tried this, at least got a response but it was Cannot
open specified file!

Wayne
-----Original Message-----
Hi


"Dave Peterson" wrote in
message
...
I think you dropped some double quotes:

=hyperlink("\\fil-....!K12","myLink")


More exactly, OE somehow did it - at start quotes were
there. I'm trying
again - the right formula will be:

=HYPERLINK("\\FIL-NW02-06\MPTTechTeamLeaders\8 Tech Team
Scorecard\Reddy
Team
Scorecards\2005_Define_Scorecard_Hixon.xls#'Scorec ard -
Tech
Group'!K12","MyLink")


Arvi Laanemets




Arvi Laanemets wrote:

Hi

This must work:

=HYPERLINK("\\FIL-NW02-06
\MPTTechTeamLeaders\8_Tech_Team_Scorecard\Reddy
Team
Scorecards\2005_Define_Scorecard_Hixson.xls#'Score card -
Tech
Group'!K12,"MyLink")

Arvi Laanemets

wrote in
message
...
I tried this, here is the contents of the cell:

=HYPERLINK('\\FIL-NW02-06
\MPTTechTeamLeaders\8_Tech_Team_Scorecard\Reddy
Team
Scorecards\[2005_Define_Scorecard_Hixson.xls]
Scorecard -
Tech Group'!K12)

and I get the little hyperlink hand icon but when
I click
nothing happens.

Wayne

-----Original Message-----
Check out the HYPERLINK function.
Example:
=HYPERLINK("[C:\Temp\MyFile.xls]Data!$C$2","Test")
will show the word 'Test' in the cell. When
selected,
the hyperlink will
take you to the 'MYFILE' workbook, the 'Data'
worksheet,
cell C2.
HTH,
Gary Brown

"Wayne"
wrote in
message
...
I have a paste link cell in a spreadsheet,
referring to
a
source cell in another spreadsheet and cell. Is
there a
way in VBA to open that source spreadsheet
and "jump"
to
the source cell?

Wayne


.


--

Dave Peterson


.