![]() |
IF statement query
All,
Trying to write a formula which returns a value depending on the value of another cell. So if d9 is less than 2500 then return 58, if between 2501 and 2900 then 60 and if 2900+ then 62. The best I have come up with is: =IF(OR(D9<2501,58),IF(D92501,60),IF(D92901,62)) which returns 60, even when d9 = 2910 obviously doing something wrong, but not sure what. any help would be appreciated. thanks |
IF statement query
try this idea where you start with the highest
=if(d92901,62,if(d92501,60,58)) -- Don Guillett SalesAid Software "shakey1181" wrote in message ... All, Trying to write a formula which returns a value depending on the value of another cell. So if d9 is less than 2500 then return 58, if between 2501 and 2900 then 60 and if 2900+ then 62. The best I have come up with is: =IF(OR(D9<2501,58),IF(D92501,60),IF(D92901,62)) which returns 60, even when d9 = 2910 obviously doing something wrong, but not sure what. any help would be appreciated. thanks |
IF statement query
Your words say 2500 is not determined,
And you formula says 2501 is no determined. Try this: =IF(D9<2501,58,IF(D9<2901,60,62)) And post back if you need a revision. -- HTH, RD ================================================== === Please keep all correspondence within the Group, so all may benefit! ================================================== === "shakey1181" wrote in message ... All, Trying to write a formula which returns a value depending on the value of another cell. So if d9 is less than 2500 then return 58, if between 2501 and 2900 then 60 and if 2900+ then 62. The best I have come up with is: =IF(OR(D9<2501,58),IF(D92501,60),IF(D92901,62)) which returns 60, even when d9 = 2910 obviously doing something wrong, but not sure what. any help would be appreciated. thanks |
All times are GMT +1. The time now is 04:38 AM. |
Powered by vBulletin® Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
ExcelBanter.com