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#1
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Does anyone have any suggestions on how to count the match letter within
string? such as "RRRRR" in cell A1, then return the number of "R" in cell B1, which is 5. Does anyone have any suggestions? Eric |
#2
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With
A1: RRRR123RR This formula returns the count of R's in A1 B1: =LEN(A1)-LEN(SUBSTITUTE(A1,"R","")) In this instance, B1 returns 6 Is that something you can work with? *********** Regards, Ron XL2003, WinXP "Eric" wrote: Does anyone have any suggestions on how to count the match letter within string? such as "RRRRR" in cell A1, then return the number of "R" in cell B1, which is 5. Does anyone have any suggestions? Eric |
#3
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On Tue, 21 Aug 2007 18:32:05 -0700, Eric
wrote: Does anyone have any suggestions on how to count the match letter within string? such as "RRRRR" in cell A1, then return the number of "R" in cell B1, which is 5. Does anyone have any suggestions? Eric =LEN(A1)-LEN(SUBSTITUTE(A1,"R","")) You can use a cell reference containing your match_letter in place of the "R" in the above example. --ron |
#4
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Try this:
=LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),"R","")) Note: SUBSTITUTE is case sensitive so the "R" needs to be in uppercase. =LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),"R","")) = 5 =LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),"r","")) = 0 -- Biff Microsoft Excel MVP "Eric" wrote in message ... Does anyone have any suggestions on how to count the match letter within string? such as "RRRRR" in cell A1, then return the number of "R" in cell B1, which is 5. Does anyone have any suggestions? Eric |
#5
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Thank you very much for suggestions
Eric "Ron Coderre" wrote: With A1: RRRR123RR This formula returns the count of R's in A1 B1: =LEN(A1)-LEN(SUBSTITUTE(A1,"R","")) In this instance, B1 returns 6 Is that something you can work with? *********** Regards, Ron XL2003, WinXP "Eric" wrote: Does anyone have any suggestions on how to count the match letter within string? such as "RRRRR" in cell A1, then return the number of "R" in cell B1, which is 5. Does anyone have any suggestions? Eric |
#6
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I'm glad you could work with that......thanks for the feedback.
*********** Regards, Ron XL2003, WinXP "Eric" wrote: Thank you very much for suggestions Eric "Ron Coderre" wrote: With A1: RRRR123RR This formula returns the count of R's in A1 B1: =LEN(A1)-LEN(SUBSTITUTE(A1,"R","")) In this instance, B1 returns 6 Is that something you can work with? *********** Regards, Ron XL2003, WinXP "Eric" wrote: Does anyone have any suggestions on how to count the match letter within string? such as "RRRRR" in cell A1, then return the number of "R" in cell B1, which is 5. Does anyone have any suggestions? Eric |
#7
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To solve for its being case sensitive, use UPPER at both
=LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),UPPER("r"),"")) "T. Valko" wrote: Try this: =LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),"R","")) Note: SUBSTITUTE is case sensitive so the "R" needs to be in uppercase. =LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),"R","")) = 5 =LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),"r","")) = 0 -- Biff Microsoft Excel MVP "Eric" wrote in message ... Does anyone have any suggestions on how to count the match letter within string? such as "RRRRR" in cell A1, then return the number of "R" in cell B1, which is 5. Does anyone have any suggestions? Eric |
#8
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You could do that but if you know the letter needs to be in uppercase why
use UPPER("r") when you can just use "R"? To make it foolproof it would be better to use a cell to hold the letter then: =LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),UPPER(A2),"")) Where A2 = R or r -- Biff Microsoft Excel MVP "Tevuna" wrote in message ... To solve for its being case sensitive, use UPPER at both =LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),UPPER("r"),"")) "T. Valko" wrote: Try this: =LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),"R","")) Note: SUBSTITUTE is case sensitive so the "R" needs to be in uppercase. =LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),"R","")) = 5 =LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),"r","")) = 0 -- Biff Microsoft Excel MVP "Eric" wrote in message ... Does anyone have any suggestions on how to count the match letter within string? such as "RRRRR" in cell A1, then return the number of "R" in cell B1, which is 5. Does anyone have any suggestions? Eric |
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