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Creating Circles in an Excel Graph
I'm making a spreadsheet that shows the circumcenter of a triangle
with the 3 points as input from the user. I can get the circumcenter calculated no problem, but now I want to make 1 circle radiating from the point the user has input that will also cross the circumcenter point. Say the point the user enters is 1,1 and the circumcenter is a 2,2. I want a circle that's center is at 1,1 and crosses through point 2,2. Any ideas? |
Creating Circles in an Excel Graph
I used the drawing toolbar and added an oval. I did this while recording a
macro and got the following ActiveSheet.Shapes.AddShape(msoShapeOval, 390.75, 377.25, 72#, 72#).Select " wrote: I'm making a spreadsheet that shows the circumcenter of a triangle with the 3 points as input from the user. I can get the circumcenter calculated no problem, but now I want to make 1 circle radiating from the point the user has input that will also cross the circumcenter point. Say the point the user enters is 1,1 and the circumcenter is a 2,2. I want a circle that's center is at 1,1 and crosses through point 2,2. Any ideas? |
Creating Circles in an Excel Graph
You know all that you need to define the circle, its center and its radius
(square root of 2). Set up a worksheet range to input coordinates of the circle, which you will later plot. A2: =SQRT(2) B2: 1 C2: 1 A4: Angle B4: X C4: Y In A5 enter 0. in A6 enter 10, select A5:A6 and drag this down to fill down to A41 with values from 0 to 360. In B5, enter =$B$2+$A$2*SIN(A5*PI()/180), and in C5 enter =$C$2+$A$2*COS(A5*PI()/180). Select B5:C5 and double click the little square at the bottom right corner of the highlighting rectangle, which will fill these formulas down to row 40. Select A1:B2, create an XY chart, with series in columns. This gives you a point at (1,1). Copy B4:C41, select the chart, choose Paste Special from the Edit menu, and choose to add the data as a new series. This is the circle. - Jon ------- Jon Peltier, Microsoft Excel MVP Tutorials and Custom Solutions http://PeltierTech.com _______ wrote in message ups.com... I'm making a spreadsheet that shows the circumcenter of a triangle with the 3 points as input from the user. I can get the circumcenter calculated no problem, but now I want to make 1 circle radiating from the point the user has input that will also cross the circumcenter point. Say the point the user enters is 1,1 and the circumcenter is a 2,2. I want a circle that's center is at 1,1 and crosses through point 2,2. Any ideas? |
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