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#1




counting identical items in a column and returning the occurrences
I use excell 2000. I have one column with 700 rows. In each cell is one
number, either a 0, 1, 2, 3, 4, or 5. In the second column I have five rows, each with one number in increasing order: 0, 1, 2, 3, 4, 5. Next to the numbers 05 (in column three) I want the total number of occurances for each number in column one. So out of the 700 rows, if the number 2 occurred 230 times, I want the number 230 to show in column 3 to correspond to the number 2 in column two. Any ideas? 
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#2




counting identical items in a column and returning the occurrences
Try this:
In C1 (to count the zeros) =COUNTIF($A$1:$A$701,"0") In C2 (to count the 1s): =COUNTIF($A$1:$A$701,"1") etc. Hope that helps. If it does, rate it has helpful at the bottom of the post. "ExcelWizardImNot" wrote: > I use excell 2000. I have one column with 700 rows. In each cell is one > number, either a 0, 1, 2, 3, 4, or 5. In the second column I have five rows, > each with one number in increasing order: 0, 1, 2, 3, 4, 5. Next to the > numbers 05 (in column three) I want the total number of occurances for each > number in column one. So out of the 700 rows, if the number 2 occurred 230 > times, I want the number 230 to show in column 3 to correspond to the number > 2 in column two. Any ideas? 
#3




counting identical items in a column and returning the occurre
That did it. Thanks much.
"Huber57" wrote: > Try this: > > In C1 (to count the zeros) > > =COUNTIF($A$1:$A$701,"0") > > In C2 (to count the 1s): > > =COUNTIF($A$1:$A$701,"1") > > etc. > > Hope that helps. If it does, rate it has helpful at the bottom of the post. > > "ExcelWizardImNot" wrote: > > > I use excell 2000. I have one column with 700 rows. In each cell is one > > number, either a 0, 1, 2, 3, 4, or 5. In the second column I have five rows, > > each with one number in increasing order: 0, 1, 2, 3, 4, 5. Next to the > > numbers 05 (in column three) I want the total number of occurances for each > > number in column one. So out of the 700 rows, if the number 2 occurred 230 > > times, I want the number 230 to show in column 3 to correspond to the number > > 2 in column two. Any ideas? 
#4




counting identical items in a column and returning the occurre
In order to avoid the correction of each and every formula  in your private
case  I would suggest, in cell C1 to type the following formula and copy down till C6: =COUNTIF($A$1:$A$700,Row()1) Micky "ExcelWizardImNot" wrote: > That did it. Thanks much. > > > "Huber57" wrote: > > > Try this: > > > > In C1 (to count the zeros) > > > > =COUNTIF($A$1:$A$701,"0") > > > > In C2 (to count the 1s): > > > > =COUNTIF($A$1:$A$701,"1") > > > > etc. > > > > Hope that helps. If it does, rate it has helpful at the bottom of the post. > > > > "ExcelWizardImNot" wrote: > > > > > I use excell 2000. I have one column with 700 rows. In each cell is one > > > number, either a 0, 1, 2, 3, 4, or 5. In the second column I have five rows, > > > each with one number in increasing order: 0, 1, 2, 3, 4, 5. Next to the > > > numbers 05 (in column three) I want the total number of occurances for each > > > number in column one. So out of the 700 rows, if the number 2 occurred 230 > > > times, I want the number 230 to show in column 3 to correspond to the number > > > 2 in column two. Any ideas? 
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