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Nev Nev is offline
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Default copy first line in a cell

I have an address
Any place
Anywhere
UK
in the above format. I want to be be to copy the first line into another
cell. I have found first word but some places have 2 names or even 3.

Can anyone help? I need to do this with a formula and not vba.

thanks

Nev
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Thumbs up Answer: copy first line in a cell

Extracting the First Line of an Address in Excel

Assuming your address is in cell A1, follow these steps:
[list=1][*]Use the FIND function to find the position of the first line break character. The formula would be:

Code:
=FIND(CHAR(10),A1)
This will return the position of the first line break character in cell A1.
[*]Use the LEFT function to extract the first line of the address. The formula would be:

Code:
=LEFT(A1,FIND(CHAR(10),A1)-1)
This will return the first line of the address, up to but not including the line break character.

Note that the CHAR(10) function is used to represent the line break character in the formula.
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Default copy first line in a cell


One way
=LEFT(D19,FIND(" ",D19,FIND(" ",D19)+1)-FIND(" ",D19))

--
Don Guillett
Microsoft MVP Excel
SalesAid Software

"Nev" wrote in message
...
I have an address
Any place
Anywhere
UK
in the above format. I want to be be to copy the first line into another
cell. I have found first word but some places have 2 names or even 3.

Can anyone help? I need to do this with a formula and not vba.

thanks

Nev


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Default copy first line in a cell

On Sat, 23 May 2009 05:26:01 -0700, Nev wrote:

I have an address
Any place
Anywhere
UK
in the above format. I want to be be to copy the first line into another
cell. I have found first word but some places have 2 names or even 3.

Can anyone help? I need to do this with a formula and not vba.

thanks

Nev



=LEFT(A1,FIND(CHAR(10),A1)-1)

CHAR(10) is the LineFeed character; which should be at the end of the first
line.
--ron
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Nev Nev is offline
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Default copy first line in a cell

That's great Thanks. If I wanted to get the 1st two line or second line
only, how would that work?

Thanks

Nev

"Ron Rosenfeld" wrote:

On Sat, 23 May 2009 05:26:01 -0700, Nev wrote:

I have an address
Any place
Anywhere
UK
in the above format. I want to be be to copy the first line into another
cell. I have found first word but some places have 2 names or even 3.

Can anyone help? I need to do this with a formula and not vba.

thanks

Nev



=LEFT(A1,FIND(CHAR(10),A1)-1)

CHAR(10) is the LineFeed character; which should be at the end of the first
line.
--ron



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Default copy first line in a cell

On Sun, 24 May 2009 01:57:04 -0700, Nev wrote:

That's great Thanks. If I wanted to get the 1st two line or second line
only, how would that work?

Thanks

Nev


Glad to help.

For the 1st two lines, you need to look for the second <lf character. The
SUBSTITUTE worksheet function allows you to specify the instance of a
character.

So =SUBSTITUTE(A1,CHAR(10),CHAR(1),2) would substitute a CHAR(1) for the <lf.
Then you just look for that:

=LEFT(A1,FIND(CHAR(1),SUBSTITUTE(A1,CHAR(10),CHAR( 1),2))-1)

To get just the second line, you use the MID function and go from the first
<lf to your substituted CHAR(1).

So something like:

=MID(A1,FIND(CHAR(10),A1)+1,FIND(CHAR(1),
SUBSTITUTE(A1,CHAR(10),CHAR(1),2))-FIND(CHAR(10),A1)-1)

I find it simpler to use either Longre's free morefunc.xll add-in and the
regular expression formula:

=REGEX.MID(A1,".+",<LineNumber)

for work like this.

The .xll will not work on strings longer than 255 characters, in which case I
would use a "home grown" VBA routine that does pretty much the same thing.

--ron
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Nev Nev is offline
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Default copy first line in a cell

Ron

That's brilliant - i will give it a go

Thanks

Nev


"Ron Rosenfeld" wrote:

On Sun, 24 May 2009 01:57:04 -0700, Nev wrote:

That's great Thanks. If I wanted to get the 1st two line or second line
only, how would that work?

Thanks

Nev


Glad to help.

For the 1st two lines, you need to look for the second <lf character. The
SUBSTITUTE worksheet function allows you to specify the instance of a
character.

So =SUBSTITUTE(A1,CHAR(10),CHAR(1),2) would substitute a CHAR(1) for the <lf.
Then you just look for that:

=LEFT(A1,FIND(CHAR(1),SUBSTITUTE(A1,CHAR(10),CHAR( 1),2))-1)

To get just the second line, you use the MID function and go from the first
<lf to your substituted CHAR(1).

So something like:

=MID(A1,FIND(CHAR(10),A1)+1,FIND(CHAR(1),
SUBSTITUTE(A1,CHAR(10),CHAR(1),2))-FIND(CHAR(10),A1)-1)

I find it simpler to use either Longre's free morefunc.xll add-in and the
regular expression formula:

=REGEX.MID(A1,".+",<LineNumber)

for work like this.

The .xll will not work on strings longer than 255 characters, in which case I
would use a "home grown" VBA routine that does pretty much the same thing.

--ron

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