Awesome, thank you very much!
This works exactly how I need it to. Thank you very much
for your time today Frank. Sorry I wasn't very clear in
the initial post.
Thanks again!
-----Original Message-----
Hi
I would guess the formula returns zero and this is your
issue. Try for
example:
=SUMIF(A1:A31,"<0")/COUNTIF(A1:A31,"<0")
--
Regards
Frank Kabel
Frankfurt, Germany
"Randy Lefferts"
schrieb im
Newsbeitrag news:ad2401c4d70f$44585f20
...
In A1:A31, as well as other columns, there is a formula
that will produce a number based on inputs in other
cells. So currently there is a formula in the cell,
although there is not a value showing, just blank
cells.
The formula hasn't produced anything yet since there
are
not any entries in the input cells.
This is a timesheet that takes time in and time out (2
time in, 2 time out to cover clocking out at lunch)
converts it to hours worked and the formula in a1
calculates the hours worked for the day. So if they
don't work on a particular day, while the formula is
still in a1, it won't calculate hours worked and as
such,
should remain blank, which it does.
So what is happening is it is treating it as a cell
with
a value when calculating the hours worked, even though
there is not a value there.
-----Original Message-----
Hi
aVERAGGE ignores empty cell. What exact values do you
have in the other
cells (zeros?)
--
Regards
Frank Kabel
Frankfurt, Germany
"Randy Lefferts"
schrieb im
Newsbeitrag news:a3b801c4d707$fd3fdb60
...
Hi Frank,
Yes, sorry about that, that was a typo on my part.
Your formula was correct initially, just that when I
used
that, it did not generate the average I was looking
for.
It appears to be including the blank cells as a
divisor,
as well, so that the average is quite lower than it
should be. So I reposted thinking that I left out
pertinent information that instead of actual
numbers in
the cells, there were formulas calculating the
numbers
I
need averaged.
As an example, the numbers 7.5, 6.5, 4.5, when
averaged
should equal 6.17, however it is equaling 1.32.
So, I need to find a way to average just the values
that
are appearing within a set of 31 cells. If out of
the
31
cells, only 6 contain data, then the numbers
contained
within the 6 cells should be averaged, not the
average
of
31 cells with just those 6 values. If, in the 31
rows,
there are 25 cells that contain data (generated by
the
formula), then I would need the average of just
those
25
cells.
Sorry about not being clearer :(
Any chance there is a way to do the above?
-----Original Message-----
Hi
sorry,
was just a typoe. Try.
=AVERAGE(A1:A31)
--
Regards
Frank Kabel
Frankfurt, Germany
"Randy Lefferts"
schrieb im
Newsbeitrag news:abf301c4d6f3$f2975ee0
...
Thank you for the replies :)
Unfortunately I may not have included enough
information
since the formula "=AVERAGE(A1:31)" is generating
an "incorrect" number. I apologize for not
including
pertinent information.
The column that contains the data that is to be
averaged,
contains formulas to get the number(s) that I
want
to
average.
So instead of A1 containing just a number, it
contains
the formula =(BN13-BM13)+(BP13-BO13). This is
true
for
each cell in the column that I want to average.
Thoughts?
-----Original Message-----
Hi
=AVERAGE(A1:A31)
blank cells and strings are ignored
--
Regards
Frank Kabel
Frankfurt, Germany
"Randy Lefferts"
schrieb im
Newsbeitrag news:16d501c4d6e7$46e0bee0
...
I have a column with 31 rows. In select
cells,
there
is
a number. I want to average the numbers. How
do I
average only the cells that contain data,
ignoring
blank
cells? Thanks!
Excel 2003
.
.
.
.
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