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Sumproduct
Hi, I currently have a sumproduct formula layed out in the standard configuration: =SUMPRODUCT((array1=condition1)*(array2=condition2 )*(array3)) Is it possible to change the (array1=condition1) part so that it looks for more than one condition in that array, so that it is looking for condition1 OR condition1a? Thanks -- sanders ------------------------------------------------------------------------ sanders's Profile: http://www.excelforum.com/member.php...o&userid=36745 View this thread: http://www.excelforum.com/showthread...hreadid=569799 |
Sumproduct
An extensive description of how SUMPRODUCT can be used can be found he
http://www.xldynamic.com/source/xld.SUMPRODUCT.html -- Kind regards, Niek Otten Microsoft MVP - Excel "sanders" wrote in message ... | | Hi, | I currently have a sumproduct formula layed out in the standard | configuration: | | =SUMPRODUCT((array1=condition1)*(array2=condition2 )*(array3)) | | Is it possible to change the (array1=condition1) part so that it looks | for more than one condition in that array, so that it is looking for | condition1 OR condition1a? | | Thanks | | | -- | sanders | ------------------------------------------------------------------------ | sanders's Profile: http://www.excelforum.com/member.php...o&userid=36745 | View this thread: http://www.excelforum.com/showthread...hreadid=569799 | |
Sumproduct
It would be something like
=SUMPRODUCT((array1={"A","B"})*(array3)) but do read the page Nick suggested, it should help explain it all. -- HTH Bob Phillips (replace somewhere in email address with gmail if mailing direct) "sanders" wrote in message ... Hi, I currently have a sumproduct formula layed out in the standard configuration: =SUMPRODUCT((array1=condition1)*(array2=condition2 )*(array3)) Is it possible to change the (array1=condition1) part so that it looks for more than one condition in that array, so that it is looking for condition1 OR condition1a? Thanks -- sanders ------------------------------------------------------------------------ sanders's Profile: http://www.excelforum.com/member.php...o&userid=36745 View this thread: http://www.excelforum.com/showthread...hreadid=569799 |
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