![]() |
Counting differing items
Hi Folks
In a column I have three possible values, A, B or C. I'd like to be able to construct formulas which count the number of times each value occurs, so that I could then have three cells showing total occurances of A, total occurances of B and total occurances of C. I've tried to get COUNTA to do this, but without success. TIA DC |
Counting differing items
The solution is to use the Countif function
e.g.=countif(A1:A100,"A") Hope this is helpful "Django Cat" wrote: Hi Folks In a column I have three possible values, A, B or C. I'd like to be able to construct formulas which count the number of times each value occurs, so that I could then have three cells showing total occurances of A, total occurances of B and total occurances of C. I've tried to get COUNTA to do this, but without success. TIA DC |
Counting differing items
Brilliant! Thanks Art, that works perfectly.
DC On 25 May, 16:28, Art Caragh wrote: The solution is to use the Countif function e.g.=countif(A1:A100,"A") Hope this is helpful "Django Cat" wrote: Hi Folks In a column I have three possible values, A, B or C. I'd like to be able to construct formulas which count the number of times each value occurs, so that I could then have three cells showing total occurances of A, total occurances of B and total occurances of C. I've tried to get COUNTA to do this, but without success. TIA DC- Hide quoted text - - Show quoted text - |
All times are GMT +1. The time now is 01:42 AM. |
Powered by vBulletin® Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
ExcelBanter.com