count different instances in a list
I have a list that has aaa, bbb, cccc, aaa, bbb and want to count the
different instances. So in this example it would be 3 because bbb is repeated. Is there a formula that does this? |
count different instances in a list
mmatz,
Assuming that your list is in cells A1:A5, if you put this formula in A7, it should accomplish what you desi =countif(A1:A5,"bbb") HTH, Conan "mmatz" wrote in message ... I have a list that has aaa, bbb, cccc, aaa, bbb and want to count the different instances. So in this example it would be 3 because bbb is repeated. Is there a formula that does this? |
count different instances in a list
This one is an array formula and need to be committed with Shift+Ctrl+Enter
=SUM(1/COUNTIF(C1:C6,C1:C6)) This is committed with just Enter =SUMPRODUCT(--(C1:C6<""),1/COUNTIF(C1:C6,C1:C6&"")) Of course, change C1:C6 to fit your situation best wishes -- Bernard V Liengme Microsoft Excel MVP www.stfx.ca/people/bliengme remove caps from email "mmatz" wrote in message ... I have a list that has aaa, bbb, cccc, aaa, bbb and want to count the different instances. So in this example it would be 3 because bbb is repeated. Is there a formula that does this? |
Quote:
=SUMPRODUCT((A1:A10<"")/COUNTIF(A1:A10,A1:A10&"")) where A1:A10 contain your data to count. |
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