To get around the "nested 7 levels deep" IF statement limitation you can use
binary switching logic. For example, assume the numbers 1 through 10 can be
placed in cell A1. You need to write an IF statement that includes all 10
numbers. You can write the statement similar to this ie. if A1=1,50 etc.:

=(A1=1)*51+(A1=2)*52+(A1=3)*53+(A1=4)*54+(A1=5)*55 +(A1=6)*56+(A1=7)*57+(A1=8)*58+(A1=9)*59+(A1=10)*6 0

If you need the statement to evaluate multiple conditions as True, use plus
(+) signs instead of multiplication (*) signs. Also, this technique works
for numbers only. The formula can not return text entries.

----
Regards,
John Mansfield
http:www.pdbook.com


"SUB-ZERO" wrote:

Hi

Is there any way to change the number of functions allowed in each cell?
I have a spreadsheet and I need it to handle more functions than 7.
10-15 functions wolud really work well for me.
Here is one example of what im working with, I need to have a few more
allowed functions for the formula to work correctly.
=IF(D11=0,D12,IF(D10=0,SUM(D11:D12),IF(D9=0,SUM(D1 0:D12),IF(D8=0,SUM(D9:D12),IF(D7=0,SUM(D8:D12),IF( D6=0,SUM(D7:D12),IF(D5=0,SUM(D6:D12),SUM(D5:D12))) )))))

Any help would be greatly appreciated

Thanks ...


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