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#1
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I need to be able to count how many entries are separated by commas. For
instance, in cell A2, I have: AB1, AB2, AB3, AB4. In cell B2, I want to display the number 4 because there are 4 values. So if I have AXX2, Ax3, A3TU0 In cell B2, I want to display the number 3 because there are 3 values. Is there a way to do this? Thanks in advance. |
#2
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Try something like this:
=LEN(B2)-LEN(SUBSTITUTE(B2,",",""))+1 Does that help? *********** Regards, Ron XL2002, WinXP "jhicsupt" wrote: I need to be able to count how many entries are separated by commas. For instance, in cell A2, I have: AB1, AB2, AB3, AB4. In cell B2, I want to display the number 4 because there are 4 values. So if I have AXX2, Ax3, A3TU0 In cell B2, I want to display the number 3 because there are 3 values. Is there a way to do this? Thanks in advance. |
#3
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B2 should be A2 ?
"Ron Coderre" schreef in bericht ... Try something like this: =LEN(B2)-LEN(SUBSTITUTE(B2,",",""))+1 Does that help? *********** Regards, Ron XL2002, WinXP "jhicsupt" wrote: I need to be able to count how many entries are separated by commas. For instance, in cell A2, I have: AB1, AB2, AB3, AB4. In cell B2, I want to display the number 4 because there are 4 values. So if I have AXX2, Ax3, A3TU0 In cell B2, I want to display the number 3 because there are 3 values. Is there a way to do this? Thanks in advance. |
#4
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Yes....In my testing I evidently transposed A2 and B2.
Thanks for catching that. *********** Regards, Ron XL2002, WinXP "Jack Sons" wrote: B2 should be A2 ? "Ron Coderre" schreef in bericht ... Try something like this: =LEN(B2)-LEN(SUBSTITUTE(B2,",",""))+1 Does that help? *********** Regards, Ron XL2002, WinXP "jhicsupt" wrote: I need to be able to count how many entries are separated by commas. For instance, in cell A2, I have: AB1, AB2, AB3, AB4. In cell B2, I want to display the number 4 because there are 4 values. So if I have AXX2, Ax3, A3TU0 In cell B2, I want to display the number 3 because there are 3 values. Is there a way to do this? Thanks in advance. |
#5
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A minor variation of Ron's suggestion:
=LEN(A2)-LEN(SUBSTITUTE(A2,",",""))+(A2<"") It may handle empty cells better. jhicsupt wrote: I need to be able to count how many entries are separated by commas. For instance, in cell A2, I have: AB1, AB2, AB3, AB4. In cell B2, I want to display the number 4 because there are 4 values. So if I have AXX2, Ax3, A3TU0 In cell B2, I want to display the number 3 because there are 3 values. Is there a way to do this? Thanks in advance. -- Dave Peterson |
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