Polinomial - What's Wrong
Hi All,
Please refer to the earlier Post. But here it is again. Below is the data for a graph. x is the x axis, and Data the applicable Data for the graph. X Data formula 1.0000 0.0688 -0.0012 2.0000 0.1277 0.0370 3.0000 0.1800 0.0756 4.0000 0.2272 0.1146 5.0000 0.4471 0.1541 6.0000 0.6924 0.1940 7.0000 1.0000 0.2343 8.0000 1.3455 0.2751 9.0000 1.5503 0.3163 10.0000 1.7955 0.3580 11.0000 2.0820 0.4001 A Polinomial trendline is then applied to the graph line. A polinmial graph has r2=.9894, so pretty good fit. The trend formula is y = 0.0148x2 + 0.0375x - 0.0398 This is entered into the Formula column as ((0.0148*x)^2)+(0.0375*x)-0.0398 If this data is taken and put into the same graph as a new line it bears no remblance to the original polinomial trend line. Which part of how thick I am, is failing to grasp the simple answer to this? Please be polite in replies, (though I may be too thick to understand them) :) Thanks |
Please see the response(s) to your other post.
-- Regards, Tushar Mehta www.tushar-mehta.com Excel, PowerPoint, and VBA add-ins, tutorials Custom MS Office productivity solutions In article , says... Hi All, Please refer to the earlier Post. But here it is again. Below is the data for a graph. x is the x axis, and Data the applicable Data {snip} |
Hi Hugh,
I can't work out what it is you have done wrong. If your first X value is in A1 then the formula should be, A1: =((0.0148*(A1*A1))+(0.0375*A1)-0.0398) which returns 0.0125 This formula the dragged down produces a plot that is very close to the trend line. Cheers Andy Hugh wrote: Hi All, Please refer to the earlier Post. But here it is again. Below is the data for a graph. x is the x axis, and Data the applicable Data for the graph. X Data formula 1.0000 0.0688 -0.0012 2.0000 0.1277 0.0370 3.0000 0.1800 0.0756 4.0000 0.2272 0.1146 5.0000 0.4471 0.1541 6.0000 0.6924 0.1940 7.0000 1.0000 0.2343 8.0000 1.3455 0.2751 9.0000 1.5503 0.3163 10.0000 1.7955 0.3580 11.0000 2.0820 0.4001 A Polinomial trendline is then applied to the graph line. A polinmial graph has r2=.9894, so pretty good fit. The trend formula is y = 0.0148x2 + 0.0375x - 0.0398 This is entered into the Formula column as ((0.0148*x)^2)+(0.0375*x)-0.0398 If this data is taken and put into the same graph as a new line it bears no remblance to the original polinomial trend line. Which part of how thick I am, is failing to grasp the simple answer to this? Please be polite in replies, (though I may be too thick to understand them) :) Thanks -- Andy Pope, Microsoft MVP - Excel http://www.andypope.info |
Many Thanks,Hugh
"Tushar Mehta" wrote in message ... Please see the response(s) to your other post. -- Regards, Tushar Mehta www.tushar-mehta.com Excel, PowerPoint, and VBA add-ins, tutorials Custom MS Office productivity solutions In article , says... Hi All, Please refer to the earlier Post. But here it is again. Below is the data for a graph. x is the x axis, and Data the applicable Data {snip} |
Many thanks, I appreciate the help.
Hugh "Andy Pope" wrote in message ... Hi Hugh, I can't work out what it is you have done wrong. If your first X value is in A1 then the formula should be, A1: =((0.0148*(A1*A1))+(0.0375*A1)-0.0398) which returns 0.0125 This formula the dragged down produces a plot that is very close to the trend line. Cheers Andy Hugh wrote: Hi All, Please refer to the earlier Post. But here it is again. Below is the data for a graph. x is the x axis, and Data the applicable Data for the graph. X Data formula 1.0000 0.0688 -0.0012 2.0000 0.1277 0.0370 3.0000 0.1800 0.0756 4.0000 0.2272 0.1146 5.0000 0.4471 0.1541 6.0000 0.6924 0.1940 7.0000 1.0000 0.2343 8.0000 1.3455 0.2751 9.0000 1.5503 0.3163 10.0000 1.7955 0.3580 11.0000 2.0820 0.4001 A Polinomial trendline is then applied to the graph line. A polinmial graph has r2=.9894, so pretty good fit. The trend formula is y = 0.0148x2 + 0.0375x - 0.0398 This is entered into the Formula column as ((0.0148*x)^2)+(0.0375*x)-0.0398 If this data is taken and put into the same graph as a new line it bears no remblance to the original polinomial trend line. Which part of how thick I am, is failing to grasp the simple answer to this? Please be polite in replies, (though I may be too thick to understand them) :) Thanks -- Andy Pope, Microsoft MVP - Excel http://www.andypope.info |
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