted text - |
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